How to calculate the Delay Formula (clarify the formula)
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I would like to understand how their respective answers were reached, this is a question in my current class and everyone in the class has A-Level mathematics experience - I have asked my tutor to explain but they talk very technically and I'm at a loss. I was hoping to get a simple answer from someone in this community, this formula is important to a project I am making - I am making an algorithm that sniffs packets and converts the delay result as png. I need to understand the maths behind it.
Question w/ Answers
I would like a run through of this formula, I am particularly lost with;
- On the first question, where the "50x10^3" comes from
- And the second question, why is R "64 x 10^3"
network delay-differential-equations
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add a comment |
$begingroup$
I would like to understand how their respective answers were reached, this is a question in my current class and everyone in the class has A-Level mathematics experience - I have asked my tutor to explain but they talk very technically and I'm at a loss. I was hoping to get a simple answer from someone in this community, this formula is important to a project I am making - I am making an algorithm that sniffs packets and converts the delay result as png. I need to understand the maths behind it.
Question w/ Answers
I would like a run through of this formula, I am particularly lost with;
- On the first question, where the "50x10^3" comes from
- And the second question, why is R "64 x 10^3"
network delay-differential-equations
$endgroup$
add a comment |
$begingroup$
I would like to understand how their respective answers were reached, this is a question in my current class and everyone in the class has A-Level mathematics experience - I have asked my tutor to explain but they talk very technically and I'm at a loss. I was hoping to get a simple answer from someone in this community, this formula is important to a project I am making - I am making an algorithm that sniffs packets and converts the delay result as png. I need to understand the maths behind it.
Question w/ Answers
I would like a run through of this formula, I am particularly lost with;
- On the first question, where the "50x10^3" comes from
- And the second question, why is R "64 x 10^3"
network delay-differential-equations
$endgroup$
I would like to understand how their respective answers were reached, this is a question in my current class and everyone in the class has A-Level mathematics experience - I have asked my tutor to explain but they talk very technically and I'm at a loss. I was hoping to get a simple answer from someone in this community, this formula is important to a project I am making - I am making an algorithm that sniffs packets and converts the delay result as png. I need to understand the maths behind it.
Question w/ Answers
I would like a run through of this formula, I am particularly lost with;
- On the first question, where the "50x10^3" comes from
- And the second question, why is R "64 x 10^3"
network delay-differential-equations
network delay-differential-equations
asked Jan 3 at 16:20
KaleKale
52
52
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You confusion relates to kilobits per second (kbs). Since a kilobit is $1000=10^3$ bits, when the answer is expressed in bits, as these two answers are, you have to multiply kilobits by $10^3$ to get bits.
$endgroup$
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You confusion relates to kilobits per second (kbs). Since a kilobit is $1000=10^3$ bits, when the answer is expressed in bits, as these two answers are, you have to multiply kilobits by $10^3$ to get bits.
$endgroup$
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
add a comment |
$begingroup$
You confusion relates to kilobits per second (kbs). Since a kilobit is $1000=10^3$ bits, when the answer is expressed in bits, as these two answers are, you have to multiply kilobits by $10^3$ to get bits.
$endgroup$
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
add a comment |
$begingroup$
You confusion relates to kilobits per second (kbs). Since a kilobit is $1000=10^3$ bits, when the answer is expressed in bits, as these two answers are, you have to multiply kilobits by $10^3$ to get bits.
$endgroup$
You confusion relates to kilobits per second (kbs). Since a kilobit is $1000=10^3$ bits, when the answer is expressed in bits, as these two answers are, you have to multiply kilobits by $10^3$ to get bits.
answered Jan 3 at 17:40
saulspatzsaulspatz
14.2k21329
14.2k21329
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
add a comment |
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
Oh I see that makes much more sense now. Is it possible to go through the formula step by step - for example what I would do on a calculator to achieve this answer
$endgroup$
– Kale
Jan 3 at 18:06
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
After you calculate the kbps to bits, It then moves to variable m over s, what do I do with the converted bit value at this point
$endgroup$
– Kale
Jan 3 at 18:10
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
$begingroup$
Ohhh you multiple it by the result, okay I get it now thanks for your time and answer!
$endgroup$
– Kale
Jan 3 at 18:12
add a comment |
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