Amalgamation base, extending Galois type
$begingroup$
Here on the page 12 the Observation 1.11 5) says
If $Mleq_{frak K} N$ are from ${frak K}_{lambda}$, $M$ is an amalgamation base
and $pin mathscr{S}(M) ;underline{text{then}}$ there is $qin mathscr{S}(N)$ extending $p$,
so the mapping $qmapsto qupharpoonright M$ is a function from $mathscr{S}(N)$ onto $mathscr{S}(M)$.
My question is easy: how have we technically used in the entire paragraph that $M$ is an amalgamation base ?? Some diagrams would clarify the situation!
functions logic order-theory predicate-logic model-theory
$endgroup$
add a comment |
$begingroup$
Here on the page 12 the Observation 1.11 5) says
If $Mleq_{frak K} N$ are from ${frak K}_{lambda}$, $M$ is an amalgamation base
and $pin mathscr{S}(M) ;underline{text{then}}$ there is $qin mathscr{S}(N)$ extending $p$,
so the mapping $qmapsto qupharpoonright M$ is a function from $mathscr{S}(N)$ onto $mathscr{S}(M)$.
My question is easy: how have we technically used in the entire paragraph that $M$ is an amalgamation base ?? Some diagrams would clarify the situation!
functions logic order-theory predicate-logic model-theory
$endgroup$
add a comment |
$begingroup$
Here on the page 12 the Observation 1.11 5) says
If $Mleq_{frak K} N$ are from ${frak K}_{lambda}$, $M$ is an amalgamation base
and $pin mathscr{S}(M) ;underline{text{then}}$ there is $qin mathscr{S}(N)$ extending $p$,
so the mapping $qmapsto qupharpoonright M$ is a function from $mathscr{S}(N)$ onto $mathscr{S}(M)$.
My question is easy: how have we technically used in the entire paragraph that $M$ is an amalgamation base ?? Some diagrams would clarify the situation!
functions logic order-theory predicate-logic model-theory
$endgroup$
Here on the page 12 the Observation 1.11 5) says
If $Mleq_{frak K} N$ are from ${frak K}_{lambda}$, $M$ is an amalgamation base
and $pin mathscr{S}(M) ;underline{text{then}}$ there is $qin mathscr{S}(N)$ extending $p$,
so the mapping $qmapsto qupharpoonright M$ is a function from $mathscr{S}(N)$ onto $mathscr{S}(M)$.
My question is easy: how have we technically used in the entire paragraph that $M$ is an amalgamation base ?? Some diagrams would clarify the situation!
functions logic order-theory predicate-logic model-theory
functions logic order-theory predicate-logic model-theory
edited Jan 21 at 18:39
user122424
asked Jan 20 at 14:08
user122424user122424
1,1482716
1,1482716
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add a comment |
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