Mixing
how to fix undefined index $user = $_GET['user']; [duplicate]
1
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
php
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
asked Nov 20 '18 at 5:50
yangmyyangmy
83
marked as duplicate by Progrock, Nigel Ren php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 20 '18 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
1
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
php
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
asked Nov 20 '18 at 5:50
yangmyyangmy
83
marked as duplicate by Progrock, Nigel Ren php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 20 '18 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 '18 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 '18 at 7:17
add a comment |
1
1
1
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
php
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
asked Nov 20 '18 at 5:50
yangmyyangmy
83
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
php
php
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
asked Nov 20 '18 at 5:50
yangmyyangmy
83
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
asked Nov 20 '18 at 5:50
yangmyyangmy
83
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
edited Nov 20 '18 at 6:08
akshaypjoshi
5421216
5421216
asked Nov 20 '18 at 5:50
yangmyyangmy
83
asked Nov 20 '18 at 5:50
yangmyyangmy
83
asked Nov 20 '18 at 5:50
yangmyyangmy
83
83
marked as duplicate by Progrock, Nigel Ren php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 20 '18 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Progrock, Nigel Ren php
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Nov 20 '18 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 '18 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 '18 at 7:17
add a comment |
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 '18 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 '18 at 7:17
1
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 '18 at 6:11
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 '18 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 '18 at 7:17
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 '18 at 7:17
add a comment |
3 Answers
3
active
oldest
votes
0
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
add a comment |
0
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
add a comment |
-1
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
answered Nov 20 '18 at 6:22
HoweeHowee
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
add a comment |
0
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
add a comment |
0
0
0
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
answered Nov 20 '18 at 7:15
F5 BuddyF5 Buddy
3604
3604
add a comment |
add a comment |
0
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
add a comment |
0
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
add a comment |
0
0
0
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
answered Nov 20 '18 at 6:15
pawansgi92pawansgi92
324112
324112
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
add a comment |
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 '18 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 '18 at 17:22
add a comment |
-1
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
answered Nov 20 '18 at 6:22
HoweeHowee
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
add a comment |
-1
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
answered Nov 20 '18 at 6:22
HoweeHowee
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
add a comment |
-1
-1
-1
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
answered Nov 20 '18 at 6:22
HoweeHowee
1
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
answered Nov 20 '18 at 6:22
HoweeHowee
1
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
edited Nov 22 '18 at 21:15
Bryce Siedschlaw
2,99911829
2,99911829
answered Nov 20 '18 at 6:22
HoweeHowee
1
answered Nov 20 '18 at 6:22
HoweeHowee
1
answered Nov 20 '18 at 6:22
HoweeHowee
1
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
add a comment |
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
2
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 '18 at 7:20
add a comment |
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 '18 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 '18 at 7:17