Use Horn formula to prove that it is possible to produce carbonic acid












0












$begingroup$


I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.





Suppose we have the apparatuses available to perform the following chemical reactions.



$$
MgO + H_2 rightarrow Mg + H_2O\
C + O_2 rightarrow CO_2\
H_2O + CO_2 rightarrow H_2CO_3
$$



Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.










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$endgroup$

















    0












    $begingroup$


    I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.





    Suppose we have the apparatuses available to perform the following chemical reactions.



    $$
    MgO + H_2 rightarrow Mg + H_2O\
    C + O_2 rightarrow CO_2\
    H_2O + CO_2 rightarrow H_2CO_3
    $$



    Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.





      Suppose we have the apparatuses available to perform the following chemical reactions.



      $$
      MgO + H_2 rightarrow Mg + H_2O\
      C + O_2 rightarrow CO_2\
      H_2O + CO_2 rightarrow H_2CO_3
      $$



      Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.










      share|cite|improve this question









      $endgroup$




      I don't know how to translate this problem to mathematical logic language. How am I supposed to came up with a Horn formula from this? I should easily be able to test it's satisfiability after that, but I'm stuck at the beginning.





      Suppose we have the apparatuses available to perform the following chemical reactions.



      $$
      MgO + H_2 rightarrow Mg + H_2O\
      C + O_2 rightarrow CO_2\
      H_2O + CO_2 rightarrow H_2CO_3
      $$



      Further, our lab has the following basic materials available: $MgO$, $H_2$, $O_2$ and $C$. Prove (by an appropriate application of the Horn formula algorithm) that under these circumstances it is possible to produce $H_2CO_3$.







      logic satisfiability






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      asked Jan 20 at 8:17









      nik0la.vrnik0la.vr

      375




      375






















          1 Answer
          1






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          oldest

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          1












          $begingroup$

          Hint



          You have already the "basic ingredients"; you have only to formalize them as Horn-clause :



          Clauses



          1) $lnot MgO lor lnot H_2 lor Mg $



          2) $lnot MgO lor lnot H_2 lor H_2O$



          3) $lnot C lor lnot O_2 lor CO_2$



          4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$



          Facts



          5) $MgO, H_2, O_2, C$.



          Goal




          $H_2CO_3$.




          Now you can easily check themfor satisfiability.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
            $endgroup$
            – Jean Marie
            Jan 20 at 9:29













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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1












          $begingroup$

          Hint



          You have already the "basic ingredients"; you have only to formalize them as Horn-clause :



          Clauses



          1) $lnot MgO lor lnot H_2 lor Mg $



          2) $lnot MgO lor lnot H_2 lor H_2O$



          3) $lnot C lor lnot O_2 lor CO_2$



          4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$



          Facts



          5) $MgO, H_2, O_2, C$.



          Goal




          $H_2CO_3$.




          Now you can easily check themfor satisfiability.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
            $endgroup$
            – Jean Marie
            Jan 20 at 9:29


















          1












          $begingroup$

          Hint



          You have already the "basic ingredients"; you have only to formalize them as Horn-clause :



          Clauses



          1) $lnot MgO lor lnot H_2 lor Mg $



          2) $lnot MgO lor lnot H_2 lor H_2O$



          3) $lnot C lor lnot O_2 lor CO_2$



          4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$



          Facts



          5) $MgO, H_2, O_2, C$.



          Goal




          $H_2CO_3$.




          Now you can easily check themfor satisfiability.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
            $endgroup$
            – Jean Marie
            Jan 20 at 9:29
















          1












          1








          1





          $begingroup$

          Hint



          You have already the "basic ingredients"; you have only to formalize them as Horn-clause :



          Clauses



          1) $lnot MgO lor lnot H_2 lor Mg $



          2) $lnot MgO lor lnot H_2 lor H_2O$



          3) $lnot C lor lnot O_2 lor CO_2$



          4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$



          Facts



          5) $MgO, H_2, O_2, C$.



          Goal




          $H_2CO_3$.




          Now you can easily check themfor satisfiability.






          share|cite|improve this answer











          $endgroup$



          Hint



          You have already the "basic ingredients"; you have only to formalize them as Horn-clause :



          Clauses



          1) $lnot MgO lor lnot H_2 lor Mg $



          2) $lnot MgO lor lnot H_2 lor H_2O$



          3) $lnot C lor lnot O_2 lor CO_2$



          4) $lnot H_2O lor lnot CO_2 lor H_2CO_3$



          Facts



          5) $MgO, H_2, O_2, C$.



          Goal




          $H_2CO_3$.




          Now you can easily check themfor satisfiability.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Jan 20 at 8:40

























          answered Jan 20 at 8:29









          Mauro ALLEGRANZAMauro ALLEGRANZA

          66.8k449115




          66.8k449115












          • $begingroup$
            The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
            $endgroup$
            – Jean Marie
            Jan 20 at 9:29




















          • $begingroup$
            The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
            $endgroup$
            – Jean Marie
            Jan 20 at 9:29


















          $begingroup$
          The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
          $endgroup$
          – Jean Marie
          Jan 20 at 9:29






          $begingroup$
          The OP needs maybe to understand that the second clause for example comes from the conversion of $(p land q) to r $ into $lnot (p land q) lor r $ then into $lnot p lor lnot q lor r $
          $endgroup$
          – Jean Marie
          Jan 20 at 9:29




















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