Mixing
Laravel Blade passing data from layout to “child”?
0
You might think, just use an include, but for reuseability reasons I would like to keep the layout a layout without strong ties to the child.
The tabs layout
<nav>
<div class="nav nav-tabs" id="nav-tab" role="tablist">
@foreach ($tabs as $tab)
<a class="nav-item nav-link
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}-tab" data-toggle="tab" href="#nav-{{$tab['title']}}" role="tab" aria-controls="nav-{{$tab['title']}}" aria-selected="true">{{$tab['title']}}</a>
@endforeach
</div>
</nav>
<div class="tab-content" id="nav-tabContent">
@foreach ($tabs as $tab)
<div class="tab-pane fade show
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}" role="tabpanel" aria-labelledby="nav-{{$tab['title']}}-tab">
{{--{{ $tab['content'] }} {{ $loop->index }}--}}
@yield('content')
</div>
@endforeach
</div>
The inner form blade
@extends('organisms.tabs.tabs')
@section('content')
<form>
... // here I would like the $tab variable from the loop in the layout
</form>
@endsection
laravel laravel-blade
asked Nov 19 '18 at 12:27
Thomas
3,98431746
add a comment |
0
You might think, just use an include, but for reuseability reasons I would like to keep the layout a layout without strong ties to the child.
The tabs layout
<nav>
<div class="nav nav-tabs" id="nav-tab" role="tablist">
@foreach ($tabs as $tab)
<a class="nav-item nav-link
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}-tab" data-toggle="tab" href="#nav-{{$tab['title']}}" role="tab" aria-controls="nav-{{$tab['title']}}" aria-selected="true">{{$tab['title']}}</a>
@endforeach
</div>
</nav>
<div class="tab-content" id="nav-tabContent">
@foreach ($tabs as $tab)
<div class="tab-pane fade show
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}" role="tabpanel" aria-labelledby="nav-{{$tab['title']}}-tab">
{{--{{ $tab['content'] }} {{ $loop->index }}--}}
@yield('content')
</div>
@endforeach
</div>
The inner form blade
@extends('organisms.tabs.tabs')
@section('content')
<form>
... // here I would like the $tab variable from the loop in the layout
</form>
@endsection
laravel laravel-blade
asked Nov 19 '18 at 12:27
Thomas
3,98431746
add a comment |
0
0
0
You might think, just use an include, but for reuseability reasons I would like to keep the layout a layout without strong ties to the child.
The tabs layout
<nav>
<div class="nav nav-tabs" id="nav-tab" role="tablist">
@foreach ($tabs as $tab)
<a class="nav-item nav-link
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}-tab" data-toggle="tab" href="#nav-{{$tab['title']}}" role="tab" aria-controls="nav-{{$tab['title']}}" aria-selected="true">{{$tab['title']}}</a>
@endforeach
</div>
</nav>
<div class="tab-content" id="nav-tabContent">
@foreach ($tabs as $tab)
<div class="tab-pane fade show
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}" role="tabpanel" aria-labelledby="nav-{{$tab['title']}}-tab">
{{--{{ $tab['content'] }} {{ $loop->index }}--}}
@yield('content')
</div>
@endforeach
</div>
The inner form blade
@extends('organisms.tabs.tabs')
@section('content')
<form>
... // here I would like the $tab variable from the loop in the layout
</form>
@endsection
laravel laravel-blade
asked Nov 19 '18 at 12:27
Thomas
3,98431746
You might think, just use an include, but for reuseability reasons I would like to keep the layout a layout without strong ties to the child.
The tabs layout
<nav>
<div class="nav nav-tabs" id="nav-tab" role="tablist">
@foreach ($tabs as $tab)
<a class="nav-item nav-link
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}-tab" data-toggle="tab" href="#nav-{{$tab['title']}}" role="tab" aria-controls="nav-{{$tab['title']}}" aria-selected="true">{{$tab['title']}}</a>
@endforeach
</div>
</nav>
<div class="tab-content" id="nav-tabContent">
@foreach ($tabs as $tab)
<div class="tab-pane fade show
@if ($loop->first)
active
@endif
" id="nav-{{$tab['title']}}" role="tabpanel" aria-labelledby="nav-{{$tab['title']}}-tab">
{{--{{ $tab['content'] }} {{ $loop->index }}--}}
@yield('content')
</div>
@endforeach
</div>
The inner form blade
@extends('organisms.tabs.tabs')
@section('content')
<form>
... // here I would like the $tab variable from the loop in the layout
</form>
@endsection
laravel laravel-blade
laravel laravel-blade
asked Nov 19 '18 at 12:27
Thomas
3,98431746
asked Nov 19 '18 at 12:27
Thomas
3,98431746
asked Nov 19 '18 at 12:27
Thomas
3,98431746
asked Nov 19 '18 at 12:27
Thomas
3,98431746
asked Nov 19 '18 at 12:27
Thomas
3,98431746
3,98431746
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
I think you should use something like this:
@foreach ($tabs as $tab)
{!! $tab->innerform() !!}
@endforeach
And in Tab model:
public function innerform() {
return view('innerform', ['tab' => $this])->render();
}
answered Nov 19 '18 at 13:01
Pourbahrami
1548
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
I think you should use something like this:
@foreach ($tabs as $tab)
{!! $tab->innerform() !!}
@endforeach
And in Tab model:
public function innerform() {
return view('innerform', ['tab' => $this])->render();
}
answered Nov 19 '18 at 13:01
Pourbahrami
1548
add a comment |
0
I think you should use something like this:
@foreach ($tabs as $tab)
{!! $tab->innerform() !!}
@endforeach
And in Tab model:
public function innerform() {
return view('innerform', ['tab' => $this])->render();
}
answered Nov 19 '18 at 13:01
Pourbahrami
1548
add a comment |
0
0
0
I think you should use something like this:
@foreach ($tabs as $tab)
{!! $tab->innerform() !!}
@endforeach
And in Tab model:
public function innerform() {
return view('innerform', ['tab' => $this])->render();
}
answered Nov 19 '18 at 13:01
Pourbahrami
1548
I think you should use something like this:
@foreach ($tabs as $tab)
{!! $tab->innerform() !!}
@endforeach
And in Tab model:
public function innerform() {
return view('innerform', ['tab' => $this])->render();
}
answered Nov 19 '18 at 13:01
Pourbahrami
1548
answered Nov 19 '18 at 13:01
Pourbahrami
1548
answered Nov 19 '18 at 13:01
Pourbahrami
1548
answered Nov 19 '18 at 13:01
Pourbahrami
1548
1548
add a comment |
add a comment |
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