Mixing
How to simplify this algebraic expression? What is the proper name for this problem?
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
asked Jul 2 '16 at 14:24
tina
61
|
show 5 more comments
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
asked Jul 2 '16 at 14:24
tina
61
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
|
show 5 more comments
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
asked Jul 2 '16 at 14:24
tina
61
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
arithmetic
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
asked Jul 2 '16 at 14:24
tina
61
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
asked Jul 2 '16 at 14:24
tina
61
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
edited Nov 20 '18 at 21:01
Robert Howard
1,9161822
1,9161822
asked Jul 2 '16 at 14:24
tina
61
asked Jul 2 '16 at 14:24
tina
61
asked Jul 2 '16 at 14:24
tina
61
61
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
|
show 5 more comments
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
1
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
|
show 5 more comments
1 Answer
1
active
oldest
votes
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1846842%2fhow-to-simplify-this-algebraic-expression-what-is-the-proper-name-for-this-prob%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
add a comment |
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
add a comment |
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
answered Nov 20 '18 at 3:54
community wiki
Robert Howard
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1846842%2fhow-to-simplify-this-algebraic-expression-what-is-the-proper-name-for-this-prob%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56