Add year to todays date

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I am trying to add a year to todays date. I am working in a system that does not allow you to use standard JavaScript.

For instance, to get todays date I have to use:

javascript:now();

I have tried:

javascript:now(+1);

I have never seen this before, but am in need of adding one year to todays date...

Has anyone seen getting current date this way before? And if so, how could I add a year?

asked Oct 11 '15 at 21:44

Code

5312825

1

Possible duplicate of How to determine one year from now in Javascript

– rnevius
Oct 11 '15 at 21:46

This is not a duplicate. Like I said above, unable to use standard javascript methodology

– Code
Oct 11 '15 at 21:48

2

It might be helpful if you gave us some insight into what system this code is executed in.

– Jon Koops
Oct 11 '15 at 21:57

add a comment |

I am trying to add a year to todays date. I am working in a system that does not allow you to use standard JavaScript.

For instance, to get todays date I have to use:

javascript:now();

I have tried:

javascript:now(+1);

I have never seen this before, but am in need of adding one year to todays date...

Has anyone seen getting current date this way before? And if so, how could I add a year?

asked Oct 11 '15 at 21:44

Code

5312825

1

Possible duplicate of How to determine one year from now in Javascript

– rnevius
Oct 11 '15 at 21:46

This is not a duplicate. Like I said above, unable to use standard javascript methodology

– Code
Oct 11 '15 at 21:48

2

It might be helpful if you gave us some insight into what system this code is executed in.

– Jon Koops
Oct 11 '15 at 21:57

add a comment |

I am trying to add a year to todays date. I am working in a system that does not allow you to use standard JavaScript.

For instance, to get todays date I have to use:

javascript:now();

I have tried:

javascript:now(+1);

I have never seen this before, but am in need of adding one year to todays date...

Has anyone seen getting current date this way before? And if so, how could I add a year?

asked Oct 11 '15 at 21:44

Code

5312825

I am trying to add a year to todays date. I am working in a system that does not allow you to use standard JavaScript.

For instance, to get todays date I have to use:

javascript:now();

I have tried:

javascript:now(+1);

I have never seen this before, but am in need of adding one year to todays date...

Has anyone seen getting current date this way before? And if so, how could I add a year?

javascript date

asked Oct 11 '15 at 21:44

Code

5312825

asked Oct 11 '15 at 21:44

Code

5312825

asked Oct 11 '15 at 21:44

Code

5312825

asked Oct 11 '15 at 21:44

Code

5312825

asked Oct 11 '15 at 21:44

Code

5312825

1

Possible duplicate of How to determine one year from now in Javascript

– rnevius
Oct 11 '15 at 21:46

This is not a duplicate. Like I said above, unable to use standard javascript methodology

– Code
Oct 11 '15 at 21:48

2

It might be helpful if you gave us some insight into what system this code is executed in.

– Jon Koops
Oct 11 '15 at 21:57

add a comment |

1

Possible duplicate of How to determine one year from now in Javascript

– rnevius
Oct 11 '15 at 21:46

This is not a duplicate. Like I said above, unable to use standard javascript methodology

– Code
Oct 11 '15 at 21:48

2

It might be helpful if you gave us some insight into what system this code is executed in.

– Jon Koops
Oct 11 '15 at 21:57

Possible duplicate of How to determine one year from now in Javascript

– rnevius
Oct 11 '15 at 21:46

This is not a duplicate. Like I said above, unable to use standard javascript methodology

– Code
Oct 11 '15 at 21:48

It might be helpful if you gave us some insight into what system this code is executed in.

– Jon Koops
Oct 11 '15 at 21:57

add a comment |

9 Answers
9

active

oldest

votes

You can create a new date object with todays date using the following code:

var d = new Date();

console.log(d);

// => Sun Oct 11 2015 14:46:51 GMT-0700 (PDT)

If you want to create a date a specific time, you can pass the new Date constructor arguments

var d = new Date(2014);

console.log(d)

// => Wed Dec 31 1969 16:00:02 GMT-0800 (PST)

If you want to take todays date and add a year, you can first create a date object, access the relevant properties, and then use them to create a new date object

var d = new Date();

var year = d.getFullYear();

var month = d.getMonth();

var day = d.getDate();

var c = new Date(year + 1, month, day)

// => Tue Oct 11 2016 00:00:00 GMT-0700 (PDT)

You can read more about the methods on the date object on MDN

Date Object

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

36

There is no need to create two date objects. d.setFullYear(d.getFullYear() + 1) will do the job in much less code.

– RobG
Oct 11 '15 at 23:01

2

but you will also lose the original date

– Jonah Williams
Oct 11 '15 at 23:11

7

This does not work with leap year date. e.g. if you enter 29/02/2016 after adding a year it will return 29/02/2017 which is incorrect.

– Nikhil Patel
Feb 3 '17 at 12:21

3

@ANP no, it returns 01/03/2017, which is probably still not what was required but it definitely will not return the non-existent date 29/02/2017. Keep in mind that in JavaScript, February is 1, not 2.

– Roman Starkov
Mar 24 '17 at 10:26

1

@ANP You are wrong, see here.

– Timwi
Mar 24 '17 at 14:46

|
show 3 more comments

Use the Date.prototype.setFullYear method to set the year to what you want it to be.

For example:

var aYearFromNow = new Date();

aYearFromNow.setFullYear(aYearFromNow.getFullYear() + 1);

There really isn't another way to work with dates in JavaScript if these methods aren't present in the environment you are working with.

edited Mar 17 '17 at 16:57

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

add a comment |

This code adds the amount of years required for a date.

var d = new Date();

// => Tue Oct 01 2017 00:00:00 GMT-0700 (PDT)



var amountOfYearsRequired = 2;

d.setFullYear(d.getFullYear() + amountOfYearsRequired);

// => Tue Oct 01 2019 00:00:00 GMT-0700 (PDT)

edited Nov 27 '18 at 10:07

answered Sep 24 '18 at 20:29

Lucas Vellido

234

add a comment |

In Angular, This is how you Calculate Date

today = new Date();

year = this.today.getFullYear();

month = this.today.getMonth();

day = this.today.getDate();

//To go 18 years back

yearsBack18= new Date(this.year - 18, this.month, this.day);



//To go to same day next year

nextYear= new Date(this.year + 1, this.month, this.day);

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

add a comment |

In case you want to add years to specific date besides today's date using either years, or months, or days. You can do the following

var christmas2000 = new Date(2000, 12, 25); 

christmas2000.setFullYear(christmas2000.getFullYear() + 5); // using year: next 5 years

christmas2000.setFullYear(christmas2000.getMonth() + 24); // using months: next 24 months

christmas2000.setFullYear(christmas2000.getDay() + 365); // using days: next 365 months

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

add a comment |

    var d = new Date();

    var year = d.getFullYear();

    var month = d.getMonth();

    var day = d.getDate();



    var fulldate = new Date(year + 1, month, day);



    var toDate = fulldate.toISOString().slice(0, 10);



    $("#txtToDate").val(toDate);



    output : 2020-01-02

edited Jan 3 at 2:49

answered Jan 2 at 4:51

Md Shahriar

32427

add a comment |

var date = new Date();

var year = date.getFullYear();

var month = date.getMonth();

month = month + 1;

if(month < 10){

month = “0” + month;
}

var day = date.getDate();

if(day < 10){

day = “0” + day;
}

year = year + 1;

var FullDate = year + ‘/’ + month + ‘/’ + day;

answered Jan 3 at 3:02

Md Shahriar

32427

add a comment |

One liner as suggested here

How to determine one year from now in Javascript
by JP DeVries

new Date(new Date().setFullYear(new Date().getFullYear() + 1))

Or you can get the number of years from somewhere in a variable:

const nr_years = 3;

new Date(new Date().setFullYear(new Date().getFullYear() + nr_years))

answered Feb 28 at 16:32

Szekelygobe

17729

add a comment |

-1

//This piece of code will handle the leap year addition as well.

function updateExpiryDate(controlID, value) {

    if ( $("#ICMEffectiveDate").val() != '' &&

        $("#ICMTermYears").val() != '') {



        var effectiveDate = $("#ICMEffectiveDate").val();

        var date = new Date(effectiveDate);

        var termYears = $("#ICMTermYears").val();



        date = new Date(date.setYear(date.getFullYear() + parseInt(termYears)));

        var expiryDate = (date.getMonth() + 1) + '/' + date.getDate() + '/' + date.getFullYear();

        $('#ICMExpiryDate').val(expiryDate);

    }

}

answered Jul 19 '17 at 12:59

Vishal Goel

add a comment |

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9 Answers
9

active

oldest

votes

9 Answers
9

active

oldest

votes

You can create a new date object with todays date using the following code:

var d = new Date();

console.log(d);

// => Sun Oct 11 2015 14:46:51 GMT-0700 (PDT)

If you want to create a date a specific time, you can pass the new Date constructor arguments

var d = new Date(2014);

console.log(d)

// => Wed Dec 31 1969 16:00:02 GMT-0800 (PST)

If you want to take todays date and add a year, you can first create a date object, access the relevant properties, and then use them to create a new date object

var d = new Date();

var year = d.getFullYear();

var month = d.getMonth();

var day = d.getDate();

var c = new Date(year + 1, month, day)

// => Tue Oct 11 2016 00:00:00 GMT-0700 (PDT)

You can read more about the methods on the date object on MDN

Date Object

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

36

There is no need to create two date objects. d.setFullYear(d.getFullYear() + 1) will do the job in much less code.

– RobG
Oct 11 '15 at 23:01

2

but you will also lose the original date

– Jonah Williams
Oct 11 '15 at 23:11

7

This does not work with leap year date. e.g. if you enter 29/02/2016 after adding a year it will return 29/02/2017 which is incorrect.

– Nikhil Patel
Feb 3 '17 at 12:21

3

@ANP no, it returns 01/03/2017, which is probably still not what was required but it definitely will not return the non-existent date 29/02/2017. Keep in mind that in JavaScript, February is 1, not 2.

– Roman Starkov
Mar 24 '17 at 10:26

1

@ANP You are wrong, see here.

– Timwi
Mar 24 '17 at 14:46

|
show 3 more comments

You can create a new date object with todays date using the following code:

var d = new Date();

console.log(d);

// => Sun Oct 11 2015 14:46:51 GMT-0700 (PDT)

If you want to create a date a specific time, you can pass the new Date constructor arguments

var d = new Date(2014);

console.log(d)

// => Wed Dec 31 1969 16:00:02 GMT-0800 (PST)

If you want to take todays date and add a year, you can first create a date object, access the relevant properties, and then use them to create a new date object

var d = new Date();

var year = d.getFullYear();

var month = d.getMonth();

var day = d.getDate();

var c = new Date(year + 1, month, day)

// => Tue Oct 11 2016 00:00:00 GMT-0700 (PDT)

You can read more about the methods on the date object on MDN

Date Object

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

36

There is no need to create two date objects. d.setFullYear(d.getFullYear() + 1) will do the job in much less code.

– RobG
Oct 11 '15 at 23:01

2

but you will also lose the original date

– Jonah Williams
Oct 11 '15 at 23:11

7

This does not work with leap year date. e.g. if you enter 29/02/2016 after adding a year it will return 29/02/2017 which is incorrect.

– Nikhil Patel
Feb 3 '17 at 12:21

3

@ANP no, it returns 01/03/2017, which is probably still not what was required but it definitely will not return the non-existent date 29/02/2017. Keep in mind that in JavaScript, February is 1, not 2.

– Roman Starkov
Mar 24 '17 at 10:26

1

@ANP You are wrong, see here.

– Timwi
Mar 24 '17 at 14:46

|
show 3 more comments

You can create a new date object with todays date using the following code:

var d = new Date();

console.log(d);

// => Sun Oct 11 2015 14:46:51 GMT-0700 (PDT)

If you want to create a date a specific time, you can pass the new Date constructor arguments

var d = new Date(2014);

console.log(d)

// => Wed Dec 31 1969 16:00:02 GMT-0800 (PST)

If you want to take todays date and add a year, you can first create a date object, access the relevant properties, and then use them to create a new date object

var d = new Date();

var year = d.getFullYear();

var month = d.getMonth();

var day = d.getDate();

var c = new Date(year + 1, month, day)

// => Tue Oct 11 2016 00:00:00 GMT-0700 (PDT)

You can read more about the methods on the date object on MDN

Date Object

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

You can create a new date object with todays date using the following code:

var d = new Date();

console.log(d);

// => Sun Oct 11 2015 14:46:51 GMT-0700 (PDT)

If you want to create a date a specific time, you can pass the new Date constructor arguments

var d = new Date(2014);

console.log(d)

// => Wed Dec 31 1969 16:00:02 GMT-0800 (PST)

If you want to take todays date and add a year, you can first create a date object, access the relevant properties, and then use them to create a new date object

var d = new Date();

var year = d.getFullYear();

var month = d.getMonth();

var day = d.getDate();

var c = new Date(year + 1, month, day)

// => Tue Oct 11 2016 00:00:00 GMT-0700 (PDT)

You can read more about the methods on the date object on MDN

Date Object

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

answered Oct 11 '15 at 21:50

Jonah Williams

5,20911728

36

There is no need to create two date objects. d.setFullYear(d.getFullYear() + 1) will do the job in much less code.

– RobG
Oct 11 '15 at 23:01

2

but you will also lose the original date

– Jonah Williams
Oct 11 '15 at 23:11

7

This does not work with leap year date. e.g. if you enter 29/02/2016 after adding a year it will return 29/02/2017 which is incorrect.

– Nikhil Patel
Feb 3 '17 at 12:21

3

@ANP no, it returns 01/03/2017, which is probably still not what was required but it definitely will not return the non-existent date 29/02/2017. Keep in mind that in JavaScript, February is 1, not 2.

– Roman Starkov
Mar 24 '17 at 10:26

1

@ANP You are wrong, see here.

– Timwi
Mar 24 '17 at 14:46

|
show 3 more comments

36

There is no need to create two date objects. d.setFullYear(d.getFullYear() + 1) will do the job in much less code.

– RobG
Oct 11 '15 at 23:01

2

but you will also lose the original date

– Jonah Williams
Oct 11 '15 at 23:11

7

This does not work with leap year date. e.g. if you enter 29/02/2016 after adding a year it will return 29/02/2017 which is incorrect.

– Nikhil Patel
Feb 3 '17 at 12:21

3

@ANP no, it returns 01/03/2017, which is probably still not what was required but it definitely will not return the non-existent date 29/02/2017. Keep in mind that in JavaScript, February is 1, not 2.

– Roman Starkov
Mar 24 '17 at 10:26

1

@ANP You are wrong, see here.

– Timwi
Mar 24 '17 at 14:46

There is no need to create two date objects. d.setFullYear(d.getFullYear() + 1) will do the job in much less code.

– RobG
Oct 11 '15 at 23:01

but you will also lose the original date

– Jonah Williams
Oct 11 '15 at 23:11

This does not work with leap year date. e.g. if you enter 29/02/2016 after adding a year it will return 29/02/2017 which is incorrect.

– Nikhil Patel
Feb 3 '17 at 12:21

@ANP no, it returns 01/03/2017, which is probably still not what was required but it definitely will not return the non-existent date 29/02/2017. Keep in mind that in JavaScript, February is 1, not 2.

– Roman Starkov
Mar 24 '17 at 10:26

@ANP You are wrong, see here.

– Timwi
Mar 24 '17 at 14:46

|
show 3 more comments

Use the Date.prototype.setFullYear method to set the year to what you want it to be.

For example:

var aYearFromNow = new Date();

aYearFromNow.setFullYear(aYearFromNow.getFullYear() + 1);

There really isn't another way to work with dates in JavaScript if these methods aren't present in the environment you are working with.

edited Mar 17 '17 at 16:57

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

add a comment |

Use the Date.prototype.setFullYear method to set the year to what you want it to be.

For example:

var aYearFromNow = new Date();

aYearFromNow.setFullYear(aYearFromNow.getFullYear() + 1);

There really isn't another way to work with dates in JavaScript if these methods aren't present in the environment you are working with.

edited Mar 17 '17 at 16:57

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

add a comment |

Use the Date.prototype.setFullYear method to set the year to what you want it to be.

For example:

var aYearFromNow = new Date();

aYearFromNow.setFullYear(aYearFromNow.getFullYear() + 1);

There really isn't another way to work with dates in JavaScript if these methods aren't present in the environment you are working with.

edited Mar 17 '17 at 16:57

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

Use the Date.prototype.setFullYear method to set the year to what you want it to be.

For example:

var aYearFromNow = new Date();

aYearFromNow.setFullYear(aYearFromNow.getFullYear() + 1);

There really isn't another way to work with dates in JavaScript if these methods aren't present in the environment you are working with.

edited Mar 17 '17 at 16:57

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

edited Mar 17 '17 at 16:57

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

answered Oct 11 '15 at 21:51

Jon Koops

3,84242242

add a comment |

This code adds the amount of years required for a date.

var d = new Date();

// => Tue Oct 01 2017 00:00:00 GMT-0700 (PDT)



var amountOfYearsRequired = 2;

d.setFullYear(d.getFullYear() + amountOfYearsRequired);

// => Tue Oct 01 2019 00:00:00 GMT-0700 (PDT)

edited Nov 27 '18 at 10:07

answered Sep 24 '18 at 20:29

Lucas Vellido

234

add a comment |

This code adds the amount of years required for a date.

var d = new Date();

// => Tue Oct 01 2017 00:00:00 GMT-0700 (PDT)



var amountOfYearsRequired = 2;

d.setFullYear(d.getFullYear() + amountOfYearsRequired);

// => Tue Oct 01 2019 00:00:00 GMT-0700 (PDT)

edited Nov 27 '18 at 10:07

answered Sep 24 '18 at 20:29

Lucas Vellido

234

add a comment |

This code adds the amount of years required for a date.

var d = new Date();

// => Tue Oct 01 2017 00:00:00 GMT-0700 (PDT)



var amountOfYearsRequired = 2;

d.setFullYear(d.getFullYear() + amountOfYearsRequired);

// => Tue Oct 01 2019 00:00:00 GMT-0700 (PDT)

edited Nov 27 '18 at 10:07

answered Sep 24 '18 at 20:29

Lucas Vellido

234

This code adds the amount of years required for a date.

var d = new Date();

// => Tue Oct 01 2017 00:00:00 GMT-0700 (PDT)



var amountOfYearsRequired = 2;

d.setFullYear(d.getFullYear() + amountOfYearsRequired);

// => Tue Oct 01 2019 00:00:00 GMT-0700 (PDT)

edited Nov 27 '18 at 10:07

answered Sep 24 '18 at 20:29

Lucas Vellido

234

edited Nov 27 '18 at 10:07

answered Sep 24 '18 at 20:29

Lucas Vellido

234

answered Sep 24 '18 at 20:29

Lucas Vellido

234

answered Sep 24 '18 at 20:29

Lucas Vellido

234

add a comment |

In Angular, This is how you Calculate Date

today = new Date();

year = this.today.getFullYear();

month = this.today.getMonth();

day = this.today.getDate();

//To go 18 years back

yearsBack18= new Date(this.year - 18, this.month, this.day);



//To go to same day next year

nextYear= new Date(this.year + 1, this.month, this.day);

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

add a comment |

In Angular, This is how you Calculate Date

today = new Date();

year = this.today.getFullYear();

month = this.today.getMonth();

day = this.today.getDate();

//To go 18 years back

yearsBack18= new Date(this.year - 18, this.month, this.day);



//To go to same day next year

nextYear= new Date(this.year + 1, this.month, this.day);

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

add a comment |

In Angular, This is how you Calculate Date

today = new Date();

year = this.today.getFullYear();

month = this.today.getMonth();

day = this.today.getDate();

//To go 18 years back

yearsBack18= new Date(this.year - 18, this.month, this.day);



//To go to same day next year

nextYear= new Date(this.year + 1, this.month, this.day);

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

In Angular, This is how you Calculate Date

today = new Date();

year = this.today.getFullYear();

month = this.today.getMonth();

day = this.today.getDate();

//To go 18 years back

yearsBack18= new Date(this.year - 18, this.month, this.day);



//To go to same day next year

nextYear= new Date(this.year + 1, this.month, this.day);

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

answered Dec 18 '18 at 12:59

Agidigbi Ayodeji Victor

472

add a comment |

In case you want to add years to specific date besides today's date using either years, or months, or days. You can do the following

var christmas2000 = new Date(2000, 12, 25); 

christmas2000.setFullYear(christmas2000.getFullYear() + 5); // using year: next 5 years

christmas2000.setFullYear(christmas2000.getMonth() + 24); // using months: next 24 months

christmas2000.setFullYear(christmas2000.getDay() + 365); // using days: next 365 months

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

add a comment |

In case you want to add years to specific date besides today's date using either years, or months, or days. You can do the following

var christmas2000 = new Date(2000, 12, 25); 

christmas2000.setFullYear(christmas2000.getFullYear() + 5); // using year: next 5 years

christmas2000.setFullYear(christmas2000.getMonth() + 24); // using months: next 24 months

christmas2000.setFullYear(christmas2000.getDay() + 365); // using days: next 365 months

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

add a comment |

In case you want to add years to specific date besides today's date using either years, or months, or days. You can do the following

var christmas2000 = new Date(2000, 12, 25); 

christmas2000.setFullYear(christmas2000.getFullYear() + 5); // using year: next 5 years

christmas2000.setFullYear(christmas2000.getMonth() + 24); // using months: next 24 months

christmas2000.setFullYear(christmas2000.getDay() + 365); // using days: next 365 months

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

In case you want to add years to specific date besides today's date using either years, or months, or days. You can do the following

var christmas2000 = new Date(2000, 12, 25); 

christmas2000.setFullYear(christmas2000.getFullYear() + 5); // using year: next 5 years

christmas2000.setFullYear(christmas2000.getMonth() + 24); // using months: next 24 months

christmas2000.setFullYear(christmas2000.getDay() + 365); // using days: next 365 months

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

answered Dec 24 '18 at 9:54

Phemelo Khetho

217

add a comment |

    var d = new Date();

    var year = d.getFullYear();

    var month = d.getMonth();

    var day = d.getDate();



    var fulldate = new Date(year + 1, month, day);



    var toDate = fulldate.toISOString().slice(0, 10);



    $("#txtToDate").val(toDate);



    output : 2020-01-02

edited Jan 3 at 2:49

answered Jan 2 at 4:51

Md Shahriar

32427

add a comment |

    var d = new Date();

    var year = d.getFullYear();

    var month = d.getMonth();

    var day = d.getDate();



    var fulldate = new Date(year + 1, month, day);



    var toDate = fulldate.toISOString().slice(0, 10);



    $("#txtToDate").val(toDate);



    output : 2020-01-02

edited Jan 3 at 2:49

answered Jan 2 at 4:51

Md Shahriar

32427

add a comment |

    var d = new Date();

    var year = d.getFullYear();

    var month = d.getMonth();

    var day = d.getDate();



    var fulldate = new Date(year + 1, month, day);



    var toDate = fulldate.toISOString().slice(0, 10);



    $("#txtToDate").val(toDate);



    output : 2020-01-02

edited Jan 3 at 2:49

answered Jan 2 at 4:51

Md Shahriar

32427

    var d = new Date();

    var year = d.getFullYear();

    var month = d.getMonth();

    var day = d.getDate();



    var fulldate = new Date(year + 1, month, day);



    var toDate = fulldate.toISOString().slice(0, 10);



    $("#txtToDate").val(toDate);



    output : 2020-01-02

edited Jan 3 at 2:49

answered Jan 2 at 4:51

Md Shahriar

32427

edited Jan 3 at 2:49

answered Jan 2 at 4:51

Md Shahriar

32427

answered Jan 2 at 4:51

Md Shahriar

32427

answered Jan 2 at 4:51

Md Shahriar

32427

add a comment |

var date = new Date();

var year = date.getFullYear();

var month = date.getMonth();

month = month + 1;

if(month < 10){

month = “0” + month;
}

var day = date.getDate();

if(day < 10){

day = “0” + day;
}

year = year + 1;

var FullDate = year + ‘/’ + month + ‘/’ + day;

answered Jan 3 at 3:02

Md Shahriar

32427

add a comment |

var date = new Date();

var year = date.getFullYear();

var month = date.getMonth();

month = month + 1;

if(month < 10){

month = “0” + month;
}

var day = date.getDate();

if(day < 10){

day = “0” + day;
}

year = year + 1;

var FullDate = year + ‘/’ + month + ‘/’ + day;

answered Jan 3 at 3:02

Md Shahriar

32427

add a comment |

var date = new Date();

var year = date.getFullYear();

var month = date.getMonth();

month = month + 1;

if(month < 10){

month = “0” + month;
}

var day = date.getDate();

if(day < 10){

day = “0” + day;
}

year = year + 1;

var FullDate = year + ‘/’ + month + ‘/’ + day;

answered Jan 3 at 3:02

Md Shahriar

32427

var date = new Date();

var year = date.getFullYear();

var month = date.getMonth();

month = month + 1;

if(month < 10){

month = “0” + month;
}

var day = date.getDate();

if(day < 10){

day = “0” + day;
}

year = year + 1;

var FullDate = year + ‘/’ + month + ‘/’ + day;

answered Jan 3 at 3:02

Md Shahriar

32427

answered Jan 3 at 3:02

Md Shahriar

32427

answered Jan 3 at 3:02

Md Shahriar

32427

answered Jan 3 at 3:02

Md Shahriar

32427

add a comment |

One liner as suggested here

How to determine one year from now in Javascript
by JP DeVries

new Date(new Date().setFullYear(new Date().getFullYear() + 1))

Or you can get the number of years from somewhere in a variable:

const nr_years = 3;

new Date(new Date().setFullYear(new Date().getFullYear() + nr_years))

answered Feb 28 at 16:32

Szekelygobe

17729

add a comment |

One liner as suggested here

How to determine one year from now in Javascript
by JP DeVries

new Date(new Date().setFullYear(new Date().getFullYear() + 1))

Or you can get the number of years from somewhere in a variable:

const nr_years = 3;

new Date(new Date().setFullYear(new Date().getFullYear() + nr_years))

answered Feb 28 at 16:32

Szekelygobe

17729

add a comment |

One liner as suggested here

How to determine one year from now in Javascript
by JP DeVries

new Date(new Date().setFullYear(new Date().getFullYear() + 1))

Or you can get the number of years from somewhere in a variable:

const nr_years = 3;

new Date(new Date().setFullYear(new Date().getFullYear() + nr_years))

answered Feb 28 at 16:32

Szekelygobe

17729

One liner as suggested here

How to determine one year from now in Javascript
by JP DeVries

new Date(new Date().setFullYear(new Date().getFullYear() + 1))

Or you can get the number of years from somewhere in a variable:

const nr_years = 3;

new Date(new Date().setFullYear(new Date().getFullYear() + nr_years))

answered Feb 28 at 16:32

Szekelygobe

17729

answered Feb 28 at 16:32

Szekelygobe

17729

answered Feb 28 at 16:32

Szekelygobe

17729

answered Feb 28 at 16:32

Szekelygobe

17729

add a comment |

-1

//This piece of code will handle the leap year addition as well.

function updateExpiryDate(controlID, value) {

    if ( $("#ICMEffectiveDate").val() != '' &&

        $("#ICMTermYears").val() != '') {



        var effectiveDate = $("#ICMEffectiveDate").val();

        var date = new Date(effectiveDate);

        var termYears = $("#ICMTermYears").val();



        date = new Date(date.setYear(date.getFullYear() + parseInt(termYears)));

        var expiryDate = (date.getMonth() + 1) + '/' + date.getDate() + '/' + date.getFullYear();

        $('#ICMExpiryDate').val(expiryDate);

    }

}

answered Jul 19 '17 at 12:59

Vishal Goel

add a comment |

-1

//This piece of code will handle the leap year addition as well.

function updateExpiryDate(controlID, value) {

    if ( $("#ICMEffectiveDate").val() != '' &&

        $("#ICMTermYears").val() != '') {



        var effectiveDate = $("#ICMEffectiveDate").val();

        var date = new Date(effectiveDate);

        var termYears = $("#ICMTermYears").val();



        date = new Date(date.setYear(date.getFullYear() + parseInt(termYears)));

        var expiryDate = (date.getMonth() + 1) + '/' + date.getDate() + '/' + date.getFullYear();

        $('#ICMExpiryDate').val(expiryDate);

    }

}

answered Jul 19 '17 at 12:59

Vishal Goel

add a comment |

-1

//This piece of code will handle the leap year addition as well.

function updateExpiryDate(controlID, value) {

    if ( $("#ICMEffectiveDate").val() != '' &&

        $("#ICMTermYears").val() != '') {



        var effectiveDate = $("#ICMEffectiveDate").val();

        var date = new Date(effectiveDate);

        var termYears = $("#ICMTermYears").val();



        date = new Date(date.setYear(date.getFullYear() + parseInt(termYears)));

        var expiryDate = (date.getMonth() + 1) + '/' + date.getDate() + '/' + date.getFullYear();

        $('#ICMExpiryDate').val(expiryDate);

    }

}

answered Jul 19 '17 at 12:59

Vishal Goel

//This piece of code will handle the leap year addition as well.

function updateExpiryDate(controlID, value) {

    if ( $("#ICMEffectiveDate").val() != '' &&

        $("#ICMTermYears").val() != '') {



        var effectiveDate = $("#ICMEffectiveDate").val();

        var date = new Date(effectiveDate);

        var termYears = $("#ICMTermYears").val();



        date = new Date(date.setYear(date.getFullYear() + parseInt(termYears)));

        var expiryDate = (date.getMonth() + 1) + '/' + date.getDate() + '/' + date.getFullYear();

        $('#ICMExpiryDate').val(expiryDate);

    }

}

answered Jul 19 '17 at 12:59

Vishal Goel

answered Jul 19 '17 at 12:59

Vishal Goel

answered Jul 19 '17 at 12:59

Vishal Goel

answered Jul 19 '17 at 12:59

Vishal Goel

add a comment |

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