Mixing
Closing all child windows
The web site could spawn one or more pop up windows.
When the main browser window is closed, i would like all the child windows to be closed as well.
Currently, I am performing this
$(window).on('unload', function () {
if (_chatWindow && !_chatWindow.closed)
{
_chatWindow.close();
};
if (_wazeWindow && !_wazeWindow.closed)
{
_wazeWindow.close();
};
if (_mapWindow && !_mapWindow.closed)
{
_mapWindow.close();
};
});
This seems to work if each child window is opened, but if, for example the _chatWindow is not opened, the _wazeWindow and _mapWindow windows are not being closed.
Does anyone have any suggestions on a way to ensure all the child popup windows can be closed when the parent window is closed.
javascript
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
add a comment |
The web site could spawn one or more pop up windows.
When the main browser window is closed, i would like all the child windows to be closed as well.
Currently, I am performing this
$(window).on('unload', function () {
if (_chatWindow && !_chatWindow.closed)
{
_chatWindow.close();
};
if (_wazeWindow && !_wazeWindow.closed)
{
_wazeWindow.close();
};
if (_mapWindow && !_mapWindow.closed)
{
_mapWindow.close();
};
});
This seems to work if each child window is opened, but if, for example the _chatWindow is not opened, the _wazeWindow and _mapWindow windows are not being closed.
Does anyone have any suggestions on a way to ensure all the child popup windows can be closed when the parent window is closed.
javascript
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
1
Are you getting an error in the console? Personally I would generalize this, maintain an array of windows instead and then dochildWindows.forEach(w => !w.closed && w.close()).
– Felix Kling
Jan 3 at 1:06
1
const childWindows = [_chatWindow, _wazeWindow, _mapWindow]; childWindows.forEach(w => w && !w.closed && w.close && w.close())
– justin.m.chase
Jan 3 at 1:16
I've used the array technique as suggested by @FelixKling. It worked in the past and it's working right now. What browser are you using and could you provide a code snippet that reproduces the problem please?
– traktor53
Jan 3 at 1:17
Great ideas!!! i went with justin chase comment. please provide it as an answer,
– pithhelmet
Jan 3 at 1:24
add a comment |
The web site could spawn one or more pop up windows.
When the main browser window is closed, i would like all the child windows to be closed as well.
Currently, I am performing this
$(window).on('unload', function () {
if (_chatWindow && !_chatWindow.closed)
{
_chatWindow.close();
};
if (_wazeWindow && !_wazeWindow.closed)
{
_wazeWindow.close();
};
if (_mapWindow && !_mapWindow.closed)
{
_mapWindow.close();
};
});
This seems to work if each child window is opened, but if, for example the _chatWindow is not opened, the _wazeWindow and _mapWindow windows are not being closed.
Does anyone have any suggestions on a way to ensure all the child popup windows can be closed when the parent window is closed.
javascript
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
The web site could spawn one or more pop up windows.
When the main browser window is closed, i would like all the child windows to be closed as well.
Currently, I am performing this
$(window).on('unload', function () {
if (_chatWindow && !_chatWindow.closed)
{
_chatWindow.close();
};
if (_wazeWindow && !_wazeWindow.closed)
{
_wazeWindow.close();
};
if (_mapWindow && !_mapWindow.closed)
{
_mapWindow.close();
};
});
This seems to work if each child window is opened, but if, for example the _chatWindow is not opened, the _wazeWindow and _mapWindow windows are not being closed.
Does anyone have any suggestions on a way to ensure all the child popup windows can be closed when the parent window is closed.
javascript
javascript
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
asked Jan 3 at 1:01
pithhelmetpithhelmet
99252150
99252150
1
Are you getting an error in the console? Personally I would generalize this, maintain an array of windows instead and then dochildWindows.forEach(w => !w.closed && w.close()).
– Felix Kling
Jan 3 at 1:06
1
const childWindows = [_chatWindow, _wazeWindow, _mapWindow]; childWindows.forEach(w => w && !w.closed && w.close && w.close())
– justin.m.chase
Jan 3 at 1:16
I've used the array technique as suggested by @FelixKling. It worked in the past and it's working right now. What browser are you using and could you provide a code snippet that reproduces the problem please?
– traktor53
Jan 3 at 1:17
Great ideas!!! i went with justin chase comment. please provide it as an answer,
– pithhelmet
Jan 3 at 1:24
add a comment |
1
Are you getting an error in the console? Personally I would generalize this, maintain an array of windows instead and then dochildWindows.forEach(w => !w.closed && w.close()).
– Felix Kling
Jan 3 at 1:06
1
const childWindows = [_chatWindow, _wazeWindow, _mapWindow]; childWindows.forEach(w => w && !w.closed && w.close && w.close())
– justin.m.chase
Jan 3 at 1:16
I've used the array technique as suggested by @FelixKling. It worked in the past and it's working right now. What browser are you using and could you provide a code snippet that reproduces the problem please?
– traktor53
Jan 3 at 1:17
Great ideas!!! i went with justin chase comment. please provide it as an answer,
– pithhelmet
Jan 3 at 1:24
1
1
Are you getting an error in the console? Personally I would generalize this, maintain an array of windows instead and then do
childWindows.forEach(w => !w.closed && w.close()).– Felix Kling
Jan 3 at 1:06
Are you getting an error in the console? Personally I would generalize this, maintain an array of windows instead and then do
childWindows.forEach(w => !w.closed && w.close()).– Felix Kling
Jan 3 at 1:06
1
1
const childWindows = [_chatWindow, _wazeWindow, _mapWindow]; childWindows.forEach(w => w && !w.closed && w.close && w.close())– justin.m.chase
Jan 3 at 1:16
const childWindows = [_chatWindow, _wazeWindow, _mapWindow]; childWindows.forEach(w => w && !w.closed && w.close && w.close())– justin.m.chase
Jan 3 at 1:16
I've used the array technique as suggested by @FelixKling. It worked in the past and it's working right now. What browser are you using and could you provide a code snippet that reproduces the problem please?
– traktor53
Jan 3 at 1:17
I've used the array technique as suggested by @FelixKling. It worked in the past and it's working right now. What browser are you using and could you provide a code snippet that reproduces the problem please?
– traktor53
Jan 3 at 1:17
Great ideas!!! i went with justin chase comment. please provide it as an answer,
– pithhelmet
Jan 3 at 1:24
Great ideas!!! i went with justin chase comment. please provide it as an answer,
– pithhelmet
Jan 3 at 1:24
add a comment |
1 Answer
1
active
oldest
votes
I went with the idea that felix and justin presented.
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
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votes
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oldest
votes
I went with the idea that felix and justin presented.
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
add a comment |
I went with the idea that felix and justin presented.
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
add a comment |
I went with the idea that felix and justin presented.
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
I went with the idea that felix and justin presented.
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
answered Jan 7 at 18:32
pithhelmetpithhelmet
99252150
99252150
add a comment |
add a comment |
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1
Are you getting an error in the console? Personally I would generalize this, maintain an array of windows instead and then do
childWindows.forEach(w => !w.closed && w.close()).– Felix Kling
Jan 3 at 1:06
1
const childWindows = [_chatWindow, _wazeWindow, _mapWindow]; childWindows.forEach(w => w && !w.closed && w.close && w.close())– justin.m.chase
Jan 3 at 1:16
I've used the array technique as suggested by @FelixKling. It worked in the past and it's working right now. What browser are you using and could you provide a code snippet that reproduces the problem please?
– traktor53
Jan 3 at 1:17
Great ideas!!! i went with justin chase comment. please provide it as an answer,
– pithhelmet
Jan 3 at 1:24