In Banach algebra $A$ find an example such hat $e^{a+b} not =e^ae^b$












0












$begingroup$


Let $A$ be a Banach algebra




if $ab=ba$ then we have $e^{a+b}=e^ae^b$




without $ab=ba$, I want to find an example such hat $e^{a+b} not =e^ae^b$



Any help will be greatly appreciated.










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    0












    $begingroup$


    Let $A$ be a Banach algebra




    if $ab=ba$ then we have $e^{a+b}=e^ae^b$




    without $ab=ba$, I want to find an example such hat $e^{a+b} not =e^ae^b$



    Any help will be greatly appreciated.










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Let $A$ be a Banach algebra




      if $ab=ba$ then we have $e^{a+b}=e^ae^b$




      without $ab=ba$, I want to find an example such hat $e^{a+b} not =e^ae^b$



      Any help will be greatly appreciated.










      share|cite|improve this question











      $endgroup$




      Let $A$ be a Banach algebra




      if $ab=ba$ then we have $e^{a+b}=e^ae^b$




      without $ab=ba$, I want to find an example such hat $e^{a+b} not =e^ae^b$



      Any help will be greatly appreciated.







      banach-algebras






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      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Jan 25 at 11:59









      José Carlos Santos

      168k23132236




      168k23132236










      asked Jan 25 at 11:53









      user62498user62498

      1,983714




      1,983714






















          1 Answer
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          $begingroup$

          Hint: In $mathbb{R}^{2times2}$, if $a=left[begin{smallmatrix}0&1\0&0end{smallmatrix}right]$ and $b=left[begin{smallmatrix}0&0\1&0end{smallmatrix}right]$, then what are $e^a$, $e^b$, and $e^{a+b}$?






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          • $begingroup$
            Thanks for your answer
            $endgroup$
            – user62498
            Jan 25 at 12:02











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          1 Answer
          1






          active

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          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$

          Hint: In $mathbb{R}^{2times2}$, if $a=left[begin{smallmatrix}0&1\0&0end{smallmatrix}right]$ and $b=left[begin{smallmatrix}0&0\1&0end{smallmatrix}right]$, then what are $e^a$, $e^b$, and $e^{a+b}$?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thanks for your answer
            $endgroup$
            – user62498
            Jan 25 at 12:02
















          3












          $begingroup$

          Hint: In $mathbb{R}^{2times2}$, if $a=left[begin{smallmatrix}0&1\0&0end{smallmatrix}right]$ and $b=left[begin{smallmatrix}0&0\1&0end{smallmatrix}right]$, then what are $e^a$, $e^b$, and $e^{a+b}$?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thanks for your answer
            $endgroup$
            – user62498
            Jan 25 at 12:02














          3












          3








          3





          $begingroup$

          Hint: In $mathbb{R}^{2times2}$, if $a=left[begin{smallmatrix}0&1\0&0end{smallmatrix}right]$ and $b=left[begin{smallmatrix}0&0\1&0end{smallmatrix}right]$, then what are $e^a$, $e^b$, and $e^{a+b}$?






          share|cite|improve this answer









          $endgroup$



          Hint: In $mathbb{R}^{2times2}$, if $a=left[begin{smallmatrix}0&1\0&0end{smallmatrix}right]$ and $b=left[begin{smallmatrix}0&0\1&0end{smallmatrix}right]$, then what are $e^a$, $e^b$, and $e^{a+b}$?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 25 at 11:56









          José Carlos SantosJosé Carlos Santos

          168k23132236




          168k23132236












          • $begingroup$
            Thanks for your answer
            $endgroup$
            – user62498
            Jan 25 at 12:02


















          • $begingroup$
            Thanks for your answer
            $endgroup$
            – user62498
            Jan 25 at 12:02
















          $begingroup$
          Thanks for your answer
          $endgroup$
          – user62498
          Jan 25 at 12:02




          $begingroup$
          Thanks for your answer
          $endgroup$
          – user62498
          Jan 25 at 12:02


















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