bin packing with constraints?
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I recently implemented a bin packing algorithm to help me decide how to re-balance some collections in my database cluster. I was very excited to see it balance all the collections by size as I wanted, but the way it fills bins places large collections together and then the last bin is full of tiny collections.
For example
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 0.07GB
200GB 200GB 0.06GB
100GB 100GB .....
It would be more optimal for me if I could have bins that sought to maximize the number of small collections per large collection in each bin. Something like this:
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 200GB
100GB 100GB 200GB
0.76GB 0.76GB 0.76GB
... ... ...
The reason being that the large collections and small collections of complimentary usage patterns; by pairing them together I can more efficiently use my resources.
combinatorics
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add a comment |
$begingroup$
I recently implemented a bin packing algorithm to help me decide how to re-balance some collections in my database cluster. I was very excited to see it balance all the collections by size as I wanted, but the way it fills bins places large collections together and then the last bin is full of tiny collections.
For example
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 0.07GB
200GB 200GB 0.06GB
100GB 100GB .....
It would be more optimal for me if I could have bins that sought to maximize the number of small collections per large collection in each bin. Something like this:
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 200GB
100GB 100GB 200GB
0.76GB 0.76GB 0.76GB
... ... ...
The reason being that the large collections and small collections of complimentary usage patterns; by pairing them together I can more efficiently use my resources.
combinatorics
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Just of the top, I would try putting the largest collection into the bin with the largest available space. Continuing for all collections. This should result in your second distribution.
$endgroup$
– Daniel Mathias
Feb 1 at 14:51
add a comment |
$begingroup$
I recently implemented a bin packing algorithm to help me decide how to re-balance some collections in my database cluster. I was very excited to see it balance all the collections by size as I wanted, but the way it fills bins places large collections together and then the last bin is full of tiny collections.
For example
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 0.07GB
200GB 200GB 0.06GB
100GB 100GB .....
It would be more optimal for me if I could have bins that sought to maximize the number of small collections per large collection in each bin. Something like this:
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 200GB
100GB 100GB 200GB
0.76GB 0.76GB 0.76GB
... ... ...
The reason being that the large collections and small collections of complimentary usage patterns; by pairing them together I can more efficiently use my resources.
combinatorics
$endgroup$
I recently implemented a bin packing algorithm to help me decide how to re-balance some collections in my database cluster. I was very excited to see it balance all the collections by size as I wanted, but the way it fills bins places large collections together and then the last bin is full of tiny collections.
For example
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 0.07GB
200GB 200GB 0.06GB
100GB 100GB .....
It would be more optimal for me if I could have bins that sought to maximize the number of small collections per large collection in each bin. Something like this:
BIN 1 BIN 2 BIN N
----- ----- .... -----
500GB 500GB 200GB
100GB 100GB 200GB
0.76GB 0.76GB 0.76GB
... ... ...
The reason being that the large collections and small collections of complimentary usage patterns; by pairing them together I can more efficiently use my resources.
combinatorics
combinatorics
asked Feb 1 at 14:21
BreedlyBreedly
143114
143114
$begingroup$
Just of the top, I would try putting the largest collection into the bin with the largest available space. Continuing for all collections. This should result in your second distribution.
$endgroup$
– Daniel Mathias
Feb 1 at 14:51
add a comment |
$begingroup$
Just of the top, I would try putting the largest collection into the bin with the largest available space. Continuing for all collections. This should result in your second distribution.
$endgroup$
– Daniel Mathias
Feb 1 at 14:51
$begingroup$
Just of the top, I would try putting the largest collection into the bin with the largest available space. Continuing for all collections. This should result in your second distribution.
$endgroup$
– Daniel Mathias
Feb 1 at 14:51
$begingroup$
Just of the top, I would try putting the largest collection into the bin with the largest available space. Continuing for all collections. This should result in your second distribution.
$endgroup$
– Daniel Mathias
Feb 1 at 14:51
add a comment |
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$begingroup$
Just of the top, I would try putting the largest collection into the bin with the largest available space. Continuing for all collections. This should result in your second distribution.
$endgroup$
– Daniel Mathias
Feb 1 at 14:51