Mixing
ISNUMER excel funtion in PYTHON
I have the following dataset
sku ids link
1 55 1
2 56 3
3 57 ab
5 58 1
9 59 bc
10 60 1
I am trying to define the follow function to create a new column
def fmq(row):
if row['link'] == 1:
value = 10
else:
row['link']
return value
I am getting the following error
TypeError: ("'>' not supported between instances of 'str' and 'float'",
'occurred at index 0')
df['sub_link'] = df.apply(fmq, axis=1)
Final Output:
sku ids link sub_link
1 55 1 10
2 56 3 3
3 57 ab ab
5 58 1 10
9 59 bc bc
10 60 1 10
I know that in excel we can use isnumber([link]) function,
how can i replicate this function in python?
python python-3.x pandas python-2.7 numpy
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
add a comment |
I have the following dataset
sku ids link
1 55 1
2 56 3
3 57 ab
5 58 1
9 59 bc
10 60 1
I am trying to define the follow function to create a new column
def fmq(row):
if row['link'] == 1:
value = 10
else:
row['link']
return value
I am getting the following error
TypeError: ("'>' not supported between instances of 'str' and 'float'",
'occurred at index 0')
df['sub_link'] = df.apply(fmq, axis=1)
Final Output:
sku ids link sub_link
1 55 1 10
2 56 3 3
3 57 ab ab
5 58 1 10
9 59 bc bc
10 60 1 10
I know that in excel we can use isnumber([link]) function,
how can i replicate this function in python?
python python-3.x pandas python-2.7 numpy
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
add a comment |
I have the following dataset
sku ids link
1 55 1
2 56 3
3 57 ab
5 58 1
9 59 bc
10 60 1
I am trying to define the follow function to create a new column
def fmq(row):
if row['link'] == 1:
value = 10
else:
row['link']
return value
I am getting the following error
TypeError: ("'>' not supported between instances of 'str' and 'float'",
'occurred at index 0')
df['sub_link'] = df.apply(fmq, axis=1)
Final Output:
sku ids link sub_link
1 55 1 10
2 56 3 3
3 57 ab ab
5 58 1 10
9 59 bc bc
10 60 1 10
I know that in excel we can use isnumber([link]) function,
how can i replicate this function in python?
python python-3.x pandas python-2.7 numpy
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
I have the following dataset
sku ids link
1 55 1
2 56 3
3 57 ab
5 58 1
9 59 bc
10 60 1
I am trying to define the follow function to create a new column
def fmq(row):
if row['link'] == 1:
value = 10
else:
row['link']
return value
I am getting the following error
TypeError: ("'>' not supported between instances of 'str' and 'float'",
'occurred at index 0')
df['sub_link'] = df.apply(fmq, axis=1)
Final Output:
sku ids link sub_link
1 55 1 10
2 56 3 3
3 57 ab ab
5 58 1 10
9 59 bc bc
10 60 1 10
I know that in excel we can use isnumber([link]) function,
how can i replicate this function in python?
python python-3.x pandas python-2.7 numpy
python python-3.x pandas python-2.7 numpy
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
asked Nov 20 '18 at 20:10
Sai SumanthSai Sumanth
313
313
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
pd.to_numeric + mask
Use Pandas methods. In this case, you need to convert to numeric first.
link_num = pd.to_numeric(df['link'], errors='coerce')
df['sub_link'] = df['link'].mask(link_num == 1, 10)
Row-wise solutions such as apply involve Python-level loops: they are inefficient and not recommended.
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
add a comment |
If I understand the problem correctly, you essentially want to test if something is an integer, correct? You can do
1) Casting
try:
to_test = int(value)
except Exception as e:
pass # In this case it could not be casted to an int
2) type checking
if isinstance(value, int):
# do thing
else:
# do other thing
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
pd.to_numeric + mask
Use Pandas methods. In this case, you need to convert to numeric first.
link_num = pd.to_numeric(df['link'], errors='coerce')
df['sub_link'] = df['link'].mask(link_num == 1, 10)
Row-wise solutions such as apply involve Python-level loops: they are inefficient and not recommended.
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
add a comment |
pd.to_numeric + mask
Use Pandas methods. In this case, you need to convert to numeric first.
link_num = pd.to_numeric(df['link'], errors='coerce')
df['sub_link'] = df['link'].mask(link_num == 1, 10)
Row-wise solutions such as apply involve Python-level loops: they are inefficient and not recommended.
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
add a comment |
pd.to_numeric + mask
Use Pandas methods. In this case, you need to convert to numeric first.
link_num = pd.to_numeric(df['link'], errors='coerce')
df['sub_link'] = df['link'].mask(link_num == 1, 10)
Row-wise solutions such as apply involve Python-level loops: they are inefficient and not recommended.
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
pd.to_numeric + mask
Use Pandas methods. In this case, you need to convert to numeric first.
link_num = pd.to_numeric(df['link'], errors='coerce')
df['sub_link'] = df['link'].mask(link_num == 1, 10)
Row-wise solutions such as apply involve Python-level loops: they are inefficient and not recommended.
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
edited Nov 20 '18 at 20:24
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
answered Nov 20 '18 at 20:17
jppjpp
98.5k2159110
98.5k2159110
add a comment |
add a comment |
If I understand the problem correctly, you essentially want to test if something is an integer, correct? You can do
1) Casting
try:
to_test = int(value)
except Exception as e:
pass # In this case it could not be casted to an int
2) type checking
if isinstance(value, int):
# do thing
else:
# do other thing
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
add a comment |
If I understand the problem correctly, you essentially want to test if something is an integer, correct? You can do
1) Casting
try:
to_test = int(value)
except Exception as e:
pass # In this case it could not be casted to an int
2) type checking
if isinstance(value, int):
# do thing
else:
# do other thing
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
add a comment |
If I understand the problem correctly, you essentially want to test if something is an integer, correct? You can do
1) Casting
try:
to_test = int(value)
except Exception as e:
pass # In this case it could not be casted to an int
2) type checking
if isinstance(value, int):
# do thing
else:
# do other thing
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
If I understand the problem correctly, you essentially want to test if something is an integer, correct? You can do
1) Casting
try:
to_test = int(value)
except Exception as e:
pass # In this case it could not be casted to an int
2) type checking
if isinstance(value, int):
# do thing
else:
# do other thing
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
answered Nov 20 '18 at 20:14
Ian QuahIan Quah
693715
693715
add a comment |
add a comment |
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