Mixing
find repeated values in an array and print them to list view in android
0
I am new in android and I am trying to get the duplicate values in an array list. I have searched over the internet but I got nothing.
My project has two array lists one is for numbers and the second one is for displaying them. And if the first array list contains a duplicate values, the second one will display all the values and the duplicate ones will be displayed with a stars to mark them as a duplicate values.
So I have tried the following code but I have got nothing. In this situation, array list contains [9,9,5,7].
The problem is I do not get what I need, here is my code.
Note that: arrayList object that contains the numbers, array object will display them.. So any help on this?
arrayList.add(Integer.valueOf(students.getSeatnum()));
array.add(students.getStuden_name() + ", Student " + students.getStudent_id() + ", Seat Num: " + students.getSeatnum());
Set<Integer> seenValues = new HashSet();
for(Integer value: arrayList) {
if(seenValues.contains(value)) {
array.add(students.getStuden_name() + ", Student " + students. getStudent_id() + ", Seat Num: " + students.getSeatnum()+ "****");
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
} else {
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
}
}
android arraylist edited Jan 2 at 19:45
mariusd96
955
asked Jan 2 at 15:31
SawsanSawsan
125
add a comment |
0
I am new in android and I am trying to get the duplicate values in an array list. I have searched over the internet but I got nothing.
My project has two array lists one is for numbers and the second one is for displaying them. And if the first array list contains a duplicate values, the second one will display all the values and the duplicate ones will be displayed with a stars to mark them as a duplicate values.
So I have tried the following code but I have got nothing. In this situation, array list contains [9,9,5,7].
The problem is I do not get what I need, here is my code.
Note that: arrayList object that contains the numbers, array object will display them.. So any help on this?
arrayList.add(Integer.valueOf(students.getSeatnum()));
array.add(students.getStuden_name() + ", Student " + students.getStudent_id() + ", Seat Num: " + students.getSeatnum());
Set<Integer> seenValues = new HashSet();
for(Integer value: arrayList) {
if(seenValues.contains(value)) {
array.add(students.getStuden_name() + ", Student " + students. getStudent_id() + ", Seat Num: " + students.getSeatnum()+ "****");
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
} else {
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
}
}
edited Jan 2 at 19:45
mariusd96
955
asked Jan 2 at 15:31
SawsanSawsan
125
add a comment |
0
0
0
I am new in android and I am trying to get the duplicate values in an array list. I have searched over the internet but I got nothing.
My project has two array lists one is for numbers and the second one is for displaying them. And if the first array list contains a duplicate values, the second one will display all the values and the duplicate ones will be displayed with a stars to mark them as a duplicate values.
So I have tried the following code but I have got nothing. In this situation, array list contains [9,9,5,7].
The problem is I do not get what I need, here is my code.
Note that: arrayList object that contains the numbers, array object will display them.. So any help on this?
arrayList.add(Integer.valueOf(students.getSeatnum()));
array.add(students.getStuden_name() + ", Student " + students.getStudent_id() + ", Seat Num: " + students.getSeatnum());
Set<Integer> seenValues = new HashSet();
for(Integer value: arrayList) {
if(seenValues.contains(value)) {
array.add(students.getStuden_name() + ", Student " + students. getStudent_id() + ", Seat Num: " + students.getSeatnum()+ "****");
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
} else {
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
}
}
edited Jan 2 at 19:45
mariusd96
955
asked Jan 2 at 15:31
SawsanSawsan
125
I am new in android and I am trying to get the duplicate values in an array list. I have searched over the internet but I got nothing.
My project has two array lists one is for numbers and the second one is for displaying them. And if the first array list contains a duplicate values, the second one will display all the values and the duplicate ones will be displayed with a stars to mark them as a duplicate values.
So I have tried the following code but I have got nothing. In this situation, array list contains [9,9,5,7].
The problem is I do not get what I need, here is my code.
Note that: arrayList object that contains the numbers, array object will display them.. So any help on this?
arrayList.add(Integer.valueOf(students.getSeatnum()));
array.add(students.getStuden_name() + ", Student " + students.getStudent_id() + ", Seat Num: " + students.getSeatnum());
Set<Integer> seenValues = new HashSet();
for(Integer value: arrayList) {
if(seenValues.contains(value)) {
array.add(students.getStuden_name() + ", Student " + students. getStudent_id() + ", Seat Num: " + students.getSeatnum()+ "****");
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
} else {
adapter = new ArrayAdapter<String>(StudentInfo.this, android.R.layout.simple_list_item_1, array);
listView.setAdapter(adapter);
}
}
edited Jan 2 at 19:45
mariusd96
955
asked Jan 2 at 15:31
SawsanSawsan
125
edited Jan 2 at 19:45
mariusd96
955
asked Jan 2 at 15:31
SawsanSawsan
125
edited Jan 2 at 19:45
mariusd96
955
edited Jan 2 at 19:45
mariusd96
955
edited Jan 2 at 19:45
mariusd96
955
955
asked Jan 2 at 15:31
SawsanSawsan
125
asked Jan 2 at 15:31
SawsanSawsan
125
asked Jan 2 at 15:31
SawsanSawsan
125
125
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
Create an Adapter which accepts arrayList you have created.
Assuming you are using ListView from your variable name convention.
public class MySimpleArrayAdapter extends ArrayAdapter<String> {
private final Context context;
private final List<String> values;
public MySimpleArrayAdapter(Context context, List<String> values) {
super(context, -1, values);
this.context = context;
this.values = values;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context. getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(R.layout.rowlayout, parent, false);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(values.get(position));
return rowView;
}
}
Your method will look like this
ArrayList<String> array = new ArrayList<>();
Map<Integer,Integer> seenValues = new HashMap<>();
int i=0;
for(int value : arrayList){
if(seenValues.containsKey(value)){
if(seenValues.get(value) !=-1){
array.set(seenValues.get(value), String.valueOf(value) + "*");
seenValues.put(value,-1);
}
array.add(String.valueOf(value)+"*");
}else{
array.add(String.valueOf(value));
seenValues.put(value,i);
}
i++;
}
MySimpleArrayAdapter adapter = new adapter(context,array);
setListAdapter(adapter);
answered Jan 2 at 16:40
vinay kantvinay kant
564
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occurjava.lang.IndexOutOfBoundsException: Index: 9, Size: 0in lineseenValues.add(value, array.size()-1);
– Sawsan
Jan 2 at 18:41
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
|
show 1 more comment
0
You can do it this way:
public class Test {
List<Integer> digits ;
List<String> digitsWatch;
public Test() {
digits = Arrays.asList(9,9,9,5,7,3,3);
digitsWatch = new ArrayList<>(digits.size());
// copying your array
for (int i = 0; i < digits.size(); i++) {
digitsWatch.add(digits.get(i).toString());
}
//filtred values
boolean hasDublicaqtes = false;
for (int i = 0; i < digits.size() -1 ; i++) {
for (int j = i +1; j < digits.size() ; j++) {
if(digitsWatch.get(j).equals(digits.get(i).toString()) ) {
hasDublicaqtes = true;
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(j,tmp);
}
}
if(hasDublicaqtes) {
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(i,tmp);
}
hasDublicaqtes = false;
}
}
}
Maybe it's not an optimal way but it works!
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Create an Adapter which accepts arrayList you have created.
Assuming you are using ListView from your variable name convention.
public class MySimpleArrayAdapter extends ArrayAdapter<String> {
private final Context context;
private final List<String> values;
public MySimpleArrayAdapter(Context context, List<String> values) {
super(context, -1, values);
this.context = context;
this.values = values;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context. getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(R.layout.rowlayout, parent, false);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(values.get(position));
return rowView;
}
}
Your method will look like this
ArrayList<String> array = new ArrayList<>();
Map<Integer,Integer> seenValues = new HashMap<>();
int i=0;
for(int value : arrayList){
if(seenValues.containsKey(value)){
if(seenValues.get(value) !=-1){
array.set(seenValues.get(value), String.valueOf(value) + "*");
seenValues.put(value,-1);
}
array.add(String.valueOf(value)+"*");
}else{
array.add(String.valueOf(value));
seenValues.put(value,i);
}
i++;
}
MySimpleArrayAdapter adapter = new adapter(context,array);
setListAdapter(adapter);
answered Jan 2 at 16:40
vinay kantvinay kant
564
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occurjava.lang.IndexOutOfBoundsException: Index: 9, Size: 0in lineseenValues.add(value, array.size()-1);
– Sawsan
Jan 2 at 18:41
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
|
show 1 more comment
1
Create an Adapter which accepts arrayList you have created.
Assuming you are using ListView from your variable name convention.
public class MySimpleArrayAdapter extends ArrayAdapter<String> {
private final Context context;
private final List<String> values;
public MySimpleArrayAdapter(Context context, List<String> values) {
super(context, -1, values);
this.context = context;
this.values = values;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context. getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(R.layout.rowlayout, parent, false);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(values.get(position));
return rowView;
}
}
Your method will look like this
ArrayList<String> array = new ArrayList<>();
Map<Integer,Integer> seenValues = new HashMap<>();
int i=0;
for(int value : arrayList){
if(seenValues.containsKey(value)){
if(seenValues.get(value) !=-1){
array.set(seenValues.get(value), String.valueOf(value) + "*");
seenValues.put(value,-1);
}
array.add(String.valueOf(value)+"*");
}else{
array.add(String.valueOf(value));
seenValues.put(value,i);
}
i++;
}
MySimpleArrayAdapter adapter = new adapter(context,array);
setListAdapter(adapter);
answered Jan 2 at 16:40
vinay kantvinay kant
564
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occurjava.lang.IndexOutOfBoundsException: Index: 9, Size: 0in lineseenValues.add(value, array.size()-1);
– Sawsan
Jan 2 at 18:41
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
|
show 1 more comment
1
1
1
Create an Adapter which accepts arrayList you have created.
Assuming you are using ListView from your variable name convention.
public class MySimpleArrayAdapter extends ArrayAdapter<String> {
private final Context context;
private final List<String> values;
public MySimpleArrayAdapter(Context context, List<String> values) {
super(context, -1, values);
this.context = context;
this.values = values;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context. getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(R.layout.rowlayout, parent, false);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(values.get(position));
return rowView;
}
}
Your method will look like this
ArrayList<String> array = new ArrayList<>();
Map<Integer,Integer> seenValues = new HashMap<>();
int i=0;
for(int value : arrayList){
if(seenValues.containsKey(value)){
if(seenValues.get(value) !=-1){
array.set(seenValues.get(value), String.valueOf(value) + "*");
seenValues.put(value,-1);
}
array.add(String.valueOf(value)+"*");
}else{
array.add(String.valueOf(value));
seenValues.put(value,i);
}
i++;
}
MySimpleArrayAdapter adapter = new adapter(context,array);
setListAdapter(adapter);
answered Jan 2 at 16:40
vinay kantvinay kant
564
Create an Adapter which accepts arrayList you have created.
Assuming you are using ListView from your variable name convention.
public class MySimpleArrayAdapter extends ArrayAdapter<String> {
private final Context context;
private final List<String> values;
public MySimpleArrayAdapter(Context context, List<String> values) {
super(context, -1, values);
this.context = context;
this.values = values;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context. getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(R.layout.rowlayout, parent, false);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(values.get(position));
return rowView;
}
}
Your method will look like this
ArrayList<String> array = new ArrayList<>();
Map<Integer,Integer> seenValues = new HashMap<>();
int i=0;
for(int value : arrayList){
if(seenValues.containsKey(value)){
if(seenValues.get(value) !=-1){
array.set(seenValues.get(value), String.valueOf(value) + "*");
seenValues.put(value,-1);
}
array.add(String.valueOf(value)+"*");
}else{
array.add(String.valueOf(value));
seenValues.put(value,i);
}
i++;
}
MySimpleArrayAdapter adapter = new adapter(context,array);
setListAdapter(adapter);
answered Jan 2 at 16:40
vinay kantvinay kant
564
edited Jan 3 at 4:07
answered Jan 2 at 16:40
vinay kantvinay kant
564
answered Jan 2 at 16:40
vinay kantvinay kant
564
answered Jan 2 at 16:40
vinay kantvinay kant
564
564
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occurjava.lang.IndexOutOfBoundsException: Index: 9, Size: 0in lineseenValues.add(value, array.size()-1);
– Sawsan
Jan 2 at 18:41
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
|
show 1 more comment
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occurjava.lang.IndexOutOfBoundsException: Index: 9, Size: 0in lineseenValues.add(value, array.size()-1);
– Sawsan
Jan 2 at 18:41
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
it returned every element in array list 4 times!!!!! :(
– Sawsan
Jan 2 at 17:21
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
Let me clearly understand what you need.. [9,9,9,7,4,3,3] ----> [9*,7,4,3*] or [9,9,9,7,4,3,3] ----> [9*,3*]
– vinay kant
Jan 2 at 18:02
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
The above code will work @Sawsan. I have edited it for your use case.
– vinay kant
Jan 2 at 18:08
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occur
java.lang.IndexOutOfBoundsException: Index: 9, Size: 0 in line seenValues.add(value, array.size()-1);– Sawsan
Jan 2 at 18:41
What i need is: [9,9,9,7,4,3,3] ------> [9*,9*,9*,7,4,3*,3*]. So I tried your suggestion but it gives me an error, tried to solve it but no results occur
java.lang.IndexOutOfBoundsException: Index: 9, Size: 0 in line seenValues.add(value, array.size()-1);– Sawsan
Jan 2 at 18:41
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
sorry for so many edits, but this edit will definitely work as per your requirements and it is O(n) solution. @Sawsan
– vinay kant
Jan 3 at 4:08
|
show 1 more comment
0
You can do it this way:
public class Test {
List<Integer> digits ;
List<String> digitsWatch;
public Test() {
digits = Arrays.asList(9,9,9,5,7,3,3);
digitsWatch = new ArrayList<>(digits.size());
// copying your array
for (int i = 0; i < digits.size(); i++) {
digitsWatch.add(digits.get(i).toString());
}
//filtred values
boolean hasDublicaqtes = false;
for (int i = 0; i < digits.size() -1 ; i++) {
for (int j = i +1; j < digits.size() ; j++) {
if(digitsWatch.get(j).equals(digits.get(i).toString()) ) {
hasDublicaqtes = true;
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(j,tmp);
}
}
if(hasDublicaqtes) {
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(i,tmp);
}
hasDublicaqtes = false;
}
}
}
Maybe it's not an optimal way but it works!
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
add a comment |
0
You can do it this way:
public class Test {
List<Integer> digits ;
List<String> digitsWatch;
public Test() {
digits = Arrays.asList(9,9,9,5,7,3,3);
digitsWatch = new ArrayList<>(digits.size());
// copying your array
for (int i = 0; i < digits.size(); i++) {
digitsWatch.add(digits.get(i).toString());
}
//filtred values
boolean hasDublicaqtes = false;
for (int i = 0; i < digits.size() -1 ; i++) {
for (int j = i +1; j < digits.size() ; j++) {
if(digitsWatch.get(j).equals(digits.get(i).toString()) ) {
hasDublicaqtes = true;
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(j,tmp);
}
}
if(hasDublicaqtes) {
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(i,tmp);
}
hasDublicaqtes = false;
}
}
}
Maybe it's not an optimal way but it works!
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
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You can do it this way:
public class Test {
List<Integer> digits ;
List<String> digitsWatch;
public Test() {
digits = Arrays.asList(9,9,9,5,7,3,3);
digitsWatch = new ArrayList<>(digits.size());
// copying your array
for (int i = 0; i < digits.size(); i++) {
digitsWatch.add(digits.get(i).toString());
}
//filtred values
boolean hasDublicaqtes = false;
for (int i = 0; i < digits.size() -1 ; i++) {
for (int j = i +1; j < digits.size() ; j++) {
if(digitsWatch.get(j).equals(digits.get(i).toString()) ) {
hasDublicaqtes = true;
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(j,tmp);
}
}
if(hasDublicaqtes) {
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(i,tmp);
}
hasDublicaqtes = false;
}
}
}
Maybe it's not an optimal way but it works!
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
You can do it this way:
public class Test {
List<Integer> digits ;
List<String> digitsWatch;
public Test() {
digits = Arrays.asList(9,9,9,5,7,3,3);
digitsWatch = new ArrayList<>(digits.size());
// copying your array
for (int i = 0; i < digits.size(); i++) {
digitsWatch.add(digits.get(i).toString());
}
//filtred values
boolean hasDublicaqtes = false;
for (int i = 0; i < digits.size() -1 ; i++) {
for (int j = i +1; j < digits.size() ; j++) {
if(digitsWatch.get(j).equals(digits.get(i).toString()) ) {
hasDublicaqtes = true;
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(j,tmp);
}
}
if(hasDublicaqtes) {
String tmp = digitsWatch.get(i) + "*";
digitsWatch.set(i,tmp);
}
hasDublicaqtes = false;
}
}
}
Maybe it's not an optimal way but it works!
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
edited Jan 2 at 22:12
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
answered Jan 2 at 22:06
Stanislav BaturaStanislav Batura
220110
220110
add a comment |
add a comment |
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