Mixing
Next Augustus in Future with Carbon
Is there prettier way to get the full-date of the next 1st of August:
$year = date('Y') + 1;
if (date('j') >= 1 && date('j') <= 8) {
$year = date('Y');
}
$nextAugust = '01-08-' . $year;
$nextAugust = Carbon::createFromFormat('d-m-Y', $nextAugust);
Preferably with Carbon PHP
php-carbon
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
add a comment |
Is there prettier way to get the full-date of the next 1st of August:
$year = date('Y') + 1;
if (date('j') >= 1 && date('j') <= 8) {
$year = date('Y');
}
$nextAugust = '01-08-' . $year;
$nextAugust = Carbon::createFromFormat('d-m-Y', $nextAugust);
Preferably with Carbon PHP
php-carbon
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
add a comment |
Is there prettier way to get the full-date of the next 1st of August:
$year = date('Y') + 1;
if (date('j') >= 1 && date('j') <= 8) {
$year = date('Y');
}
$nextAugust = '01-08-' . $year;
$nextAugust = Carbon::createFromFormat('d-m-Y', $nextAugust);
Preferably with Carbon PHP
php-carbon
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
Is there prettier way to get the full-date of the next 1st of August:
$year = date('Y') + 1;
if (date('j') >= 1 && date('j') <= 8) {
$year = date('Y');
}
$nextAugust = '01-08-' . $year;
$nextAugust = Carbon::createFromFormat('d-m-Y', $nextAugust);
Preferably with Carbon PHP
php-carbon
php-carbon
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
asked Nov 20 '18 at 12:29
user1469734user1469734
92552741
92552741
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Following code find next august with carbon object.
$nextAugust = Carbon::parse('first day of August' . (date('n') > 8 ? ' next year' : ''));
I hope my answer can help for your problem.
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
add a comment |
This will do it:
$nextAugust = Carbon::createFromFormat('d-m-Y', '01-08-' . (date('Y') + intval(date('m') / 8)));
Clarification:
Instead of the if condition, you can divide the current month by 8 and convert the resulting value to an integer using intval(date('m') / 8). This will give you either 0 or 1, and will be added to the current year. For example, if you are in March (i.e., m is 3), you get 3/8 = 0. Hence, next August will be in the same year because 2018 + 0 will be 2018. On the other hand, if you are in October (i.e., m is 10), you get 10/8 = 1. Hence, next August will be in the next year because 2018 + 1 will be 2019. Here's how you simply implement it:
Hope it helps.
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
What does the intval(date('m') / 8) do? I meant more like:Carbon::parse('next August'), but that doesn't work..
– user1469734
Nov 29 '18 at 8:57
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
add a comment |
For me, I'll do:
$date = '01-08-';
$year_now = Carbon::now()->format('Y');
$date = $date.$year_now;
$carbon_date = Carbon::createFromFormat('d-m-Y', $date);
Let me know if it is not working.
answered Nov 29 '18 at 5:17
ChrisChris
11
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Following code find next august with carbon object.
$nextAugust = Carbon::parse('first day of August' . (date('n') > 8 ? ' next year' : ''));
I hope my answer can help for your problem.
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
add a comment |
Following code find next august with carbon object.
$nextAugust = Carbon::parse('first day of August' . (date('n') > 8 ? ' next year' : ''));
I hope my answer can help for your problem.
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
add a comment |
Following code find next august with carbon object.
$nextAugust = Carbon::parse('first day of August' . (date('n') > 8 ? ' next year' : ''));
I hope my answer can help for your problem.
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
Following code find next august with carbon object.
$nextAugust = Carbon::parse('first day of August' . (date('n') > 8 ? ' next year' : ''));
I hope my answer can help for your problem.
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
answered Nov 29 '18 at 14:39
FGDeveloperFGDeveloper
664415
664415
add a comment |
add a comment |
This will do it:
$nextAugust = Carbon::createFromFormat('d-m-Y', '01-08-' . (date('Y') + intval(date('m') / 8)));
Clarification:
Instead of the if condition, you can divide the current month by 8 and convert the resulting value to an integer using intval(date('m') / 8). This will give you either 0 or 1, and will be added to the current year. For example, if you are in March (i.e., m is 3), you get 3/8 = 0. Hence, next August will be in the same year because 2018 + 0 will be 2018. On the other hand, if you are in October (i.e., m is 10), you get 10/8 = 1. Hence, next August will be in the next year because 2018 + 1 will be 2019. Here's how you simply implement it:
Hope it helps.
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
What does the intval(date('m') / 8) do? I meant more like:Carbon::parse('next August'), but that doesn't work..
– user1469734
Nov 29 '18 at 8:57
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
add a comment |
This will do it:
$nextAugust = Carbon::createFromFormat('d-m-Y', '01-08-' . (date('Y') + intval(date('m') / 8)));
Clarification:
Instead of the if condition, you can divide the current month by 8 and convert the resulting value to an integer using intval(date('m') / 8). This will give you either 0 or 1, and will be added to the current year. For example, if you are in March (i.e., m is 3), you get 3/8 = 0. Hence, next August will be in the same year because 2018 + 0 will be 2018. On the other hand, if you are in October (i.e., m is 10), you get 10/8 = 1. Hence, next August will be in the next year because 2018 + 1 will be 2019. Here's how you simply implement it:
Hope it helps.
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
What does the intval(date('m') / 8) do? I meant more like:Carbon::parse('next August'), but that doesn't work..
– user1469734
Nov 29 '18 at 8:57
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
add a comment |
This will do it:
$nextAugust = Carbon::createFromFormat('d-m-Y', '01-08-' . (date('Y') + intval(date('m') / 8)));
Clarification:
Instead of the if condition, you can divide the current month by 8 and convert the resulting value to an integer using intval(date('m') / 8). This will give you either 0 or 1, and will be added to the current year. For example, if you are in March (i.e., m is 3), you get 3/8 = 0. Hence, next August will be in the same year because 2018 + 0 will be 2018. On the other hand, if you are in October (i.e., m is 10), you get 10/8 = 1. Hence, next August will be in the next year because 2018 + 1 will be 2019. Here's how you simply implement it:
Hope it helps.
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
This will do it:
$nextAugust = Carbon::createFromFormat('d-m-Y', '01-08-' . (date('Y') + intval(date('m') / 8)));
Clarification:
Instead of the if condition, you can divide the current month by 8 and convert the resulting value to an integer using intval(date('m') / 8). This will give you either 0 or 1, and will be added to the current year. For example, if you are in March (i.e., m is 3), you get 3/8 = 0. Hence, next August will be in the same year because 2018 + 0 will be 2018. On the other hand, if you are in October (i.e., m is 10), you get 10/8 = 1. Hence, next August will be in the next year because 2018 + 1 will be 2019. Here's how you simply implement it:
Hope it helps.
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
edited Nov 29 '18 at 16:49
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
answered Nov 29 '18 at 5:26
TeeKeaTeeKea
3,22341630
3,22341630
What does the intval(date('m') / 8) do? I meant more like:Carbon::parse('next August'), but that doesn't work..
– user1469734
Nov 29 '18 at 8:57
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
add a comment |
What does the intval(date('m') / 8) do? I meant more like:Carbon::parse('next August'), but that doesn't work..
– user1469734
Nov 29 '18 at 8:57
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
What does the intval(date('m') / 8) do? I meant more like:
Carbon::parse('next August'), but that doesn't work..– user1469734
Nov 29 '18 at 8:57
What does the intval(date('m') / 8) do? I meant more like:
Carbon::parse('next August'), but that doesn't work..– user1469734
Nov 29 '18 at 8:57
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
@user1469734 I updated my answer to clarify this.
– TeeKea
Nov 29 '18 at 15:38
add a comment |
For me, I'll do:
$date = '01-08-';
$year_now = Carbon::now()->format('Y');
$date = $date.$year_now;
$carbon_date = Carbon::createFromFormat('d-m-Y', $date);
Let me know if it is not working.
answered Nov 29 '18 at 5:17
ChrisChris
11
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
add a comment |
For me, I'll do:
$date = '01-08-';
$year_now = Carbon::now()->format('Y');
$date = $date.$year_now;
$carbon_date = Carbon::createFromFormat('d-m-Y', $date);
Let me know if it is not working.
answered Nov 29 '18 at 5:17
ChrisChris
11
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
add a comment |
For me, I'll do:
$date = '01-08-';
$year_now = Carbon::now()->format('Y');
$date = $date.$year_now;
$carbon_date = Carbon::createFromFormat('d-m-Y', $date);
Let me know if it is not working.
answered Nov 29 '18 at 5:17
ChrisChris
11
For me, I'll do:
$date = '01-08-';
$year_now = Carbon::now()->format('Y');
$date = $date.$year_now;
$carbon_date = Carbon::createFromFormat('d-m-Y', $date);
Let me know if it is not working.
answered Nov 29 '18 at 5:17
ChrisChris
11
answered Nov 29 '18 at 5:17
ChrisChris
11
answered Nov 29 '18 at 5:17
ChrisChris
11
answered Nov 29 '18 at 5:17
ChrisChris
11
11
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
add a comment |
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Can't take this seriously
– user1469734
Nov 29 '18 at 8:56
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
Are you trolling?
– user1670816
Nov 29 '18 at 10:28
add a comment |
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