Mixing
Why is the domain of this trig sub using $sec$ from 0 to $frac{pi}{2}$ and from $pi$ to $frac{3pi}{2}$
0
$begingroup$
I am looking at this problem:
and I'm wondering about the domain. Why are we choosing the domain to be 0 to $frac{pi}{2}$ and from $pi$ to $frac{3pi}{2}$ ?
calculus
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
$endgroup$
add a comment |
0
$begingroup$
I am looking at this problem:
and I'm wondering about the domain. Why are we choosing the domain to be 0 to $frac{pi}{2}$ and from $pi$ to $frac{3pi}{2}$ ?
calculus
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
$endgroup$
$begingroup$
Because when $theta=frac{pi} {2} $, $cos (tfrac{pi} {2})=0 $ and we have a $frac10$ situation?
$endgroup$
– Zacky
Jan 26 at 22:54
$begingroup$
But why the domain range? What's wrong with thetas between $pi/2$ and $pi$?
$endgroup$
– Jwan622
Jan 26 at 22:58
$begingroup$
Between $frac{pi}{2}$ and $pi$, $cos theta $ becomes negative and we don't want that under the square root?
$endgroup$
– Zacky
Jan 26 at 23:01
$begingroup$
$cos{theta}$ is negative between $pi$ and $frac{3pi}{2}$ too though
$endgroup$
– Jwan622
Jan 27 at 10:40
$begingroup$
Any updates on this?
$endgroup$
– Jwan622
Feb 2 at 17:03
add a comment |
0
0
0
$begingroup$
I am looking at this problem:
and I'm wondering about the domain. Why are we choosing the domain to be 0 to $frac{pi}{2}$ and from $pi$ to $frac{3pi}{2}$ ?
calculus
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
$endgroup$
I am looking at this problem:
and I'm wondering about the domain. Why are we choosing the domain to be 0 to $frac{pi}{2}$ and from $pi$ to $frac{3pi}{2}$ ?
calculus
calculus
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
asked Jan 26 at 22:24
Jwan622Jwan622
2,28211632
2,28211632
$begingroup$
Because when $theta=frac{pi} {2} $, $cos (tfrac{pi} {2})=0 $ and we have a $frac10$ situation?
$endgroup$
– Zacky
Jan 26 at 22:54
$begingroup$
But why the domain range? What's wrong with thetas between $pi/2$ and $pi$?
$endgroup$
– Jwan622
Jan 26 at 22:58
$begingroup$
Between $frac{pi}{2}$ and $pi$, $cos theta $ becomes negative and we don't want that under the square root?
$endgroup$
– Zacky
Jan 26 at 23:01
$begingroup$
$cos{theta}$ is negative between $pi$ and $frac{3pi}{2}$ too though
$endgroup$
– Jwan622
Jan 27 at 10:40
$begingroup$
Any updates on this?
$endgroup$
– Jwan622
Feb 2 at 17:03
add a comment |
$begingroup$
Because when $theta=frac{pi} {2} $, $cos (tfrac{pi} {2})=0 $ and we have a $frac10$ situation?
$endgroup$
– Zacky
Jan 26 at 22:54
$begingroup$
But why the domain range? What's wrong with thetas between $pi/2$ and $pi$?
$endgroup$
– Jwan622
Jan 26 at 22:58
$begingroup$
Between $frac{pi}{2}$ and $pi$, $cos theta $ becomes negative and we don't want that under the square root?
$endgroup$
– Zacky
Jan 26 at 23:01
$begingroup$
$cos{theta}$ is negative between $pi$ and $frac{3pi}{2}$ too though
$endgroup$
– Jwan622
Jan 27 at 10:40
$begingroup$
Any updates on this?
$endgroup$
– Jwan622
Feb 2 at 17:03
$begingroup$
Because when $theta=frac{pi} {2} $, $cos (tfrac{pi} {2})=0 $ and we have a $frac10$ situation?
$endgroup$
– Zacky
Jan 26 at 22:54
$begingroup$
Because when $theta=frac{pi} {2} $, $cos (tfrac{pi} {2})=0 $ and we have a $frac10$ situation?
$endgroup$
– Zacky
Jan 26 at 22:54
$begingroup$
But why the domain range? What's wrong with thetas between $pi/2$ and $pi$?
$endgroup$
– Jwan622
Jan 26 at 22:58
$begingroup$
But why the domain range? What's wrong with thetas between $pi/2$ and $pi$?
$endgroup$
– Jwan622
Jan 26 at 22:58
$begingroup$
Between $frac{pi}{2}$ and $pi$, $cos theta $ becomes negative and we don't want that under the square root?
$endgroup$
– Zacky
Jan 26 at 23:01
$begingroup$
Between $frac{pi}{2}$ and $pi$, $cos theta $ becomes negative and we don't want that under the square root?
$endgroup$
– Zacky
Jan 26 at 23:01
$begingroup$
$cos{theta}$ is negative between $pi$ and $frac{3pi}{2}$ too though
$endgroup$
– Jwan622
Jan 27 at 10:40
$begingroup$
$cos{theta}$ is negative between $pi$ and $frac{3pi}{2}$ too though
$endgroup$
– Jwan622
Jan 27 at 10:40
$begingroup$
Any updates on this?
$endgroup$
– Jwan622
Feb 2 at 17:03
$begingroup$
Any updates on this?
$endgroup$
– Jwan622
Feb 2 at 17:03
add a comment |
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$begingroup$
Because when $theta=frac{pi} {2} $, $cos (tfrac{pi} {2})=0 $ and we have a $frac10$ situation?
$endgroup$
– Zacky
Jan 26 at 22:54
$begingroup$
But why the domain range? What's wrong with thetas between $pi/2$ and $pi$?
$endgroup$
– Jwan622
Jan 26 at 22:58
$begingroup$
Between $frac{pi}{2}$ and $pi$, $cos theta $ becomes negative and we don't want that under the square root?
$endgroup$
– Zacky
Jan 26 at 23:01
$begingroup$
$cos{theta}$ is negative between $pi$ and $frac{3pi}{2}$ too though
$endgroup$
– Jwan622
Jan 27 at 10:40
$begingroup$
Any updates on this?
$endgroup$
– Jwan622
Feb 2 at 17:03