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Finding area of a triangle with integration
I have a triangle with coordinates (0,0), (1,2) and (1,0).
Is the area of this triangle same as finding the integral of the function $y=2x^2$ and substituting the value of x=1 and y=2? Because what i understood by reading about integral is that it can find the area under the slop with which the function to be integrated is defined. I have tried this way and i am getting different values for the integration method and original area. Where am i wrong?
integration triangle coordinate-systems area
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
add a comment |
I have a triangle with coordinates (0,0), (1,2) and (1,0).
Is the area of this triangle same as finding the integral of the function $y=2x^2$ and substituting the value of x=1 and y=2? Because what i understood by reading about integral is that it can find the area under the slop with which the function to be integrated is defined. I have tried this way and i am getting different values for the integration method and original area. Where am i wrong?
integration triangle coordinate-systems area
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
add a comment |
I have a triangle with coordinates (0,0), (1,2) and (1,0).
Is the area of this triangle same as finding the integral of the function $y=2x^2$ and substituting the value of x=1 and y=2? Because what i understood by reading about integral is that it can find the area under the slop with which the function to be integrated is defined. I have tried this way and i am getting different values for the integration method and original area. Where am i wrong?
integration triangle coordinate-systems area
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
I have a triangle with coordinates (0,0), (1,2) and (1,0).
Is the area of this triangle same as finding the integral of the function $y=2x^2$ and substituting the value of x=1 and y=2? Because what i understood by reading about integral is that it can find the area under the slop with which the function to be integrated is defined. I have tried this way and i am getting different values for the integration method and original area. Where am i wrong?
integration triangle coordinate-systems area
integration triangle coordinate-systems area
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
asked Nov 21 '18 at 7:05
Hari Krishnan
1033
1033
add a comment |
add a comment |
1 Answer
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The function to integrate is $y=2x$, not $y=2x^2$. The hypotenuse is a straight line, not a parabola. And you integrate between 0 and 1. Draw a figure. It will help you understand.
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The function to integrate is $y=2x$, not $y=2x^2$. The hypotenuse is a straight line, not a parabola. And you integrate between 0 and 1. Draw a figure. It will help you understand.
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
add a comment |
The function to integrate is $y=2x$, not $y=2x^2$. The hypotenuse is a straight line, not a parabola. And you integrate between 0 and 1. Draw a figure. It will help you understand.
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
add a comment |
The function to integrate is $y=2x$, not $y=2x^2$. The hypotenuse is a straight line, not a parabola. And you integrate between 0 and 1. Draw a figure. It will help you understand.
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
The function to integrate is $y=2x$, not $y=2x^2$. The hypotenuse is a straight line, not a parabola. And you integrate between 0 and 1. Draw a figure. It will help you understand.
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
answered Nov 21 '18 at 7:08
Andrei
11.3k21026
11.3k21026
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
add a comment |
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
ok. i got it. thanks. i will not be measuring the area of triangle with y=2x^2.
– Hari Krishnan
Nov 21 '18 at 8:08
add a comment |
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