About clopen set in $mathbb R^n$












-1












$begingroup$


Is there any clopen set in the metric space ($mathbb R^n$,$d$) (where $d$ is the usual metric)



besides $mathbb R^n$ & the empty set?










share|cite|improve this question









$endgroup$

















    -1












    $begingroup$


    Is there any clopen set in the metric space ($mathbb R^n$,$d$) (where $d$ is the usual metric)



    besides $mathbb R^n$ & the empty set?










    share|cite|improve this question









    $endgroup$















      -1












      -1








      -1





      $begingroup$


      Is there any clopen set in the metric space ($mathbb R^n$,$d$) (where $d$ is the usual metric)



      besides $mathbb R^n$ & the empty set?










      share|cite|improve this question









      $endgroup$




      Is there any clopen set in the metric space ($mathbb R^n$,$d$) (where $d$ is the usual metric)



      besides $mathbb R^n$ & the empty set?







      metric-spaces






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Feb 1 at 14:42









      Supriyo BanerjeeSupriyo Banerjee

      1056




      1056






















          2 Answers
          2






          active

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          3












          $begingroup$

          No. If there were such a set $U$, then setting $V = mathbb{R}^n setminus U$, $V$ will also be clopen, so that $mathbb{R}^n = U sqcup V$ is a decomposition of $mathbb{R}^n$ as a union of nonempty disjoint open sets.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            How can I prove $U$ and $V$ are separated?
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:08










          • $begingroup$
            What do you mean?
            $endgroup$
            – csprun
            Feb 1 at 15:08










          • $begingroup$
            If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:11






          • 1




            $begingroup$
            We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
            $endgroup$
            – csprun
            Feb 1 at 15:12





















          1












          $begingroup$

          The metric spaces $X$ for which the only clopen subsets are $emptyset$ and $X$ have a name: connected spaces. And, yes, $mathbb{R}^n$ is connected. Therefore, it has no other clopen subsets.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            It's more general than metric spaces!
            $endgroup$
            – csprun
            Feb 1 at 15:11










          • $begingroup$
            I know, but I suspect that the OP is not aware of topological spaces.
            $endgroup$
            – José Carlos Santos
            Feb 1 at 15:12










          • $begingroup$
            That's fair. I figured you did but wanted to add it in case OP does know about them.
            $endgroup$
            – csprun
            Feb 1 at 15:13












          Your Answer





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          2 Answers
          2






          active

          oldest

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          2 Answers
          2






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$

          No. If there were such a set $U$, then setting $V = mathbb{R}^n setminus U$, $V$ will also be clopen, so that $mathbb{R}^n = U sqcup V$ is a decomposition of $mathbb{R}^n$ as a union of nonempty disjoint open sets.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            How can I prove $U$ and $V$ are separated?
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:08










          • $begingroup$
            What do you mean?
            $endgroup$
            – csprun
            Feb 1 at 15:08










          • $begingroup$
            If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:11






          • 1




            $begingroup$
            We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
            $endgroup$
            – csprun
            Feb 1 at 15:12


















          3












          $begingroup$

          No. If there were such a set $U$, then setting $V = mathbb{R}^n setminus U$, $V$ will also be clopen, so that $mathbb{R}^n = U sqcup V$ is a decomposition of $mathbb{R}^n$ as a union of nonempty disjoint open sets.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            How can I prove $U$ and $V$ are separated?
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:08










          • $begingroup$
            What do you mean?
            $endgroup$
            – csprun
            Feb 1 at 15:08










          • $begingroup$
            If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:11






          • 1




            $begingroup$
            We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
            $endgroup$
            – csprun
            Feb 1 at 15:12
















          3












          3








          3





          $begingroup$

          No. If there were such a set $U$, then setting $V = mathbb{R}^n setminus U$, $V$ will also be clopen, so that $mathbb{R}^n = U sqcup V$ is a decomposition of $mathbb{R}^n$ as a union of nonempty disjoint open sets.






          share|cite|improve this answer











          $endgroup$



          No. If there were such a set $U$, then setting $V = mathbb{R}^n setminus U$, $V$ will also be clopen, so that $mathbb{R}^n = U sqcup V$ is a decomposition of $mathbb{R}^n$ as a union of nonempty disjoint open sets.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Feb 1 at 15:09

























          answered Feb 1 at 14:46









          cspruncsprun

          2,804211




          2,804211












          • $begingroup$
            How can I prove $U$ and $V$ are separated?
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:08










          • $begingroup$
            What do you mean?
            $endgroup$
            – csprun
            Feb 1 at 15:08










          • $begingroup$
            If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:11






          • 1




            $begingroup$
            We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
            $endgroup$
            – csprun
            Feb 1 at 15:12




















          • $begingroup$
            How can I prove $U$ and $V$ are separated?
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:08










          • $begingroup$
            What do you mean?
            $endgroup$
            – csprun
            Feb 1 at 15:08










          • $begingroup$
            If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
            $endgroup$
            – Supriyo Banerjee
            Feb 1 at 15:11






          • 1




            $begingroup$
            We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
            $endgroup$
            – csprun
            Feb 1 at 15:12


















          $begingroup$
          How can I prove $U$ and $V$ are separated?
          $endgroup$
          – Supriyo Banerjee
          Feb 1 at 15:08




          $begingroup$
          How can I prove $U$ and $V$ are separated?
          $endgroup$
          – Supriyo Banerjee
          Feb 1 at 15:08












          $begingroup$
          What do you mean?
          $endgroup$
          – csprun
          Feb 1 at 15:08




          $begingroup$
          What do you mean?
          $endgroup$
          – csprun
          Feb 1 at 15:08












          $begingroup$
          If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
          $endgroup$
          – Supriyo Banerjee
          Feb 1 at 15:11




          $begingroup$
          If U and V are separated and U $union$ V =$mathbb R^n$ then $mathbb R^n$ is not connected
          $endgroup$
          – Supriyo Banerjee
          Feb 1 at 15:11




          1




          1




          $begingroup$
          We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
          $endgroup$
          – csprun
          Feb 1 at 15:12






          $begingroup$
          We defined $V$ so that it has nothing in common with $U$. (Also, the LaTeX command for the 'union' symbol is cup !)
          $endgroup$
          – csprun
          Feb 1 at 15:12













          1












          $begingroup$

          The metric spaces $X$ for which the only clopen subsets are $emptyset$ and $X$ have a name: connected spaces. And, yes, $mathbb{R}^n$ is connected. Therefore, it has no other clopen subsets.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            It's more general than metric spaces!
            $endgroup$
            – csprun
            Feb 1 at 15:11










          • $begingroup$
            I know, but I suspect that the OP is not aware of topological spaces.
            $endgroup$
            – José Carlos Santos
            Feb 1 at 15:12










          • $begingroup$
            That's fair. I figured you did but wanted to add it in case OP does know about them.
            $endgroup$
            – csprun
            Feb 1 at 15:13
















          1












          $begingroup$

          The metric spaces $X$ for which the only clopen subsets are $emptyset$ and $X$ have a name: connected spaces. And, yes, $mathbb{R}^n$ is connected. Therefore, it has no other clopen subsets.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            It's more general than metric spaces!
            $endgroup$
            – csprun
            Feb 1 at 15:11










          • $begingroup$
            I know, but I suspect that the OP is not aware of topological spaces.
            $endgroup$
            – José Carlos Santos
            Feb 1 at 15:12










          • $begingroup$
            That's fair. I figured you did but wanted to add it in case OP does know about them.
            $endgroup$
            – csprun
            Feb 1 at 15:13














          1












          1








          1





          $begingroup$

          The metric spaces $X$ for which the only clopen subsets are $emptyset$ and $X$ have a name: connected spaces. And, yes, $mathbb{R}^n$ is connected. Therefore, it has no other clopen subsets.






          share|cite|improve this answer









          $endgroup$



          The metric spaces $X$ for which the only clopen subsets are $emptyset$ and $X$ have a name: connected spaces. And, yes, $mathbb{R}^n$ is connected. Therefore, it has no other clopen subsets.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Feb 1 at 14:58









          José Carlos SantosJosé Carlos Santos

          174k23133242




          174k23133242












          • $begingroup$
            It's more general than metric spaces!
            $endgroup$
            – csprun
            Feb 1 at 15:11










          • $begingroup$
            I know, but I suspect that the OP is not aware of topological spaces.
            $endgroup$
            – José Carlos Santos
            Feb 1 at 15:12










          • $begingroup$
            That's fair. I figured you did but wanted to add it in case OP does know about them.
            $endgroup$
            – csprun
            Feb 1 at 15:13


















          • $begingroup$
            It's more general than metric spaces!
            $endgroup$
            – csprun
            Feb 1 at 15:11










          • $begingroup$
            I know, but I suspect that the OP is not aware of topological spaces.
            $endgroup$
            – José Carlos Santos
            Feb 1 at 15:12










          • $begingroup$
            That's fair. I figured you did but wanted to add it in case OP does know about them.
            $endgroup$
            – csprun
            Feb 1 at 15:13
















          $begingroup$
          It's more general than metric spaces!
          $endgroup$
          – csprun
          Feb 1 at 15:11




          $begingroup$
          It's more general than metric spaces!
          $endgroup$
          – csprun
          Feb 1 at 15:11












          $begingroup$
          I know, but I suspect that the OP is not aware of topological spaces.
          $endgroup$
          – José Carlos Santos
          Feb 1 at 15:12




          $begingroup$
          I know, but I suspect that the OP is not aware of topological spaces.
          $endgroup$
          – José Carlos Santos
          Feb 1 at 15:12












          $begingroup$
          That's fair. I figured you did but wanted to add it in case OP does know about them.
          $endgroup$
          – csprun
          Feb 1 at 15:13




          $begingroup$
          That's fair. I figured you did but wanted to add it in case OP does know about them.
          $endgroup$
          – csprun
          Feb 1 at 15:13


















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