Mixing
I have api call more than one time, but want to trigger ajax only once in Angular 6
I have a dashboard with dynamic widgets adding up, If a user adds two widgets which have same api call, it obviously hit two ajax call. How can I make sure, if the API is called once, the second call get the result of first one
angular rxjs
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
add a comment |
I have a dashboard with dynamic widgets adding up, If a user adds two widgets which have same api call, it obviously hit two ajax call. How can I make sure, if the API is called once, the second call get the result of first one
angular rxjs
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
You can usePromisesand sequentially execute them. Take a look at this SO question: stackoverflow.com/a/45649612/4091337
– Teun van der Wijst
Nov 20 '18 at 11:58
You can check Observable. shareReplay operator. this might help.
– Suresh Kumar Ariya
Nov 20 '18 at 12:35
add a comment |
I have a dashboard with dynamic widgets adding up, If a user adds two widgets which have same api call, it obviously hit two ajax call. How can I make sure, if the API is called once, the second call get the result of first one
angular rxjs
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
I have a dashboard with dynamic widgets adding up, If a user adds two widgets which have same api call, it obviously hit two ajax call. How can I make sure, if the API is called once, the second call get the result of first one
angular rxjs
angular rxjs
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
asked Nov 20 '18 at 11:53
imranashakeimranashake
134
134
You can usePromisesand sequentially execute them. Take a look at this SO question: stackoverflow.com/a/45649612/4091337
– Teun van der Wijst
Nov 20 '18 at 11:58
You can check Observable. shareReplay operator. this might help.
– Suresh Kumar Ariya
Nov 20 '18 at 12:35
add a comment |
You can usePromisesand sequentially execute them. Take a look at this SO question: stackoverflow.com/a/45649612/4091337
– Teun van der Wijst
Nov 20 '18 at 11:58
You can check Observable. shareReplay operator. this might help.
– Suresh Kumar Ariya
Nov 20 '18 at 12:35
You can use
Promises and sequentially execute them. Take a look at this SO question: stackoverflow.com/a/45649612/4091337– Teun van der Wijst
Nov 20 '18 at 11:58
You can use
Promises and sequentially execute them. Take a look at this SO question: stackoverflow.com/a/45649612/4091337– Teun van der Wijst
Nov 20 '18 at 11:58
You can check Observable. shareReplay operator. this might help.
– Suresh Kumar Ariya
Nov 20 '18 at 12:35
You can check Observable. shareReplay operator. this might help.
– Suresh Kumar Ariya
Nov 20 '18 at 12:35
add a comment |
1 Answer
1
active
oldest
votes
You can use the shareReplay operator. It is caching the results and emits them to new subscribers without creating the stream again.
import { ajax } from 'rxjs/ajax';
import { tap, map, shareReplay } from 'rxjs/operators';
const endpoint = 'https://api.github.com/users?per_page=1'
const obs$ = ajax.getJSON(endpoint).pipe(
tap(() => console.log('Making BE call')),
shareReplay(1)
);
obs$.subscribe(x => console.log('[1]', x));
obs$.subscribe(x => console.log('[2]', x));
// Output:
// Making BE call
// [1] object
// [2] object
You can have a look at this small demo: https://stackblitz.com/edit/rxjs-eyk9y5
answered Nov 20 '18 at 21:34
BeneBene
35529
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the shareReplay operator. It is caching the results and emits them to new subscribers without creating the stream again.
import { ajax } from 'rxjs/ajax';
import { tap, map, shareReplay } from 'rxjs/operators';
const endpoint = 'https://api.github.com/users?per_page=1'
const obs$ = ajax.getJSON(endpoint).pipe(
tap(() => console.log('Making BE call')),
shareReplay(1)
);
obs$.subscribe(x => console.log('[1]', x));
obs$.subscribe(x => console.log('[2]', x));
// Output:
// Making BE call
// [1] object
// [2] object
You can have a look at this small demo: https://stackblitz.com/edit/rxjs-eyk9y5
answered Nov 20 '18 at 21:34
BeneBene
35529
add a comment |
You can use the shareReplay operator. It is caching the results and emits them to new subscribers without creating the stream again.
import { ajax } from 'rxjs/ajax';
import { tap, map, shareReplay } from 'rxjs/operators';
const endpoint = 'https://api.github.com/users?per_page=1'
const obs$ = ajax.getJSON(endpoint).pipe(
tap(() => console.log('Making BE call')),
shareReplay(1)
);
obs$.subscribe(x => console.log('[1]', x));
obs$.subscribe(x => console.log('[2]', x));
// Output:
// Making BE call
// [1] object
// [2] object
You can have a look at this small demo: https://stackblitz.com/edit/rxjs-eyk9y5
answered Nov 20 '18 at 21:34
BeneBene
35529
add a comment |
You can use the shareReplay operator. It is caching the results and emits them to new subscribers without creating the stream again.
import { ajax } from 'rxjs/ajax';
import { tap, map, shareReplay } from 'rxjs/operators';
const endpoint = 'https://api.github.com/users?per_page=1'
const obs$ = ajax.getJSON(endpoint).pipe(
tap(() => console.log('Making BE call')),
shareReplay(1)
);
obs$.subscribe(x => console.log('[1]', x));
obs$.subscribe(x => console.log('[2]', x));
// Output:
// Making BE call
// [1] object
// [2] object
You can have a look at this small demo: https://stackblitz.com/edit/rxjs-eyk9y5
answered Nov 20 '18 at 21:34
BeneBene
35529
You can use the shareReplay operator. It is caching the results and emits them to new subscribers without creating the stream again.
import { ajax } from 'rxjs/ajax';
import { tap, map, shareReplay } from 'rxjs/operators';
const endpoint = 'https://api.github.com/users?per_page=1'
const obs$ = ajax.getJSON(endpoint).pipe(
tap(() => console.log('Making BE call')),
shareReplay(1)
);
obs$.subscribe(x => console.log('[1]', x));
obs$.subscribe(x => console.log('[2]', x));
// Output:
// Making BE call
// [1] object
// [2] object
You can have a look at this small demo: https://stackblitz.com/edit/rxjs-eyk9y5
answered Nov 20 '18 at 21:34
BeneBene
35529
answered Nov 20 '18 at 21:34
BeneBene
35529
answered Nov 20 '18 at 21:34
BeneBene
35529
answered Nov 20 '18 at 21:34
BeneBene
35529
35529
add a comment |
add a comment |
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You can use
Promisesand sequentially execute them. Take a look at this SO question: stackoverflow.com/a/45649612/4091337– Teun van der Wijst
Nov 20 '18 at 11:58
You can check Observable. shareReplay operator. this might help.
– Suresh Kumar Ariya
Nov 20 '18 at 12:35