Sum of first 25 terms of AP whose first four terms












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Find the sum of first $25$ terms of an AP whose first four terms are
$1, log_yx,log_zy$ and $-15cdot log_xz$.




I made equations from given data but they won't help. Something seems missing.










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  • 2




    $begingroup$
    If the four numbers are $$1,1+d,1+2d,1+3d$$ $$(1+d)(1+2d)(1+3d)=-15$$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 12:20










  • $begingroup$
    @lab That's really sleek. Didn't notice!
    $endgroup$
    – Ice Inkberry
    Jan 3 at 12:21
















0












$begingroup$



Find the sum of first $25$ terms of an AP whose first four terms are
$1, log_yx,log_zy$ and $-15cdot log_xz$.




I made equations from given data but they won't help. Something seems missing.










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    If the four numbers are $$1,1+d,1+2d,1+3d$$ $$(1+d)(1+2d)(1+3d)=-15$$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 12:20










  • $begingroup$
    @lab That's really sleek. Didn't notice!
    $endgroup$
    – Ice Inkberry
    Jan 3 at 12:21














0












0








0


1



$begingroup$



Find the sum of first $25$ terms of an AP whose first four terms are
$1, log_yx,log_zy$ and $-15cdot log_xz$.




I made equations from given data but they won't help. Something seems missing.










share|cite|improve this question











$endgroup$





Find the sum of first $25$ terms of an AP whose first four terms are
$1, log_yx,log_zy$ and $-15cdot log_xz$.




I made equations from given data but they won't help. Something seems missing.







sequences-and-series






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 3 at 15:52









amWhy

1




1










asked Jan 3 at 12:14









Ice InkberryIce Inkberry

336112




336112








  • 2




    $begingroup$
    If the four numbers are $$1,1+d,1+2d,1+3d$$ $$(1+d)(1+2d)(1+3d)=-15$$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 12:20










  • $begingroup$
    @lab That's really sleek. Didn't notice!
    $endgroup$
    – Ice Inkberry
    Jan 3 at 12:21














  • 2




    $begingroup$
    If the four numbers are $$1,1+d,1+2d,1+3d$$ $$(1+d)(1+2d)(1+3d)=-15$$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 12:20










  • $begingroup$
    @lab That's really sleek. Didn't notice!
    $endgroup$
    – Ice Inkberry
    Jan 3 at 12:21








2




2




$begingroup$
If the four numbers are $$1,1+d,1+2d,1+3d$$ $$(1+d)(1+2d)(1+3d)=-15$$
$endgroup$
– lab bhattacharjee
Jan 3 at 12:20




$begingroup$
If the four numbers are $$1,1+d,1+2d,1+3d$$ $$(1+d)(1+2d)(1+3d)=-15$$
$endgroup$
– lab bhattacharjee
Jan 3 at 12:20












$begingroup$
@lab That's really sleek. Didn't notice!
$endgroup$
– Ice Inkberry
Jan 3 at 12:21




$begingroup$
@lab That's really sleek. Didn't notice!
$endgroup$
– Ice Inkberry
Jan 3 at 12:21










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