E[(X+Y)^3], where X follows exponential distribution with a, and Y follows exponential distribution with b.












0












$begingroup$


First, of all, forgive my English terminology. If you need any clarification let me know.



I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.



Also, how can I find φ(x+y)(t)?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
    $endgroup$
    – angryavian
    Jan 20 at 21:20










  • $begingroup$
    Can you help me calculate E[X^3]? I'm not good with integrals.
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:31










  • $begingroup$
    Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
    $endgroup$
    – angryavian
    Jan 20 at 22:34










  • $begingroup$
    I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:39






  • 1




    $begingroup$
    $lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
    $endgroup$
    – angryavian
    Jan 20 at 23:00
















0












$begingroup$


First, of all, forgive my English terminology. If you need any clarification let me know.



I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.



Also, how can I find φ(x+y)(t)?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
    $endgroup$
    – angryavian
    Jan 20 at 21:20










  • $begingroup$
    Can you help me calculate E[X^3]? I'm not good with integrals.
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:31










  • $begingroup$
    Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
    $endgroup$
    – angryavian
    Jan 20 at 22:34










  • $begingroup$
    I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:39






  • 1




    $begingroup$
    $lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
    $endgroup$
    – angryavian
    Jan 20 at 23:00














0












0








0





$begingroup$


First, of all, forgive my English terminology. If you need any clarification let me know.



I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.



Also, how can I find φ(x+y)(t)?










share|cite|improve this question









$endgroup$




First, of all, forgive my English terminology. If you need any clarification let me know.



I do understand how E[X+Y] is calculated into E[X]+E[Y], but I'm having trouble when it is ^3.



Also, how can I find φ(x+y)(t)?







probability probability-theory probability-distributions






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 20 at 21:03









Nikos GavraNikos Gavra

11




11








  • 1




    $begingroup$
    1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
    $endgroup$
    – angryavian
    Jan 20 at 21:20










  • $begingroup$
    Can you help me calculate E[X^3]? I'm not good with integrals.
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:31










  • $begingroup$
    Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
    $endgroup$
    – angryavian
    Jan 20 at 22:34










  • $begingroup$
    I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:39






  • 1




    $begingroup$
    $lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
    $endgroup$
    – angryavian
    Jan 20 at 23:00














  • 1




    $begingroup$
    1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
    $endgroup$
    – angryavian
    Jan 20 at 21:20










  • $begingroup$
    Can you help me calculate E[X^3]? I'm not good with integrals.
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:31










  • $begingroup$
    Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
    $endgroup$
    – angryavian
    Jan 20 at 22:34










  • $begingroup$
    I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
    $endgroup$
    – Nikos Gavra
    Jan 20 at 22:39






  • 1




    $begingroup$
    $lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
    $endgroup$
    – angryavian
    Jan 20 at 23:00








1




1




$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20




$begingroup$
1. You haven't mentioned the dependence between $X$ and $Y$. (Are they independent?) 2. If they are independent, you can write $E[(X+Y)^3] = E[X^3] + 3 E[X^2] E[Y] + 3 E[X] E[Y^2] + E[Y^3]$ and compute each expectation individually. 3. Compute the expectation $phi_{X+Y}(t) = E[e^{i(X+Y) t}]$ directly.
$endgroup$
– angryavian
Jan 20 at 21:20












$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31




$begingroup$
Can you help me calculate E[X^3]? I'm not good with integrals.
$endgroup$
– Nikos Gavra
Jan 20 at 22:31












$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34




$begingroup$
Start with $int_0^infty x^3 a e^{-a x} , dx$ and do integration by parts three times. (Alternatively if you recognize the Gamma distribution you can avoid doing integration by parts.)
$endgroup$
– angryavian
Jan 20 at 22:34












$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39




$begingroup$
I did, but after the first integration by parts, I need to calculate [-x^3 * e^(-ax)] from 0 to oo, which if I'm not wrong, can't be calculated do to the oo. (forgive me again for the symbols I use, I'm not accustomed to it)
$endgroup$
– Nikos Gavra
Jan 20 at 22:39




1




1




$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00




$begingroup$
$lim_{x to infty} x^3 e^{-ax} = 0$. You should review how to compute $E[X]$ and $text{Var}(X)$ if you are uncomfortable with these computations.
$endgroup$
– angryavian
Jan 20 at 23:00










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