Induced Semigroup Structures via (left) Translation












3














Let $(M,circ)$ be any semigroup satisfying the following properties:



P-1: $text{For every } x,y,z in M text{, if } z circ x = z circ y , text{ then } , x = y$.



If $zeta in M$ we define $M_zeta = {m in M ; | ; m = zeta circ u}$.



We can define a binary operation $circ_zeta$ on $M_zeta$ as follows:



$tag 1 (zeta circ u) circ_zeta (zeta circ v) = zeta circ (u circ v)$



It is easy to see that $circ_zeta$ is an associative operation and that the semigroup $M_zeta$ also satisfies property $text{P-1}$.



I can think of several other properties of $M$ that would also hold true for $M_zeta$.




Is there any developed theory that analyzes these induced algebraic
structures?



Any answers that contain books/papers as well any results would be
helpful.











share|cite|improve this question





























    3














    Let $(M,circ)$ be any semigroup satisfying the following properties:



    P-1: $text{For every } x,y,z in M text{, if } z circ x = z circ y , text{ then } , x = y$.



    If $zeta in M$ we define $M_zeta = {m in M ; | ; m = zeta circ u}$.



    We can define a binary operation $circ_zeta$ on $M_zeta$ as follows:



    $tag 1 (zeta circ u) circ_zeta (zeta circ v) = zeta circ (u circ v)$



    It is easy to see that $circ_zeta$ is an associative operation and that the semigroup $M_zeta$ also satisfies property $text{P-1}$.



    I can think of several other properties of $M$ that would also hold true for $M_zeta$.




    Is there any developed theory that analyzes these induced algebraic
    structures?



    Any answers that contain books/papers as well any results would be
    helpful.











    share|cite|improve this question



























      3












      3








      3


      1





      Let $(M,circ)$ be any semigroup satisfying the following properties:



      P-1: $text{For every } x,y,z in M text{, if } z circ x = z circ y , text{ then } , x = y$.



      If $zeta in M$ we define $M_zeta = {m in M ; | ; m = zeta circ u}$.



      We can define a binary operation $circ_zeta$ on $M_zeta$ as follows:



      $tag 1 (zeta circ u) circ_zeta (zeta circ v) = zeta circ (u circ v)$



      It is easy to see that $circ_zeta$ is an associative operation and that the semigroup $M_zeta$ also satisfies property $text{P-1}$.



      I can think of several other properties of $M$ that would also hold true for $M_zeta$.




      Is there any developed theory that analyzes these induced algebraic
      structures?



      Any answers that contain books/papers as well any results would be
      helpful.











      share|cite|improve this question















      Let $(M,circ)$ be any semigroup satisfying the following properties:



      P-1: $text{For every } x,y,z in M text{, if } z circ x = z circ y , text{ then } , x = y$.



      If $zeta in M$ we define $M_zeta = {m in M ; | ; m = zeta circ u}$.



      We can define a binary operation $circ_zeta$ on $M_zeta$ as follows:



      $tag 1 (zeta circ u) circ_zeta (zeta circ v) = zeta circ (u circ v)$



      It is easy to see that $circ_zeta$ is an associative operation and that the semigroup $M_zeta$ also satisfies property $text{P-1}$.



      I can think of several other properties of $M$ that would also hold true for $M_zeta$.




      Is there any developed theory that analyzes these induced algebraic
      structures?



      Any answers that contain books/papers as well any results would be
      helpful.








      abstract-algebra reference-request soft-question book-recommendation semigroups






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Nov 18 '18 at 2:56









      Shaun

      8,805113680




      8,805113680










      asked Nov 18 '18 at 2:35









      CopyPasteIt

      4,0451627




      4,0451627






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Since the map $umapstozetacirc u$ is an injection with range $M_zeta$, we actually get a bijection $Mto M_zeta$, and you just pulled over the semigroup operation of $M$.

          Note that we could have done it with any other bijection $phi:Mto N$, by defining $acirc_N b:=phi^{-1}(a)circ_Mphi^{-1}(b)$.

          Consequently, as semigroups, $M$ and $M_zeta$ are isomorphic.






          share|cite|improve this answer





















          • Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
            – Berci
            Nov 21 '18 at 0:34











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3003080%2finduced-semigroup-structures-via-left-translation%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Since the map $umapstozetacirc u$ is an injection with range $M_zeta$, we actually get a bijection $Mto M_zeta$, and you just pulled over the semigroup operation of $M$.

          Note that we could have done it with any other bijection $phi:Mto N$, by defining $acirc_N b:=phi^{-1}(a)circ_Mphi^{-1}(b)$.

          Consequently, as semigroups, $M$ and $M_zeta$ are isomorphic.






          share|cite|improve this answer





















          • Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
            – Berci
            Nov 21 '18 at 0:34
















          1














          Since the map $umapstozetacirc u$ is an injection with range $M_zeta$, we actually get a bijection $Mto M_zeta$, and you just pulled over the semigroup operation of $M$.

          Note that we could have done it with any other bijection $phi:Mto N$, by defining $acirc_N b:=phi^{-1}(a)circ_Mphi^{-1}(b)$.

          Consequently, as semigroups, $M$ and $M_zeta$ are isomorphic.






          share|cite|improve this answer





















          • Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
            – Berci
            Nov 21 '18 at 0:34














          1












          1








          1






          Since the map $umapstozetacirc u$ is an injection with range $M_zeta$, we actually get a bijection $Mto M_zeta$, and you just pulled over the semigroup operation of $M$.

          Note that we could have done it with any other bijection $phi:Mto N$, by defining $acirc_N b:=phi^{-1}(a)circ_Mphi^{-1}(b)$.

          Consequently, as semigroups, $M$ and $M_zeta$ are isomorphic.






          share|cite|improve this answer












          Since the map $umapstozetacirc u$ is an injection with range $M_zeta$, we actually get a bijection $Mto M_zeta$, and you just pulled over the semigroup operation of $M$.

          Note that we could have done it with any other bijection $phi:Mto N$, by defining $acirc_N b:=phi^{-1}(a)circ_Mphi^{-1}(b)$.

          Consequently, as semigroups, $M$ and $M_zeta$ are isomorphic.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 21 '18 at 0:30









          Berci

          59.7k23672




          59.7k23672












          • Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
            – Berci
            Nov 21 '18 at 0:34


















          • Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
            – Berci
            Nov 21 '18 at 0:34
















          Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
          – Berci
          Nov 21 '18 at 0:34




          Nevertheless, I've seen very similar and useful (!) ideas in e.g. functional analysis, defining a new inner product on the range of certain operators..
          – Berci
          Nov 21 '18 at 0:34


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.





          Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


          Please pay close attention to the following guidance:


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3003080%2finduced-semigroup-structures-via-left-translation%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          'app-layout' is not a known element: how to share Component with different Modules

          android studio warns about leanback feature tag usage required on manifest while using Unity exported app?

          WPF add header to Image with URL pettitions [duplicate]