what is the length of this triangle?
$begingroup$
if sides a and b are 100m, and there is a right angle, then how long is side c?. By the way, I made it on paint quickly.
>--triangle link<--
I AM ONLY A 6TH GRADER SO PLEASE DO NOT PUT THINGS LIKE "Pythagorean theorem" AND "100√2" BECAUSE I WILL NOT UNDERSTAND
triangles
$endgroup$
add a comment |
$begingroup$
if sides a and b are 100m, and there is a right angle, then how long is side c?. By the way, I made it on paint quickly.
>--triangle link<--
I AM ONLY A 6TH GRADER SO PLEASE DO NOT PUT THINGS LIKE "Pythagorean theorem" AND "100√2" BECAUSE I WILL NOT UNDERSTAND
triangles
$endgroup$
add a comment |
$begingroup$
if sides a and b are 100m, and there is a right angle, then how long is side c?. By the way, I made it on paint quickly.
>--triangle link<--
I AM ONLY A 6TH GRADER SO PLEASE DO NOT PUT THINGS LIKE "Pythagorean theorem" AND "100√2" BECAUSE I WILL NOT UNDERSTAND
triangles
$endgroup$
if sides a and b are 100m, and there is a right angle, then how long is side c?. By the way, I made it on paint quickly.
>--triangle link<--
I AM ONLY A 6TH GRADER SO PLEASE DO NOT PUT THINGS LIKE "Pythagorean theorem" AND "100√2" BECAUSE I WILL NOT UNDERSTAND
triangles
triangles
edited Jan 31 at 21:52
Awesome Gamer 333
asked Jan 31 at 2:12


Awesome Gamer 333Awesome Gamer 333
14
14
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3 Answers
3
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oldest
votes
$begingroup$
I get $100sqrt2$ with the Pythagorean theorem.
$endgroup$
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
add a comment |
$begingroup$
To find the third side of a right triangle given two of them, you can use the Pythagorean Theorem given by:
$$a^2+b^2=c^2$$
Note that $c$ is the hypotenuse and $a$ and $b$ are the legs.
Your drawing indicates that you have the two legs so you can plug the values into the formula to find $c$.
$$(100)^2+(100)^2=c^2$$
$$10000+10000=c^2$$
$$c^2=20000$$
$$c=sqrt{20000}$$
$$c=100sqrt{2}$$
Just make sure you include meters as a unit.
I hope this helps, if you need any explanation of how I progressed between steps, let me know in the comments.
$endgroup$
add a comment |
$begingroup$
It is nice that you included a picture, but I would figure out that c is the hypotenuse anyway, as the hypotenuse is always longer than the other 2 sides. This is using the Pythagorean theorem.
To see this better you need to know the Pythagorean theorem:
Here is one shape that can be used to prove the theorem
You will see there that the assigned value for the hypotenuse of one of the 4 congruent triangles is c (and so will be the same for the others).
You should try using this to prove the theorem to figure out that $a^2+b^2=c^2$ where c is the hypotenuse (identifying the hypotenuse is important as it may not always be c).
In case you need a hint, but only after trying should you see the hint: try calculating the whole area in 2 different ways.
Then you can find the side c of your triangle by using the Pythagorean theorem. It's $100sqrt2$, which should agree with your answer.
$endgroup$
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I get $100sqrt2$ with the Pythagorean theorem.
$endgroup$
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
add a comment |
$begingroup$
I get $100sqrt2$ with the Pythagorean theorem.
$endgroup$
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
add a comment |
$begingroup$
I get $100sqrt2$ with the Pythagorean theorem.
$endgroup$
I get $100sqrt2$ with the Pythagorean theorem.
answered Jan 31 at 2:16
Chris CusterChris Custer
14.3k3827
14.3k3827
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
add a comment |
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
can you please explain that more clearly? I am only a 6th grader and have trouble understanding.
$endgroup$
– Awesome Gamer 333
Jan 31 at 2:17
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
$begingroup$
I drew a right triangle and called two sides $x$, the other $c$. Then the Pythagorean theorem says $2x^2=c^2$. Hence $c=sqrt2 x$. Finally, $x=100$.
$endgroup$
– Chris Custer
Jan 31 at 2:20
add a comment |
$begingroup$
To find the third side of a right triangle given two of them, you can use the Pythagorean Theorem given by:
$$a^2+b^2=c^2$$
Note that $c$ is the hypotenuse and $a$ and $b$ are the legs.
Your drawing indicates that you have the two legs so you can plug the values into the formula to find $c$.
$$(100)^2+(100)^2=c^2$$
$$10000+10000=c^2$$
$$c^2=20000$$
$$c=sqrt{20000}$$
$$c=100sqrt{2}$$
Just make sure you include meters as a unit.
I hope this helps, if you need any explanation of how I progressed between steps, let me know in the comments.
$endgroup$
add a comment |
$begingroup$
To find the third side of a right triangle given two of them, you can use the Pythagorean Theorem given by:
$$a^2+b^2=c^2$$
Note that $c$ is the hypotenuse and $a$ and $b$ are the legs.
Your drawing indicates that you have the two legs so you can plug the values into the formula to find $c$.
$$(100)^2+(100)^2=c^2$$
$$10000+10000=c^2$$
$$c^2=20000$$
$$c=sqrt{20000}$$
$$c=100sqrt{2}$$
Just make sure you include meters as a unit.
I hope this helps, if you need any explanation of how I progressed between steps, let me know in the comments.
$endgroup$
add a comment |
$begingroup$
To find the third side of a right triangle given two of them, you can use the Pythagorean Theorem given by:
$$a^2+b^2=c^2$$
Note that $c$ is the hypotenuse and $a$ and $b$ are the legs.
Your drawing indicates that you have the two legs so you can plug the values into the formula to find $c$.
$$(100)^2+(100)^2=c^2$$
$$10000+10000=c^2$$
$$c^2=20000$$
$$c=sqrt{20000}$$
$$c=100sqrt{2}$$
Just make sure you include meters as a unit.
I hope this helps, if you need any explanation of how I progressed between steps, let me know in the comments.
$endgroup$
To find the third side of a right triangle given two of them, you can use the Pythagorean Theorem given by:
$$a^2+b^2=c^2$$
Note that $c$ is the hypotenuse and $a$ and $b$ are the legs.
Your drawing indicates that you have the two legs so you can plug the values into the formula to find $c$.
$$(100)^2+(100)^2=c^2$$
$$10000+10000=c^2$$
$$c^2=20000$$
$$c=sqrt{20000}$$
$$c=100sqrt{2}$$
Just make sure you include meters as a unit.
I hope this helps, if you need any explanation of how I progressed between steps, let me know in the comments.
answered Jan 31 at 2:20
GnumbertesterGnumbertester
6771114
6771114
add a comment |
add a comment |
$begingroup$
It is nice that you included a picture, but I would figure out that c is the hypotenuse anyway, as the hypotenuse is always longer than the other 2 sides. This is using the Pythagorean theorem.
To see this better you need to know the Pythagorean theorem:
Here is one shape that can be used to prove the theorem
You will see there that the assigned value for the hypotenuse of one of the 4 congruent triangles is c (and so will be the same for the others).
You should try using this to prove the theorem to figure out that $a^2+b^2=c^2$ where c is the hypotenuse (identifying the hypotenuse is important as it may not always be c).
In case you need a hint, but only after trying should you see the hint: try calculating the whole area in 2 different ways.
Then you can find the side c of your triangle by using the Pythagorean theorem. It's $100sqrt2$, which should agree with your answer.
$endgroup$
add a comment |
$begingroup$
It is nice that you included a picture, but I would figure out that c is the hypotenuse anyway, as the hypotenuse is always longer than the other 2 sides. This is using the Pythagorean theorem.
To see this better you need to know the Pythagorean theorem:
Here is one shape that can be used to prove the theorem
You will see there that the assigned value for the hypotenuse of one of the 4 congruent triangles is c (and so will be the same for the others).
You should try using this to prove the theorem to figure out that $a^2+b^2=c^2$ where c is the hypotenuse (identifying the hypotenuse is important as it may not always be c).
In case you need a hint, but only after trying should you see the hint: try calculating the whole area in 2 different ways.
Then you can find the side c of your triangle by using the Pythagorean theorem. It's $100sqrt2$, which should agree with your answer.
$endgroup$
add a comment |
$begingroup$
It is nice that you included a picture, but I would figure out that c is the hypotenuse anyway, as the hypotenuse is always longer than the other 2 sides. This is using the Pythagorean theorem.
To see this better you need to know the Pythagorean theorem:
Here is one shape that can be used to prove the theorem
You will see there that the assigned value for the hypotenuse of one of the 4 congruent triangles is c (and so will be the same for the others).
You should try using this to prove the theorem to figure out that $a^2+b^2=c^2$ where c is the hypotenuse (identifying the hypotenuse is important as it may not always be c).
In case you need a hint, but only after trying should you see the hint: try calculating the whole area in 2 different ways.
Then you can find the side c of your triangle by using the Pythagorean theorem. It's $100sqrt2$, which should agree with your answer.
$endgroup$
It is nice that you included a picture, but I would figure out that c is the hypotenuse anyway, as the hypotenuse is always longer than the other 2 sides. This is using the Pythagorean theorem.
To see this better you need to know the Pythagorean theorem:
Here is one shape that can be used to prove the theorem
You will see there that the assigned value for the hypotenuse of one of the 4 congruent triangles is c (and so will be the same for the others).
You should try using this to prove the theorem to figure out that $a^2+b^2=c^2$ where c is the hypotenuse (identifying the hypotenuse is important as it may not always be c).
In case you need a hint, but only after trying should you see the hint: try calculating the whole area in 2 different ways.
Then you can find the side c of your triangle by using the Pythagorean theorem. It's $100sqrt2$, which should agree with your answer.
answered Jan 31 at 2:36


TheTroll73TheTroll73
83
83
add a comment |
add a comment |
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