E[(X+Y)^3], where X follows exponential distribution with a, and Y follows exponential distribution with b.
$begingroup$
First, of all, forgive my English terminology. If you need any clarification let me know.
I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.
Also, how can I find φ(x+y)(t)?
probability probability-theory probability-distributions
$endgroup$
add a comment |
$begingroup$
First, of all, forgive my English terminology. If you need any clarification let me know.
I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.
Also, how can I find φ(x+y)(t)?
probability probability-theory probability-distributions
$endgroup$
1
$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20
$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31
$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34
$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39
1
$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00
add a comment |
$begingroup$
First, of all, forgive my English terminology. If you need any clarification let me know.
I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.
Also, how can I find φ(x+y)(t)?
probability probability-theory probability-distributions
$endgroup$
First, of all, forgive my English terminology. If you need any clarification let me know.
I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.
Also, how can I find φ(x+y)(t)?
probability probability-theory probability-distributions
probability probability-theory probability-distributions
asked Jan 20 at 21:03
Nikos GavraNikos Gavra
11
11
1
$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20
$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31
$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34
$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39
1
$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00
add a comment |
1
$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20
$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31
$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34
$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39
1
$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00
1
1
$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20
$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20
$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31
$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31
$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34
$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34
$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39
$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39
1
1
$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00
$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3081126%2fexy3-where-x-follows-exponential-distribution-with-a-and-y-follows-expon%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3081126%2fexy3-where-x-follows-exponential-distribution-with-a-and-y-follows-expon%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20
$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31
$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34
$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39
1
$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00