Elliptic Curves (equation)












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Is there a specific method to solve equations like $ y^2 = x^3 - n^2x $ ?
I was reading an example about $ y^2 = x^3 - 49x $ and it says that a solution is $ (-frac{63}{16},frac{735}{64}) $ .
How did he find it?
Thanks



In some papers I saw that if I find a solution $ (x_{0},y_{0}) $ and replace $ x $ with $ x-x_{0} $ and $ y $ with $ y=kx+y_{0} $ I will find all rational solutions.










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  • $begingroup$
    I don't understand what you mean by "solving" such an equation. In what sense does $left(-frac{63}{16},frac{735}{64}right)$ "solve" $y^2= x^3- 49x$?
    $endgroup$
    – user247327
    Jan 27 at 13:33










  • $begingroup$
    I want to know if there is a way to find all rational points $ (x,y) $ giving that $ y^2= x^3 -49x $ or $ y^2= x^3 - n^2x $ in general. This example is from "Arithmetic Progressions of Three squares" by Keith Conrad. The point I wrote verifies the equation
    $endgroup$
    – Dr.Mathematics
    Jan 27 at 13:40












  • $begingroup$
    Have a look at Algorithms for finding rational points on an elliptic curve? from Mathoverflow.
    $endgroup$
    – kelalaka
    Jan 27 at 13:57










  • $begingroup$
    The last paragraph sounds really strange. But, are you familiar with the chord-tangent method of finding more points on an elliptic curve?
    $endgroup$
    – Jyrki Lahtonen
    Jan 27 at 14:38










  • $begingroup$
    @Dr.Mathematics : Do you understand why points of finite order ($E(mathbb{Q})_{tors}$) are very special rational points ? The method to find both are very different. Your previous question is referencing everything you need for $E(mathbb{Q})_{tors}$.
    $endgroup$
    – reuns
    Jan 27 at 17:10


















0












$begingroup$


Is there a specific method to solve equations like $ y^2 = x^3 - n^2x $ ?
I was reading an example about $ y^2 = x^3 - 49x $ and it says that a solution is $ (-frac{63}{16},frac{735}{64}) $ .
How did he find it?
Thanks



In some papers I saw that if I find a solution $ (x_{0},y_{0}) $ and replace $ x $ with $ x-x_{0} $ and $ y $ with $ y=kx+y_{0} $ I will find all rational solutions.










share|cite|improve this question











$endgroup$












  • $begingroup$
    I don't understand what you mean by "solving" such an equation. In what sense does $left(-frac{63}{16},frac{735}{64}right)$ "solve" $y^2= x^3- 49x$?
    $endgroup$
    – user247327
    Jan 27 at 13:33










  • $begingroup$
    I want to know if there is a way to find all rational points $ (x,y) $ giving that $ y^2= x^3 -49x $ or $ y^2= x^3 - n^2x $ in general. This example is from "Arithmetic Progressions of Three squares" by Keith Conrad. The point I wrote verifies the equation
    $endgroup$
    – Dr.Mathematics
    Jan 27 at 13:40












  • $begingroup$
    Have a look at Algorithms for finding rational points on an elliptic curve? from Mathoverflow.
    $endgroup$
    – kelalaka
    Jan 27 at 13:57










  • $begingroup$
    The last paragraph sounds really strange. But, are you familiar with the chord-tangent method of finding more points on an elliptic curve?
    $endgroup$
    – Jyrki Lahtonen
    Jan 27 at 14:38










  • $begingroup$
    @Dr.Mathematics : Do you understand why points of finite order ($E(mathbb{Q})_{tors}$) are very special rational points ? The method to find both are very different. Your previous question is referencing everything you need for $E(mathbb{Q})_{tors}$.
    $endgroup$
    – reuns
    Jan 27 at 17:10
















0












0








0





$begingroup$


Is there a specific method to solve equations like $ y^2 = x^3 - n^2x $ ?
I was reading an example about $ y^2 = x^3 - 49x $ and it says that a solution is $ (-frac{63}{16},frac{735}{64}) $ .
How did he find it?
Thanks



In some papers I saw that if I find a solution $ (x_{0},y_{0}) $ and replace $ x $ with $ x-x_{0} $ and $ y $ with $ y=kx+y_{0} $ I will find all rational solutions.










share|cite|improve this question











$endgroup$




Is there a specific method to solve equations like $ y^2 = x^3 - n^2x $ ?
I was reading an example about $ y^2 = x^3 - 49x $ and it says that a solution is $ (-frac{63}{16},frac{735}{64}) $ .
How did he find it?
Thanks



In some papers I saw that if I find a solution $ (x_{0},y_{0}) $ and replace $ x $ with $ x-x_{0} $ and $ y $ with $ y=kx+y_{0} $ I will find all rational solutions.







number-theory elliptic-curves






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 27 at 13:18









Jyrki Lahtonen

110k13171386




110k13171386










asked Jan 27 at 13:15









Dr.MathematicsDr.Mathematics

466




466












  • $begingroup$
    I don't understand what you mean by "solving" such an equation. In what sense does $left(-frac{63}{16},frac{735}{64}right)$ "solve" $y^2= x^3- 49x$?
    $endgroup$
    – user247327
    Jan 27 at 13:33










  • $begingroup$
    I want to know if there is a way to find all rational points $ (x,y) $ giving that $ y^2= x^3 -49x $ or $ y^2= x^3 - n^2x $ in general. This example is from "Arithmetic Progressions of Three squares" by Keith Conrad. The point I wrote verifies the equation
    $endgroup$
    – Dr.Mathematics
    Jan 27 at 13:40












  • $begingroup$
    Have a look at Algorithms for finding rational points on an elliptic curve? from Mathoverflow.
    $endgroup$
    – kelalaka
    Jan 27 at 13:57










  • $begingroup$
    The last paragraph sounds really strange. But, are you familiar with the chord-tangent method of finding more points on an elliptic curve?
    $endgroup$
    – Jyrki Lahtonen
    Jan 27 at 14:38










  • $begingroup$
    @Dr.Mathematics : Do you understand why points of finite order ($E(mathbb{Q})_{tors}$) are very special rational points ? The method to find both are very different. Your previous question is referencing everything you need for $E(mathbb{Q})_{tors}$.
    $endgroup$
    – reuns
    Jan 27 at 17:10




















  • $begingroup$
    I don't understand what you mean by "solving" such an equation. In what sense does $left(-frac{63}{16},frac{735}{64}right)$ "solve" $y^2= x^3- 49x$?
    $endgroup$
    – user247327
    Jan 27 at 13:33










  • $begingroup$
    I want to know if there is a way to find all rational points $ (x,y) $ giving that $ y^2= x^3 -49x $ or $ y^2= x^3 - n^2x $ in general. This example is from "Arithmetic Progressions of Three squares" by Keith Conrad. The point I wrote verifies the equation
    $endgroup$
    – Dr.Mathematics
    Jan 27 at 13:40












  • $begingroup$
    Have a look at Algorithms for finding rational points on an elliptic curve? from Mathoverflow.
    $endgroup$
    – kelalaka
    Jan 27 at 13:57










  • $begingroup$
    The last paragraph sounds really strange. But, are you familiar with the chord-tangent method of finding more points on an elliptic curve?
    $endgroup$
    – Jyrki Lahtonen
    Jan 27 at 14:38










  • $begingroup$
    @Dr.Mathematics : Do you understand why points of finite order ($E(mathbb{Q})_{tors}$) are very special rational points ? The method to find both are very different. Your previous question is referencing everything you need for $E(mathbb{Q})_{tors}$.
    $endgroup$
    – reuns
    Jan 27 at 17:10


















$begingroup$
I don't understand what you mean by "solving" such an equation. In what sense does $left(-frac{63}{16},frac{735}{64}right)$ "solve" $y^2= x^3- 49x$?
$endgroup$
– user247327
Jan 27 at 13:33




$begingroup$
I don't understand what you mean by "solving" such an equation. In what sense does $left(-frac{63}{16},frac{735}{64}right)$ "solve" $y^2= x^3- 49x$?
$endgroup$
– user247327
Jan 27 at 13:33












$begingroup$
I want to know if there is a way to find all rational points $ (x,y) $ giving that $ y^2= x^3 -49x $ or $ y^2= x^3 - n^2x $ in general. This example is from "Arithmetic Progressions of Three squares" by Keith Conrad. The point I wrote verifies the equation
$endgroup$
– Dr.Mathematics
Jan 27 at 13:40






$begingroup$
I want to know if there is a way to find all rational points $ (x,y) $ giving that $ y^2= x^3 -49x $ or $ y^2= x^3 - n^2x $ in general. This example is from "Arithmetic Progressions of Three squares" by Keith Conrad. The point I wrote verifies the equation
$endgroup$
– Dr.Mathematics
Jan 27 at 13:40














$begingroup$
Have a look at Algorithms for finding rational points on an elliptic curve? from Mathoverflow.
$endgroup$
– kelalaka
Jan 27 at 13:57




$begingroup$
Have a look at Algorithms for finding rational points on an elliptic curve? from Mathoverflow.
$endgroup$
– kelalaka
Jan 27 at 13:57












$begingroup$
The last paragraph sounds really strange. But, are you familiar with the chord-tangent method of finding more points on an elliptic curve?
$endgroup$
– Jyrki Lahtonen
Jan 27 at 14:38




$begingroup$
The last paragraph sounds really strange. But, are you familiar with the chord-tangent method of finding more points on an elliptic curve?
$endgroup$
– Jyrki Lahtonen
Jan 27 at 14:38












$begingroup$
@Dr.Mathematics : Do you understand why points of finite order ($E(mathbb{Q})_{tors}$) are very special rational points ? The method to find both are very different. Your previous question is referencing everything you need for $E(mathbb{Q})_{tors}$.
$endgroup$
– reuns
Jan 27 at 17:10






$begingroup$
@Dr.Mathematics : Do you understand why points of finite order ($E(mathbb{Q})_{tors}$) are very special rational points ? The method to find both are very different. Your previous question is referencing everything you need for $E(mathbb{Q})_{tors}$.
$endgroup$
– reuns
Jan 27 at 17:10












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