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How to fix row value in a table passed from controller using ajax?
1
I have to pass table value from controller to view using ajax. I am succeeded to pass table value but all the data comes in a same column. I want to show data in row.
I have tried possible cases. Since, this is the first time i am getting this problem, so i request to guide me.
//this is my table code in view:
<table class="report">
<tr>
<th class="report-th"> Module ID </th>
<th class="report-th"> Module Name </th>
<th class="report-th"> Module Status </th>
</tr>
<tr id='values'>
</tr>
//this is my ajax:
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
// console.log(response);
$('#values').html(response);
}
});
});
});
//this is my controller:
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json($html);
}
laravel
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
add a comment |
1
I have to pass table value from controller to view using ajax. I am succeeded to pass table value but all the data comes in a same column. I want to show data in row.
I have tried possible cases. Since, this is the first time i am getting this problem, so i request to guide me.
//this is my table code in view:
<table class="report">
<tr>
<th class="report-th"> Module ID </th>
<th class="report-th"> Module Name </th>
<th class="report-th"> Module Status </th>
</tr>
<tr id='values'>
</tr>
//this is my ajax:
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
// console.log(response);
$('#values').html(response);
}
});
});
});
//this is my controller:
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json($html);
}
laravel
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
add a comment |
1
1
1
I have to pass table value from controller to view using ajax. I am succeeded to pass table value but all the data comes in a same column. I want to show data in row.
I have tried possible cases. Since, this is the first time i am getting this problem, so i request to guide me.
//this is my table code in view:
<table class="report">
<tr>
<th class="report-th"> Module ID </th>
<th class="report-th"> Module Name </th>
<th class="report-th"> Module Status </th>
</tr>
<tr id='values'>
</tr>
//this is my ajax:
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
// console.log(response);
$('#values').html(response);
}
});
});
});
//this is my controller:
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json($html);
}
laravel
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
I have to pass table value from controller to view using ajax. I am succeeded to pass table value but all the data comes in a same column. I want to show data in row.
I have tried possible cases. Since, this is the first time i am getting this problem, so i request to guide me.
//this is my table code in view:
<table class="report">
<tr>
<th class="report-th"> Module ID </th>
<th class="report-th"> Module Name </th>
<th class="report-th"> Module Status </th>
</tr>
<tr id='values'>
</tr>
//this is my ajax:
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
// console.log(response);
$('#values').html(response);
}
});
});
});
//this is my controller:
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json($html);
}
laravel
laravel
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
asked Jan 1 at 7:41
Sagar BasnetSagar Basnet
146
146
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
Your ajax call function,
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
//type instead of method
type: 'GET',
success:function(response){
// console.log(response);
// append instead of html
$('#values').append(response.html);
}
});
});
});
Your Controller,
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json(['success' => true, 'html'=>$html]);
}
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
add a comment |
0
According to your response, Adding a class in the row doesn't solve your problem. You have to use insertAfter()
var $tableRow = $('.report tr');
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
$(response).insertAfter( $tableRow );
}
});
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Your ajax call function,
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
//type instead of method
type: 'GET',
success:function(response){
// console.log(response);
// append instead of html
$('#values').append(response.html);
}
});
});
});
Your Controller,
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json(['success' => true, 'html'=>$html]);
}
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
add a comment |
0
Your ajax call function,
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
//type instead of method
type: 'GET',
success:function(response){
// console.log(response);
// append instead of html
$('#values').append(response.html);
}
});
});
});
Your Controller,
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json(['success' => true, 'html'=>$html]);
}
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
add a comment |
0
0
0
Your ajax call function,
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
//type instead of method
type: 'GET',
success:function(response){
// console.log(response);
// append instead of html
$('#values').append(response.html);
}
});
});
});
Your Controller,
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json(['success' => true, 'html'=>$html]);
}
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
Your ajax call function,
$(function () {
$(".report").click(function () {
var title = $(this).data('title');
var id=$(this).data('id');
$("#project-title").val(title);
$('#project-id').val(id);
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
//type instead of method
type: 'GET',
success:function(response){
// console.log(response);
// append instead of html
$('#values').append(response.html);
}
});
});
});
Your Controller,
public function showajax($id){
$modules= modules::where('project_id',$id)->get();
foreach($modules as $row)
{
$html=
'<td>' . $row->id . '</td>' .
'<td>' . $row->title . '</td>' .
'<td>' . $row->status. '</td>'.
'<br/>';
}
return Response::json(['success' => true, 'html'=>$html]);
}
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
answered Jan 1 at 8:00
Md.Sukel AliMd.Sukel Ali
1,1681716
1,1681716
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
add a comment |
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
thanks for your response sir, I tried it but same problem appeared. It was a simple code error , i just have solved it. Thank you
– Sagar Basnet
Jan 2 at 4:41
add a comment |
0
According to your response, Adding a class in the row doesn't solve your problem. You have to use insertAfter()
var $tableRow = $('.report tr');
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
$(response).insertAfter( $tableRow );
}
});
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
add a comment |
0
According to your response, Adding a class in the row doesn't solve your problem. You have to use insertAfter()
var $tableRow = $('.report tr');
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
$(response).insertAfter( $tableRow );
}
});
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
add a comment |
0
0
0
According to your response, Adding a class in the row doesn't solve your problem. You have to use insertAfter()
var $tableRow = $('.report tr');
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
$(response).insertAfter( $tableRow );
}
});
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
According to your response, Adding a class in the row doesn't solve your problem. You have to use insertAfter()
var $tableRow = $('.report tr');
$.ajax({
url: "{{url('tms/projects/',[null])}}/"+id,
method: 'GET',
success:function(response){
$(response).insertAfter( $tableRow );
}
});
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
answered Jan 1 at 8:13
jogesh_pijogesh_pi
8,04132550
8,04132550
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
add a comment |
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
thank you for your response, bt after using ur suggestion , i am not getting any value. It is showing Uncaught ReferenceError: $tableRow is not defined as a error
– Sagar Basnet
Jan 1 at 9:41
add a comment |
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