Not able to access row property in ui-grid angularJS











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I have one angularjs project in which I am using ui-grid.



I am writing the code of controller.



Problem is, I am able to access "row" property for in cellTemplate for some fields, but not for all the fields.



In the below example, I am not able to access row property for "rating-percentage" field in cell template. Actually I want to access row property , so that I can make rating percentage value is same as per row index.



Could you please help me?



  define([
'angular'
], function (angular) {

function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn,

vm.rating = 20;

//This function gets called only one time from cell template
function getRating(){
vm.rating++;
return vm.rating;
}

_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="'+getRating()+'"',
'total-count="23"',
'suffix-display="true"',
'rating-display="{{ ', ''opr.toolrunner.satrRating.successRate' | oprL10n }}"',
'count-display="{{ ', ''opr.toolrunner.satrRating.executions' | oprL10n }}">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');

_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}

_columnDefs.push(_starRatingColumn);

function gridInitialized(gridApi) {
_gridApi = gridApi;
});

})();









share|improve this question


















  • 1




    It is unclear where you are trying to access the row property? There is no function accessing row anywhere. What I'm looking for is something like row.entity.someFieldName. Keep in mind - the fields available on row.entity.someFieldName are the fields of the JSON object in your grid data. If there are fields you want to calculate and add, you need to process the data before setting it as grid data
    – ArielGro
    2 days ago















up vote
0
down vote

favorite












I have one angularjs project in which I am using ui-grid.



I am writing the code of controller.



Problem is, I am able to access "row" property for in cellTemplate for some fields, but not for all the fields.



In the below example, I am not able to access row property for "rating-percentage" field in cell template. Actually I want to access row property , so that I can make rating percentage value is same as per row index.



Could you please help me?



  define([
'angular'
], function (angular) {

function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn,

vm.rating = 20;

//This function gets called only one time from cell template
function getRating(){
vm.rating++;
return vm.rating;
}

_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="'+getRating()+'"',
'total-count="23"',
'suffix-display="true"',
'rating-display="{{ ', ''opr.toolrunner.satrRating.successRate' | oprL10n }}"',
'count-display="{{ ', ''opr.toolrunner.satrRating.executions' | oprL10n }}">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');

_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}

_columnDefs.push(_starRatingColumn);

function gridInitialized(gridApi) {
_gridApi = gridApi;
});

})();









share|improve this question


















  • 1




    It is unclear where you are trying to access the row property? There is no function accessing row anywhere. What I'm looking for is something like row.entity.someFieldName. Keep in mind - the fields available on row.entity.someFieldName are the fields of the JSON object in your grid data. If there are fields you want to calculate and add, you need to process the data before setting it as grid data
    – ArielGro
    2 days ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have one angularjs project in which I am using ui-grid.



I am writing the code of controller.



Problem is, I am able to access "row" property for in cellTemplate for some fields, but not for all the fields.



In the below example, I am not able to access row property for "rating-percentage" field in cell template. Actually I want to access row property , so that I can make rating percentage value is same as per row index.



Could you please help me?



  define([
'angular'
], function (angular) {

function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn,

vm.rating = 20;

//This function gets called only one time from cell template
function getRating(){
vm.rating++;
return vm.rating;
}

_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="'+getRating()+'"',
'total-count="23"',
'suffix-display="true"',
'rating-display="{{ ', ''opr.toolrunner.satrRating.successRate' | oprL10n }}"',
'count-display="{{ ', ''opr.toolrunner.satrRating.executions' | oprL10n }}">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');

_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}

_columnDefs.push(_starRatingColumn);

function gridInitialized(gridApi) {
_gridApi = gridApi;
});

})();









share|improve this question













I have one angularjs project in which I am using ui-grid.



I am writing the code of controller.



Problem is, I am able to access "row" property for in cellTemplate for some fields, but not for all the fields.



In the below example, I am not able to access row property for "rating-percentage" field in cell template. Actually I want to access row property , so that I can make rating percentage value is same as per row index.



Could you please help me?



  define([
'angular'
], function (angular) {

function SelectToolController($scope, $timeout, $filter) {
var vm = this,
_gridApi,
_cellTemplate,
_columnDefs,
_starRatingTemplate,
_starRatingColumn,

vm.rating = 20;

//This function gets called only one time from cell template
function getRating(){
vm.rating++;
return vm.rating;
}

_starRatingTemplate =[
'<div class="ui-grid-cell-contents ">',
'<div class="opr-star-rating" >',
'<opr-star-rating rating-percentage="'+getRating()+'"',
'total-count="23"',
'suffix-display="true"',
'rating-display="{{ ', ''opr.toolrunner.satrRating.successRate' | oprL10n }}"',
'count-display="{{ ', ''opr.toolrunner.satrRating.executions' | oprL10n }}">',
'</opr-star-rating>',
'</div>',
'</div>'
].join('');

_starRatingColumn = {
name: 'starRating',
cellTemplate: _starRatingTemplate,
displayName: 'Rating',
enableFiltering: false,
enableSorting: true,
cellClass: 'star-column',
enableHiding: false,
enableRowSelection: true,
}

_columnDefs.push(_starRatingColumn);

function gridInitialized(gridApi) {
_gridApi = gridApi;
});

})();






angularjs angular-ui-grid ui-grid






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asked Nov 19 at 11:32









Anubha Gupta

469




469








  • 1




    It is unclear where you are trying to access the row property? There is no function accessing row anywhere. What I'm looking for is something like row.entity.someFieldName. Keep in mind - the fields available on row.entity.someFieldName are the fields of the JSON object in your grid data. If there are fields you want to calculate and add, you need to process the data before setting it as grid data
    – ArielGro
    2 days ago














  • 1




    It is unclear where you are trying to access the row property? There is no function accessing row anywhere. What I'm looking for is something like row.entity.someFieldName. Keep in mind - the fields available on row.entity.someFieldName are the fields of the JSON object in your grid data. If there are fields you want to calculate and add, you need to process the data before setting it as grid data
    – ArielGro
    2 days ago








1




1




It is unclear where you are trying to access the row property? There is no function accessing row anywhere. What I'm looking for is something like row.entity.someFieldName. Keep in mind - the fields available on row.entity.someFieldName are the fields of the JSON object in your grid data. If there are fields you want to calculate and add, you need to process the data before setting it as grid data
– ArielGro
2 days ago




It is unclear where you are trying to access the row property? There is no function accessing row anywhere. What I'm looking for is something like row.entity.someFieldName. Keep in mind - the fields available on row.entity.someFieldName are the fields of the JSON object in your grid data. If there are fields you want to calculate and add, you need to process the data before setting it as grid data
– ArielGro
2 days ago

















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