Every finite Borel Measure on a complete separable Metric Space is tight












0












$begingroup$


I'm trying to understand the proof of the Theorem in the title which I found here
https://www.math.leidenuniv.nl/~vangaans/jancol1.pdf. (Theorem 2.6)
The proof is very good in my opinion however I don't understand why he can choose
$bigcup _{ }^{ infty }{ B({ a }_{ n, }delta )=X } $ in the 4th line.
If I'm not fully mistaken, it doesn't hold in general that every complete metric space can be represented as a union of open balls.
Could someone explain to me why he is allowed to make such a choice?










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just as a comment, the title of your question is misleading. Your problem is entirely about topology.
    $endgroup$
    – alexp9
    Jan 20 at 20:18
















0












$begingroup$


I'm trying to understand the proof of the Theorem in the title which I found here
https://www.math.leidenuniv.nl/~vangaans/jancol1.pdf. (Theorem 2.6)
The proof is very good in my opinion however I don't understand why he can choose
$bigcup _{ }^{ infty }{ B({ a }_{ n, }delta )=X } $ in the 4th line.
If I'm not fully mistaken, it doesn't hold in general that every complete metric space can be represented as a union of open balls.
Could someone explain to me why he is allowed to make such a choice?










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just as a comment, the title of your question is misleading. Your problem is entirely about topology.
    $endgroup$
    – alexp9
    Jan 20 at 20:18














0












0








0





$begingroup$


I'm trying to understand the proof of the Theorem in the title which I found here
https://www.math.leidenuniv.nl/~vangaans/jancol1.pdf. (Theorem 2.6)
The proof is very good in my opinion however I don't understand why he can choose
$bigcup _{ }^{ infty }{ B({ a }_{ n, }delta )=X } $ in the 4th line.
If I'm not fully mistaken, it doesn't hold in general that every complete metric space can be represented as a union of open balls.
Could someone explain to me why he is allowed to make such a choice?










share|cite|improve this question











$endgroup$




I'm trying to understand the proof of the Theorem in the title which I found here
https://www.math.leidenuniv.nl/~vangaans/jancol1.pdf. (Theorem 2.6)
The proof is very good in my opinion however I don't understand why he can choose
$bigcup _{ }^{ infty }{ B({ a }_{ n, }delta )=X } $ in the 4th line.
If I'm not fully mistaken, it doesn't hold in general that every complete metric space can be represented as a union of open balls.
Could someone explain to me why he is allowed to make such a choice?







real-analysis






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 20 at 20:05









Bernard

122k740116




122k740116










asked Jan 20 at 19:54









MasterPIMasterPI

21828




21828












  • $begingroup$
    Just as a comment, the title of your question is misleading. Your problem is entirely about topology.
    $endgroup$
    – alexp9
    Jan 20 at 20:18


















  • $begingroup$
    Just as a comment, the title of your question is misleading. Your problem is entirely about topology.
    $endgroup$
    – alexp9
    Jan 20 at 20:18
















$begingroup$
Just as a comment, the title of your question is misleading. Your problem is entirely about topology.
$endgroup$
– alexp9
Jan 20 at 20:18




$begingroup$
Just as a comment, the title of your question is misleading. Your problem is entirely about topology.
$endgroup$
– alexp9
Jan 20 at 20:18










1 Answer
1






active

oldest

votes


















1












$begingroup$

Since it's a metric space, the open balls are well defined. In particular, they exist and $B(a_{n},delta)subset X$ holds. This implies that $bigcup_{i}B(a_{i},delta)subset X.$



Now take $xin X$. Since the sequence of points ${a_{n}}_{ninmathbb{N}}$ is dense in X, $exists iinmathbb{N}$ such that $d(a_{i},x)<frac{delta}{2}$. In particular, $xin B(a_{i},delta)$. Since $xin X$ was arbitrary, we conclude that $Xsubset bigcup_{i} B(a_{i},delta)$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thanks I get it! actually pretty easy
    $endgroup$
    – MasterPI
    Jan 20 at 20:26











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3081070%2fevery-finite-borel-measure-on-a-complete-separable-metric-space-is-tight%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

Since it's a metric space, the open balls are well defined. In particular, they exist and $B(a_{n},delta)subset X$ holds. This implies that $bigcup_{i}B(a_{i},delta)subset X.$



Now take $xin X$. Since the sequence of points ${a_{n}}_{ninmathbb{N}}$ is dense in X, $exists iinmathbb{N}$ such that $d(a_{i},x)<frac{delta}{2}$. In particular, $xin B(a_{i},delta)$. Since $xin X$ was arbitrary, we conclude that $Xsubset bigcup_{i} B(a_{i},delta)$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thanks I get it! actually pretty easy
    $endgroup$
    – MasterPI
    Jan 20 at 20:26
















1












$begingroup$

Since it's a metric space, the open balls are well defined. In particular, they exist and $B(a_{n},delta)subset X$ holds. This implies that $bigcup_{i}B(a_{i},delta)subset X.$



Now take $xin X$. Since the sequence of points ${a_{n}}_{ninmathbb{N}}$ is dense in X, $exists iinmathbb{N}$ such that $d(a_{i},x)<frac{delta}{2}$. In particular, $xin B(a_{i},delta)$. Since $xin X$ was arbitrary, we conclude that $Xsubset bigcup_{i} B(a_{i},delta)$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thanks I get it! actually pretty easy
    $endgroup$
    – MasterPI
    Jan 20 at 20:26














1












1








1





$begingroup$

Since it's a metric space, the open balls are well defined. In particular, they exist and $B(a_{n},delta)subset X$ holds. This implies that $bigcup_{i}B(a_{i},delta)subset X.$



Now take $xin X$. Since the sequence of points ${a_{n}}_{ninmathbb{N}}$ is dense in X, $exists iinmathbb{N}$ such that $d(a_{i},x)<frac{delta}{2}$. In particular, $xin B(a_{i},delta)$. Since $xin X$ was arbitrary, we conclude that $Xsubset bigcup_{i} B(a_{i},delta)$.






share|cite|improve this answer









$endgroup$



Since it's a metric space, the open balls are well defined. In particular, they exist and $B(a_{n},delta)subset X$ holds. This implies that $bigcup_{i}B(a_{i},delta)subset X.$



Now take $xin X$. Since the sequence of points ${a_{n}}_{ninmathbb{N}}$ is dense in X, $exists iinmathbb{N}$ such that $d(a_{i},x)<frac{delta}{2}$. In particular, $xin B(a_{i},delta)$. Since $xin X$ was arbitrary, we conclude that $Xsubset bigcup_{i} B(a_{i},delta)$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jan 20 at 20:17









alexp9alexp9

454314




454314












  • $begingroup$
    Thanks I get it! actually pretty easy
    $endgroup$
    – MasterPI
    Jan 20 at 20:26


















  • $begingroup$
    Thanks I get it! actually pretty easy
    $endgroup$
    – MasterPI
    Jan 20 at 20:26
















$begingroup$
Thanks I get it! actually pretty easy
$endgroup$
– MasterPI
Jan 20 at 20:26




$begingroup$
Thanks I get it! actually pretty easy
$endgroup$
– MasterPI
Jan 20 at 20:26


















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3081070%2fevery-finite-borel-measure-on-a-complete-separable-metric-space-is-tight%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

'app-layout' is not a known element: how to share Component with different Modules

android studio warns about leanback feature tag usage required on manifest while using Unity exported app?

WPF add header to Image with URL pettitions [duplicate]