Use Horn formula to prove that it is possible to produce carbonic acid
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I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.
Suppose we have the apparatuses available to perform the following chemical reactions.
$$
MgO + H_2 rightarrow Mg + H_2O\
C + O_2 rightarrow CO_2\
H_2O + CO_2 rightarrow H_2CO_3
$$
Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.
logic satisfiability
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add a comment |
$begingroup$
I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.
Suppose we have the apparatuses available to perform the following chemical reactions.
$$
MgO + H_2 rightarrow Mg + H_2O\
C + O_2 rightarrow CO_2\
H_2O + CO_2 rightarrow H_2CO_3
$$
Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.
logic satisfiability
$endgroup$
add a comment |
$begingroup$
I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.
Suppose we have the apparatuses available to perform the following chemical reactions.
$$
MgO + H_2 rightarrow Mg + H_2O\
C + O_2 rightarrow CO_2\
H_2O + CO_2 rightarrow H_2CO_3
$$
Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.
logic satisfiability
$endgroup$
I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.
Suppose we have the apparatuses available to perform the following chemical reactions.
$$
MgO + H_2 rightarrow Mg + H_2O\
C + O_2 rightarrow CO_2\
H_2O + CO_2 rightarrow H_2CO_3
$$
Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.
logic satisfiability
logic satisfiability
asked Jan 20 at 8:17
nik0la.vrnik0la.vr
375
375
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1 Answer
1
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$begingroup$
Hint
You have already the "basic ingredients"; you have only to formalize them as Horn-clause :
Clauses
1) $lnot MgO lor lnot H_2 lor Mg $
2) $lnot MgO lor lnot H_2 lor H_2O$
3) $lnot C lor lnot O_2 lor CO_2$
4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$
Facts
5) $MgO, H_2, O_2, C$.
Goal
$H_2CO_3$.
Now you can easily check themfor satisfiability.
$endgroup$
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint
You have already the "basic ingredients"; you have only to formalize them as Horn-clause :
Clauses
1) $lnot MgO lor lnot H_2 lor Mg $
2) $lnot MgO lor lnot H_2 lor H_2O$
3) $lnot C lor lnot O_2 lor CO_2$
4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$
Facts
5) $MgO, H_2, O_2, C$.
Goal
$H_2CO_3$.
Now you can easily check themfor satisfiability.
$endgroup$
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
add a comment |
$begingroup$
Hint
You have already the "basic ingredients"; you have only to formalize them as Horn-clause :
Clauses
1) $lnot MgO lor lnot H_2 lor Mg $
2) $lnot MgO lor lnot H_2 lor H_2O$
3) $lnot C lor lnot O_2 lor CO_2$
4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$
Facts
5) $MgO, H_2, O_2, C$.
Goal
$H_2CO_3$.
Now you can easily check themfor satisfiability.
$endgroup$
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
add a comment |
$begingroup$
Hint
You have already the "basic ingredients"; you have only to formalize them as Horn-clause :
Clauses
1) $lnot MgO lor lnot H_2 lor Mg $
2) $lnot MgO lor lnot H_2 lor H_2O$
3) $lnot C lor lnot O_2 lor CO_2$
4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$
Facts
5) $MgO, H_2, O_2, C$.
Goal
$H_2CO_3$.
Now you can easily check themfor satisfiability.
$endgroup$
Hint
You have already the "basic ingredients"; you have only to formalize them as Horn-clause :
Clauses
1) $lnot MgO lor lnot H_2 lor Mg $
2) $lnot MgO lor lnot H_2 lor H_2O$
3) $lnot C lor lnot O_2 lor CO_2$
4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$
Facts
5) $MgO, H_2, O_2, C$.
Goal
$H_2CO_3$.
Now you can easily check themfor satisfiability.
edited Jan 20 at 8:40
answered Jan 20 at 8:29
Mauro ALLEGRANZAMauro ALLEGRANZA
66.8k449115
66.8k449115
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
add a comment |
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
$begingroup$
The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
$endgroup$
– Jean Marie
Jan 20 at 9:29
add a comment |
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