Match once but not repetitions [duplicate]

-1

This question already has an answer here:

• 
  Regex that does not allow consecutive dots
  
  3 answers
  
  


• 
  Regex for not allowing consecutive dots or underscores
  
  3 answers
  
  


• 
  Regex for not containing consecutive characters
  
  3 answers
  
  

I have the following code to match:

String(s) in which . is not present consecutively, it can be alternatively

let strArr = [

  '#foo3.5', // true

  '#bar34..34', // false

  '.', // true

  '#ipv4-1.1.1.1' // true

];



const re = /^([^.]*.[^.]*)+$/;



strArr.map(

  (val, idx) => console.log(`${idx}: ${re.test(val)}`)

);

But, the above code also matches #bar34..34, which is not desired. I tried changing the * meta-character in my pattern to +, but then, it fails to match . and #ipv4-1.1.1.1 strings.

Also, I want my regex to be small, because it is a part of a very long regex (you can suppose it an Email ID regex). So, what should be the required regex?

javascript regex match

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asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

marked as duplicate by Wiktor Stribiżew javascript
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Nov 20 '18 at 6:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

-1

This question already has an answer here:

• 
  Regex that does not allow consecutive dots
  
  3 answers
  
  


• 
  Regex for not allowing consecutive dots or underscores
  
  3 answers
  
  


• 
  Regex for not containing consecutive characters
  
  3 answers
  
  

I have the following code to match:

String(s) in which . is not present consecutively, it can be alternatively

let strArr = [

  '#foo3.5', // true

  '#bar34..34', // false

  '.', // true

  '#ipv4-1.1.1.1' // true

];



const re = /^([^.]*.[^.]*)+$/;



strArr.map(

  (val, idx) => console.log(`${idx}: ${re.test(val)}`)

);

But, the above code also matches #bar34..34, which is not desired. I tried changing the * meta-character in my pattern to +, but then, it fails to match . and #ipv4-1.1.1.1 strings.

Also, I want my regex to be small, because it is a part of a very long regex (you can suppose it an Email ID regex). So, what should be the required regex?

javascript regex match

share|improve this question

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

marked as duplicate by Wiktor Stribiżew javascript
Users with the  javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

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Nov 20 '18 at 6:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

-1

-1

-1

This question already has an answer here:

• 
  Regex that does not allow consecutive dots
  
  3 answers
  
  


• 
  Regex for not allowing consecutive dots or underscores
  
  3 answers
  
  


• 
  Regex for not containing consecutive characters
  
  3 answers
  
  

I have the following code to match:

String(s) in which . is not present consecutively, it can be alternatively

let strArr = [

  '#foo3.5', // true

  '#bar34..34', // false

  '.', // true

  '#ipv4-1.1.1.1' // true

];



const re = /^([^.]*.[^.]*)+$/;



strArr.map(

  (val, idx) => console.log(`${idx}: ${re.test(val)}`)

);

But, the above code also matches #bar34..34, which is not desired. I tried changing the * meta-character in my pattern to +, but then, it fails to match . and #ipv4-1.1.1.1 strings.

Also, I want my regex to be small, because it is a part of a very long regex (you can suppose it an Email ID regex). So, what should be the required regex?

javascript regex match

share|improve this question

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

This question already has an answer here:

• 
  Regex that does not allow consecutive dots
  
  3 answers
  
  


• 
  Regex for not allowing consecutive dots or underscores
  
  3 answers
  
  


• 
  Regex for not containing consecutive characters
  
  3 answers
  
  

I have the following code to match:

String(s) in which . is not present consecutively, it can be alternatively

let strArr = [

  '#foo3.5', // true

  '#bar34..34', // false

  '.', // true

  '#ipv4-1.1.1.1' // true

];



const re = /^([^.]*.[^.]*)+$/;



strArr.map(

  (val, idx) => console.log(`${idx}: ${re.test(val)}`)

);

But, the above code also matches #bar34..34, which is not desired. I tried changing the * meta-character in my pattern to +, but then, it fails to match . and #ipv4-1.1.1.1 strings.

Also, I want my regex to be small, because it is a part of a very long regex (you can suppose it an Email ID regex). So, what should be the required regex?

This question already has an answer here:

• 
  Regex that does not allow consecutive dots
  
  3 answers
  
  


• 
  Regex for not allowing consecutive dots or underscores
  
  3 answers
  
  


• 
  Regex for not containing consecutive characters
  
  3 answers
  
  

let strArr = [

  '#foo3.5', // true

  '#bar34..34', // false

  '.', // true

  '#ipv4-1.1.1.1' // true

];



const re = /^([^.]*.[^.]*)+$/;



strArr.map(

  (val, idx) => console.log(`${idx}: ${re.test(val)}`)

);

let strArr = [

  '#foo3.5', // true

  '#bar34..34', // false

  '.', // true

  '#ipv4-1.1.1.1' // true

];



const re = /^([^.]*.[^.]*)+$/;



strArr.map(

  (val, idx) => console.log(`${idx}: ${re.test(val)}`)

);

javascript regex match

javascript regex match

share|improve this question

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

share|improve this question

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

share|improve this question

share|improve this question

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

asked Nov 20 '18 at 6:05

rv7rv7

2,2061324

2,2061324

marked as duplicate by Wiktor Stribiżew javascript
Users with the  javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

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Nov 20 '18 at 6:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Wiktor Stribiżew javascript
Users with the  javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

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Nov 20 '18 at 6:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

add a comment | 

1 Answer
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oldest

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1

Match a whole string with no consecutive dots:

/^(?!.*..).*$/

share|improve this answer

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

add a comment | 

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

1

Match a whole string with no consecutive dots:

/^(?!.*..).*$/

share|improve this answer

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

add a comment | 

1

Match a whole string with no consecutive dots:

/^(?!.*..).*$/

share|improve this answer

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

add a comment | 

1

1

1

Match a whole string with no consecutive dots:

/^(?!.*..).*$/

share|improve this answer

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

Match a whole string with no consecutive dots:

/^(?!.*..).*$/

share|improve this answer

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

share|improve this answer

share|improve this answer

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

answered Nov 20 '18 at 6:07

AmadanAmadan

129k13140192

129k13140192

add a comment | 

add a comment | 

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