Mixing
Probability homework help. Data management Grade 12. [on hold]
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I need help with two questions!
The first question asks… Let X and Y be mutually exclusive events such that P(X) = 1/5 and P(Y) = 1/4. Find a) P(X (union symbol) Y) b) P(X’UY’)
The second question asks... A safe opens when the right combination of three numbers from 00 to 99 are entered. The same number may be used more than once. a) What is the probability of getting the correct comibination by chance? b) What is the probability of getting the right combination of you already know the first number? c) What is the probability of getting the right combination if you already know the first two numbers?
probability
asked 2 days ago
Alexis
12
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put on hold as off-topic by Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
-6
down vote
favorite
I need help with two questions!
The first question asks… Let X and Y be mutually exclusive events such that P(X) = 1/5 and P(Y) = 1/4. Find a) P(X (union symbol) Y) b) P(X’UY’)
The second question asks... A safe opens when the right combination of three numbers from 00 to 99 are entered. The same number may be used more than once. a) What is the probability of getting the correct comibination by chance? b) What is the probability of getting the right combination of you already know the first number? c) What is the probability of getting the right combination if you already know the first two numbers?
probability
asked 2 days ago
Alexis
12
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
3
Can you show us what you have attempted? Or what is interesting about this question? Usually questions posed with the tone "do this homework problem for me" are not well-received.
– Mason
2 days ago
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up vote
-6
down vote
favorite
up vote
-6
down vote
favorite
I need help with two questions!
The first question asks… Let X and Y be mutually exclusive events such that P(X) = 1/5 and P(Y) = 1/4. Find a) P(X (union symbol) Y) b) P(X’UY’)
The second question asks... A safe opens when the right combination of three numbers from 00 to 99 are entered. The same number may be used more than once. a) What is the probability of getting the correct comibination by chance? b) What is the probability of getting the right combination of you already know the first number? c) What is the probability of getting the right combination if you already know the first two numbers?
probability
asked 2 days ago
Alexis
12
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I need help with two questions!
The first question asks… Let X and Y be mutually exclusive events such that P(X) = 1/5 and P(Y) = 1/4. Find a) P(X (union symbol) Y) b) P(X’UY’)
The second question asks... A safe opens when the right combination of three numbers from 00 to 99 are entered. The same number may be used more than once. a) What is the probability of getting the correct comibination by chance? b) What is the probability of getting the right combination of you already know the first number? c) What is the probability of getting the right combination if you already know the first two numbers?
probability
probability
asked 2 days ago
Alexis
12
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Alexis
12
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Alexis
12
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Alexis
12
asked 2 days ago
Alexis
12
12
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Alexis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Kavi Rama Murthy, lulu, Shaun, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
3
Can you show us what you have attempted? Or what is interesting about this question? Usually questions posed with the tone "do this homework problem for me" are not well-received.
– Mason
2 days ago
add a comment |
3
Can you show us what you have attempted? Or what is interesting about this question? Usually questions posed with the tone "do this homework problem for me" are not well-received.
– Mason
2 days ago
3
3
Can you show us what you have attempted? Or what is interesting about this question? Usually questions posed with the tone "do this homework problem for me" are not well-received.
– Mason
2 days ago
Can you show us what you have attempted? Or what is interesting about this question? Usually questions posed with the tone "do this homework problem for me" are not well-received.
– Mason
2 days ago
add a comment |
1 Answer
1
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oldest
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0
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accepted
For problem a), note: $P(X cup Y)$ denotes "the probability of $X$ or $Y$ happening." We know, for mutually exclusive events,
$$P(X cup Y) = P(X) + P(Y)$$
For problem b) note: $P(X')$ denotes "the probability of $X$ not happening." Per the probability analogue of one of de Morgan's laws,
$$P(X' cup Y') = 1 - P(X cap Y)$$
i.e. "the probability of both $X$ and $Y$ happening". What do we know about mutually exclusive events?
For problem 2, take note of the fact that picking numbers $00-99$ at random would be independent from picking the number again. We know if events $A,B$ are independent, then
$$P(A cap B) = P(A) cdot P(B)$$
You can apply this and a little common sense to solve these problems.
answered 2 days ago
Eevee Trainer
97111
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
For problem a), note: $P(X cup Y)$ denotes "the probability of $X$ or $Y$ happening." We know, for mutually exclusive events,
$$P(X cup Y) = P(X) + P(Y)$$
For problem b) note: $P(X')$ denotes "the probability of $X$ not happening." Per the probability analogue of one of de Morgan's laws,
$$P(X' cup Y') = 1 - P(X cap Y)$$
i.e. "the probability of both $X$ and $Y$ happening". What do we know about mutually exclusive events?
For problem 2, take note of the fact that picking numbers $00-99$ at random would be independent from picking the number again. We know if events $A,B$ are independent, then
$$P(A cap B) = P(A) cdot P(B)$$
You can apply this and a little common sense to solve these problems.
answered 2 days ago
Eevee Trainer
97111
add a comment |
up vote
0
down vote
accepted
For problem a), note: $P(X cup Y)$ denotes "the probability of $X$ or $Y$ happening." We know, for mutually exclusive events,
$$P(X cup Y) = P(X) + P(Y)$$
For problem b) note: $P(X')$ denotes "the probability of $X$ not happening." Per the probability analogue of one of de Morgan's laws,
$$P(X' cup Y') = 1 - P(X cap Y)$$
i.e. "the probability of both $X$ and $Y$ happening". What do we know about mutually exclusive events?
For problem 2, take note of the fact that picking numbers $00-99$ at random would be independent from picking the number again. We know if events $A,B$ are independent, then
$$P(A cap B) = P(A) cdot P(B)$$
You can apply this and a little common sense to solve these problems.
answered 2 days ago
Eevee Trainer
97111
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
For problem a), note: $P(X cup Y)$ denotes "the probability of $X$ or $Y$ happening." We know, for mutually exclusive events,
$$P(X cup Y) = P(X) + P(Y)$$
For problem b) note: $P(X')$ denotes "the probability of $X$ not happening." Per the probability analogue of one of de Morgan's laws,
$$P(X' cup Y') = 1 - P(X cap Y)$$
i.e. "the probability of both $X$ and $Y$ happening". What do we know about mutually exclusive events?
For problem 2, take note of the fact that picking numbers $00-99$ at random would be independent from picking the number again. We know if events $A,B$ are independent, then
$$P(A cap B) = P(A) cdot P(B)$$
You can apply this and a little common sense to solve these problems.
answered 2 days ago
Eevee Trainer
97111
For problem a), note: $P(X cup Y)$ denotes "the probability of $X$ or $Y$ happening." We know, for mutually exclusive events,
$$P(X cup Y) = P(X) + P(Y)$$
For problem b) note: $P(X')$ denotes "the probability of $X$ not happening." Per the probability analogue of one of de Morgan's laws,
$$P(X' cup Y') = 1 - P(X cap Y)$$
i.e. "the probability of both $X$ and $Y$ happening". What do we know about mutually exclusive events?
For problem 2, take note of the fact that picking numbers $00-99$ at random would be independent from picking the number again. We know if events $A,B$ are independent, then
$$P(A cap B) = P(A) cdot P(B)$$
You can apply this and a little common sense to solve these problems.
answered 2 days ago
Eevee Trainer
97111
answered 2 days ago
Eevee Trainer
97111
answered 2 days ago
Eevee Trainer
97111
answered 2 days ago
Eevee Trainer
97111
97111
add a comment |
add a comment |
3
Can you show us what you have attempted? Or what is interesting about this question? Usually questions posed with the tone "do this homework problem for me" are not well-received.
– Mason
2 days ago