How to return letters from UTF-16

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-1

I need to return the letters in a word in alphabetical order. I got the following problem, I don't know how to return the letters from numbers, I tried to use String.fromCharCode() and charAt() but it did nothing.
I got:

function AlphabetSoup(str) { 



  let spl = str.split('');

let res = spl.map(order => order.charCodeAt()).sort((a,b) => b - a).reverse();



 return res;

}

So the result is [ 98, 99, 100, 101, 101, 111, 114, 116, 121 ]

asked Jan 3 at 4:35

Ilya Solodeev

please ask your question little bit clearly

– Muthusamy
Jan 3 at 4:38

How to change numbers in an array to the letters through utf 16

– Ilya Solodeev
Jan 3 at 4:43

add a comment |

-1

function AlphabetSoup(str) { 



  let spl = str.split('');

let res = spl.map(order => order.charCodeAt()).sort((a,b) => b - a).reverse();



 return res;

}

So the result is [ 98, 99, 100, 101, 101, 111, 114, 116, 121 ]

asked Jan 3 at 4:35

Ilya Solodeev

please ask your question little bit clearly

– Muthusamy
Jan 3 at 4:38

How to change numbers in an array to the letters through utf 16

– Ilya Solodeev
Jan 3 at 4:43

add a comment |

-1

function AlphabetSoup(str) { 



  let spl = str.split('');

let res = spl.map(order => order.charCodeAt()).sort((a,b) => b - a).reverse();



 return res;

}

So the result is [ 98, 99, 100, 101, 101, 111, 114, 116, 121 ]

asked Jan 3 at 4:35

Ilya Solodeev

function AlphabetSoup(str) { 



  let spl = str.split('');

let res = spl.map(order => order.charCodeAt()).sort((a,b) => b - a).reverse();



 return res;

}

So the result is [ 98, 99, 100, 101, 101, 111, 114, 116, 121 ]

javascript

asked Jan 3 at 4:35

Ilya Solodeev

asked Jan 3 at 4:35

Ilya Solodeev

asked Jan 3 at 4:35

Ilya Solodeev

asked Jan 3 at 4:35

Ilya Solodeev

asked Jan 3 at 4:35

Ilya Solodeev

please ask your question little bit clearly

– Muthusamy
Jan 3 at 4:38

How to change numbers in an array to the letters through utf 16

– Ilya Solodeev
Jan 3 at 4:43

add a comment |

please ask your question little bit clearly

– Muthusamy
Jan 3 at 4:38

How to change numbers in an array to the letters through utf 16

– Ilya Solodeev
Jan 3 at 4:43

please ask your question little bit clearly

– Muthusamy
Jan 3 at 4:38

How to change numbers in an array to the letters through utf 16

– Ilya Solodeev
Jan 3 at 4:43

add a comment |

2 Answers
2

active

oldest

votes

By default, .sort() already orders values by their UTF-16 string representation.

The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

If you were insistent upon using your proposed method, you could re-map the values back to their string representation using String.fromCharCode().

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

add a comment |

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

Of course, sort() be default does what you want so you could be less explicit (and more accurate) by doing return arr.sort().join('')

answered Jan 3 at 4:50

vol7ron

25.6k1687152

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

By default, .sort() already orders values by their UTF-16 string representation.

The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

If you were insistent upon using your proposed method, you could re-map the values back to their string representation using String.fromCharCode().

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

add a comment |

By default, .sort() already orders values by their UTF-16 string representation.

The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

If you were insistent upon using your proposed method, you could re-map the values back to their string representation using String.fromCharCode().

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

add a comment |

By default, .sort() already orders values by their UTF-16 string representation.

The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

If you were insistent upon using your proposed method, you could re-map the values back to their string representation using String.fromCharCode().

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

By default, .sort() already orders values by their UTF-16 string representation.

The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

If you were insistent upon using your proposed method, you could re-map the values back to their string representation using String.fromCharCode().

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

function AlphabetSoup(str) {

  return str.split('').sort();

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

function AlphabetSoup(str) {



  let spl = str.split('');

  let res = spl

    .map(order => order.charCodeAt())

    .sort((a, b) => a-b)

    .map(order => String.fromCharCode(order));



  return res;

}



var r = AlphabetSoup("HelloWorld");

console.log(r);

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

answered Jan 3 at 4:46

Tyler Roper

14.4k32142

add a comment |

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

Of course, sort() be default does what you want so you could be less explicit (and more accurate) by doing return arr.sort().join('')

answered Jan 3 at 4:50

vol7ron

25.6k1687152

add a comment |

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

Of course, sort() be default does what you want so you could be less explicit (and more accurate) by doing return arr.sort().join('')

answered Jan 3 at 4:50

vol7ron

25.6k1687152

add a comment |

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

Of course, sort() be default does what you want so you could be less explicit (and more accurate) by doing return arr.sort().join('')

answered Jan 3 at 4:50

vol7ron

25.6k1687152

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

Of course, sort() be default does what you want so you could be less explicit (and more accurate) by doing return arr.sort().join('')

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

console.log(AlphabetSoup('hello'))

console.log(AlphabetSoup2('hello'))



/* Given what you gave, you have to convert it back */

function AlphabetSoup(str) {

  let spl = str.split('');

  let res = spl.map(char => char.charCodeAt())

               .sort((a, b) => b - a)

               .reverse()

               .map(ascii=>String.fromCharCode(ascii))  // <-- convert back

               .join('');                               // <-- make it a string



  return res;

}





/* Of course string comparison natively works on ASCII values */

function AlphabetSoup2(str) {

  let arr = str.split('');

  return arr.sort((a, b) => b < a).join('');             // <-- notice the '<'

}

answered Jan 3 at 4:50

vol7ron

25.6k1687152

answered Jan 3 at 4:50

vol7ron

25.6k1687152

answered Jan 3 at 4:50

vol7ron

25.6k1687152

answered Jan 3 at 4:50

vol7ron

25.6k1687152

add a comment |

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