Mixing
Algebraic manipulation problem
$begingroup$
I was just wondering out of curiosity since i do not see how this could be done but is there a potential way to make $a $ the subject of this formula?
$$X=bigg(frac{50times2}{a^{50times2}}-1bigg)a^y-bigg(frac{50times2}{a^{50times2}}-1bigg)$$
Where $Xin[0,100]$ and $yin [0,100]$.
Would appreciate the suggestions and help offered.
EDIT: What if the equation is given as:
$$X=bigg(frac{50times2}{a^{50times2}-1}bigg)a^y-bigg(frac{50times2}{a^{50times2}-1}bigg)$$
algebra-precalculus
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
$endgroup$
|
show 3 more comments
$begingroup$
I was just wondering out of curiosity since i do not see how this could be done but is there a potential way to make $a $ the subject of this formula?
$$X=bigg(frac{50times2}{a^{50times2}}-1bigg)a^y-bigg(frac{50times2}{a^{50times2}}-1bigg)$$
Where $Xin[0,100]$ and $yin [0,100]$.
Would appreciate the suggestions and help offered.
EDIT: What if the equation is given as:
$$X=bigg(frac{50times2}{a^{50times2}-1}bigg)a^y-bigg(frac{50times2}{a^{50times2}-1}bigg)$$
algebra-precalculus
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
$endgroup$
$begingroup$
As the Wolfram Development Platform can't find a solution, I'm guessing your only option is to find $a$ numerically.
$endgroup$
– Adrian Keister
Jan 30 at 17:23
$begingroup$
Thank you for the suggestion, so what numerical analysis techniques could we employ?
$endgroup$
– Aurora Borealis
Jan 30 at 17:26
$begingroup$
Do you have an interval in which $a$ must lie?
$endgroup$
– Adrian Keister
Jan 30 at 17:27
$begingroup$
There is no information given on the interval of $a$.
$endgroup$
– Aurora Borealis
Jan 30 at 17:28
1
$begingroup$
Also, rewriting the equation as $$x = frac{(a^{100} - 100) (1 - a^y )}{a^{100}}$$ might help.
$endgroup$
– Viktor Glombik
Jan 30 at 17:39
|
show 3 more comments
$begingroup$
I was just wondering out of curiosity since i do not see how this could be done but is there a potential way to make $a $ the subject of this formula?
$$X=bigg(frac{50times2}{a^{50times2}}-1bigg)a^y-bigg(frac{50times2}{a^{50times2}}-1bigg)$$
Where $Xin[0,100]$ and $yin [0,100]$.
Would appreciate the suggestions and help offered.
EDIT: What if the equation is given as:
$$X=bigg(frac{50times2}{a^{50times2}-1}bigg)a^y-bigg(frac{50times2}{a^{50times2}-1}bigg)$$
algebra-precalculus
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
$endgroup$
I was just wondering out of curiosity since i do not see how this could be done but is there a potential way to make $a $ the subject of this formula?
$$X=bigg(frac{50times2}{a^{50times2}}-1bigg)a^y-bigg(frac{50times2}{a^{50times2}}-1bigg)$$
Where $Xin[0,100]$ and $yin [0,100]$.
Would appreciate the suggestions and help offered.
EDIT: What if the equation is given as:
$$X=bigg(frac{50times2}{a^{50times2}-1}bigg)a^y-bigg(frac{50times2}{a^{50times2}-1}bigg)$$
algebra-precalculus
algebra-precalculus
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
edited Jan 31 at 2:50
Aurora Borealis
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
asked Jan 30 at 17:10
Aurora BorealisAurora Borealis
866414
866414
$begingroup$
As the Wolfram Development Platform can't find a solution, I'm guessing your only option is to find $a$ numerically.
$endgroup$
– Adrian Keister
Jan 30 at 17:23
$begingroup$
Thank you for the suggestion, so what numerical analysis techniques could we employ?
$endgroup$
– Aurora Borealis
Jan 30 at 17:26
$begingroup$
Do you have an interval in which $a$ must lie?
$endgroup$
– Adrian Keister
Jan 30 at 17:27
$begingroup$
There is no information given on the interval of $a$.
$endgroup$
– Aurora Borealis
Jan 30 at 17:28
1
$begingroup$
Also, rewriting the equation as $$x = frac{(a^{100} - 100) (1 - a^y )}{a^{100}}$$ might help.
$endgroup$
– Viktor Glombik
Jan 30 at 17:39
|
show 3 more comments
$begingroup$
As the Wolfram Development Platform can't find a solution, I'm guessing your only option is to find $a$ numerically.
$endgroup$
– Adrian Keister
Jan 30 at 17:23
$begingroup$
Thank you for the suggestion, so what numerical analysis techniques could we employ?
$endgroup$
– Aurora Borealis
Jan 30 at 17:26
$begingroup$
Do you have an interval in which $a$ must lie?
$endgroup$
– Adrian Keister
Jan 30 at 17:27
$begingroup$
There is no information given on the interval of $a$.
$endgroup$
– Aurora Borealis
Jan 30 at 17:28
1
$begingroup$
Also, rewriting the equation as $$x = frac{(a^{100} - 100) (1 - a^y )}{a^{100}}$$ might help.
$endgroup$
– Viktor Glombik
Jan 30 at 17:39
$begingroup$
As the Wolfram Development Platform can't find a solution, I'm guessing your only option is to find $a$ numerically.
$endgroup$
– Adrian Keister
Jan 30 at 17:23
$begingroup$
As the Wolfram Development Platform can't find a solution, I'm guessing your only option is to find $a$ numerically.
$endgroup$
– Adrian Keister
Jan 30 at 17:23
$begingroup$
Thank you for the suggestion, so what numerical analysis techniques could we employ?
$endgroup$
– Aurora Borealis
Jan 30 at 17:26
$begingroup$
Thank you for the suggestion, so what numerical analysis techniques could we employ?
$endgroup$
– Aurora Borealis
Jan 30 at 17:26
$begingroup$
Do you have an interval in which $a$ must lie?
$endgroup$
– Adrian Keister
Jan 30 at 17:27
$begingroup$
Do you have an interval in which $a$ must lie?
$endgroup$
– Adrian Keister
Jan 30 at 17:27
$begingroup$
There is no information given on the interval of $a$.
$endgroup$
– Aurora Borealis
Jan 30 at 17:28
$begingroup$
There is no information given on the interval of $a$.
$endgroup$
– Aurora Borealis
Jan 30 at 17:28
1
1
$begingroup$
Also, rewriting the equation as $$x = frac{(a^{100} - 100) (1 - a^y )}{a^{100}}$$ might help.
$endgroup$
– Viktor Glombik
Jan 30 at 17:39
$begingroup$
Also, rewriting the equation as $$x = frac{(a^{100} - 100) (1 - a^y )}{a^{100}}$$ might help.
$endgroup$
– Viktor Glombik
Jan 30 at 17:39
|
show 3 more comments
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3093810%2falgebraic-manipulation-problem%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3093810%2falgebraic-manipulation-problem%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
As the Wolfram Development Platform can't find a solution, I'm guessing your only option is to find $a$ numerically.
$endgroup$
– Adrian Keister
Jan 30 at 17:23
$begingroup$
Thank you for the suggestion, so what numerical analysis techniques could we employ?
$endgroup$
– Aurora Borealis
Jan 30 at 17:26
$begingroup$
Do you have an interval in which $a$ must lie?
$endgroup$
– Adrian Keister
Jan 30 at 17:27
$begingroup$
There is no information given on the interval of $a$.
$endgroup$
– Aurora Borealis
Jan 30 at 17:28
1
$begingroup$
Also, rewriting the equation as $$x = frac{(a^{100} - 100) (1 - a^y )}{a^{100}}$$ might help.
$endgroup$
– Viktor Glombik
Jan 30 at 17:39