How to continuously receive data?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}

I've created a very simple tcp server in Python. I connect, then the server waits for data to be sent from the client, then the client waits for data to be sent back. While each is waiting, they aren't able to send data. So one side can't send two messages back to back. I'd like to for both sides to listen and still be able to send at all times.How would I go about that?
Server code:

socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

socket.bind((ipAddr, port))

print('Server starting on ' + ipAddr + ':' + str(port))

socket.listen(10)

print('Waiting for connection...')

c, addr = socket.accept()

print('Connection recieved from ' + str(addr))

while True:

    try:



        buf = c.recv(1024)

        if buf == 'stop':

            break

        elif len(buf) > 0:

            print(buf)

            response = input('>')

            c.sendall(str.encode(str(response)))

    except:

        print('Error')

        break



socket.close()

I'd like to be able to send back to back messages from the server to the client while still listening for responses from the client

edited Jan 3 at 4:11

asked Jan 3 at 4:06

Austin Palmer

1

One good way to do this is to set your socket to non-blocking mode, and write your event loop around a call to select(). The only place the loop should ever block is in the select() call, and (assuming you pass in the correct arguments to it) that call will return whenever there is data ready-for-read, and/or whenever there is buffer-space-ready-to-write-to. (Only request that it return for the latter condition if you actually have data to send, of course)

– Jeremy Friesner
Jan 3 at 4:16

Is there an example you could link? I don't totally get what you're saying

– Austin Palmer
Jan 3 at 4:18

Maybe this article will be helpful: medium.com/vaidikkapoor/…

– Jeremy Friesner
Jan 3 at 4:22

add a comment |

socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

socket.bind((ipAddr, port))

print('Server starting on ' + ipAddr + ':' + str(port))

socket.listen(10)

print('Waiting for connection...')

c, addr = socket.accept()

print('Connection recieved from ' + str(addr))

while True:

    try:



        buf = c.recv(1024)

        if buf == 'stop':

            break

        elif len(buf) > 0:

            print(buf)

            response = input('>')

            c.sendall(str.encode(str(response)))

    except:

        print('Error')

        break



socket.close()

I'd like to be able to send back to back messages from the server to the client while still listening for responses from the client

edited Jan 3 at 4:11

asked Jan 3 at 4:06

Austin Palmer

1

One good way to do this is to set your socket to non-blocking mode, and write your event loop around a call to select(). The only place the loop should ever block is in the select() call, and (assuming you pass in the correct arguments to it) that call will return whenever there is data ready-for-read, and/or whenever there is buffer-space-ready-to-write-to. (Only request that it return for the latter condition if you actually have data to send, of course)

– Jeremy Friesner
Jan 3 at 4:16

Is there an example you could link? I don't totally get what you're saying

– Austin Palmer
Jan 3 at 4:18

Maybe this article will be helpful: medium.com/vaidikkapoor/…

– Jeremy Friesner
Jan 3 at 4:22

add a comment |

socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

socket.bind((ipAddr, port))

print('Server starting on ' + ipAddr + ':' + str(port))

socket.listen(10)

print('Waiting for connection...')

c, addr = socket.accept()

print('Connection recieved from ' + str(addr))

while True:

    try:



        buf = c.recv(1024)

        if buf == 'stop':

            break

        elif len(buf) > 0:

            print(buf)

            response = input('>')

            c.sendall(str.encode(str(response)))

    except:

        print('Error')

        break



socket.close()

I'd like to be able to send back to back messages from the server to the client while still listening for responses from the client

edited Jan 3 at 4:11

asked Jan 3 at 4:06

Austin Palmer

socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

socket.bind((ipAddr, port))

print('Server starting on ' + ipAddr + ':' + str(port))

socket.listen(10)

print('Waiting for connection...')

c, addr = socket.accept()

print('Connection recieved from ' + str(addr))

while True:

    try:



        buf = c.recv(1024)

        if buf == 'stop':

            break

        elif len(buf) > 0:

            print(buf)

            response = input('>')

            c.sendall(str.encode(str(response)))

    except:

        print('Error')

        break



socket.close()

I'd like to be able to send back to back messages from the server to the client while still listening for responses from the client

python sockets

edited Jan 3 at 4:11

asked Jan 3 at 4:06

Austin Palmer

edited Jan 3 at 4:11

asked Jan 3 at 4:06

Austin Palmer

edited Jan 3 at 4:11

asked Jan 3 at 4:06

Austin Palmer

asked Jan 3 at 4:06

Austin Palmer

asked Jan 3 at 4:06

Austin Palmer

1

One good way to do this is to set your socket to non-blocking mode, and write your event loop around a call to select(). The only place the loop should ever block is in the select() call, and (assuming you pass in the correct arguments to it) that call will return whenever there is data ready-for-read, and/or whenever there is buffer-space-ready-to-write-to. (Only request that it return for the latter condition if you actually have data to send, of course)

– Jeremy Friesner
Jan 3 at 4:16

Is there an example you could link? I don't totally get what you're saying

– Austin Palmer
Jan 3 at 4:18

Maybe this article will be helpful: medium.com/vaidikkapoor/…

– Jeremy Friesner
Jan 3 at 4:22

add a comment |

1

One good way to do this is to set your socket to non-blocking mode, and write your event loop around a call to select(). The only place the loop should ever block is in the select() call, and (assuming you pass in the correct arguments to it) that call will return whenever there is data ready-for-read, and/or whenever there is buffer-space-ready-to-write-to. (Only request that it return for the latter condition if you actually have data to send, of course)

– Jeremy Friesner
Jan 3 at 4:16

Is there an example you could link? I don't totally get what you're saying

– Austin Palmer
Jan 3 at 4:18

Maybe this article will be helpful: medium.com/vaidikkapoor/…

– Jeremy Friesner
Jan 3 at 4:22

One good way to do this is to set your socket to non-blocking mode, and write your event loop around a call to select(). The only place the loop should ever block is in the select() call, and (assuming you pass in the correct arguments to it) that call will return whenever there is data ready-for-read, and/or whenever there is buffer-space-ready-to-write-to. (Only request that it return for the latter condition if you actually have data to send, of course)

– Jeremy Friesner
Jan 3 at 4:16

Is there an example you could link? I don't totally get what you're saying

– Austin Palmer
Jan 3 at 4:18

Maybe this article will be helpful: medium.com/vaidikkapoor/…

– Jeremy Friesner
Jan 3 at 4:22

add a comment |

1 Answer
1

active

oldest

votes

while True:
#receiving

client,add=server.accept()

data = client.recv(1024)

str = data.decode('ascii')

print("client is saying: ",str)



#sending



msg = input("server:")

a= msg.encode('ascii')

client.send(a)

answered Jan 3 at 4:54

sushants367

163

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54016220%2fhow-to-continuously-receive-data%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

while True:
#receiving

client,add=server.accept()

data = client.recv(1024)

str = data.decode('ascii')

print("client is saying: ",str)



#sending



msg = input("server:")

a= msg.encode('ascii')

client.send(a)

answered Jan 3 at 4:54

sushants367

163

add a comment |

while True:
#receiving

client,add=server.accept()

data = client.recv(1024)

str = data.decode('ascii')

print("client is saying: ",str)



#sending



msg = input("server:")

a= msg.encode('ascii')

client.send(a)

answered Jan 3 at 4:54

sushants367

163

add a comment |

while True:
#receiving

client,add=server.accept()

data = client.recv(1024)

str = data.decode('ascii')

print("client is saying: ",str)



#sending



msg = input("server:")

a= msg.encode('ascii')

client.send(a)

answered Jan 3 at 4:54

sushants367

163

while True:
#receiving

client,add=server.accept()

data = client.recv(1024)

str = data.decode('ascii')

print("client is saying: ",str)



#sending



msg = input("server:")

a= msg.encode('ascii')

client.send(a)

answered Jan 3 at 4:54

sushants367

163

answered Jan 3 at 4:54

sushants367

163

answered Jan 3 at 4:54

sushants367

163

answered Jan 3 at 4:54

sushants367

163

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

Search This Blog

Ufyukyu