Mixing
How to write regular expression to match a pattern in java?
I've the following java string:
"Java (simple) _New=AB_U748490_JAVA47BYH"
.. and I'm using the following regular expression:
"_New=[A-Z]{2}_(w{7})_(JAVA.+)";
Problem: it always returns false. But why?
java regex spring-mvc
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
asked Nov 19 '18 at 20:02
JeenaJeena
72
add a comment |
I've the following java string:
"Java (simple) _New=AB_U748490_JAVA47BYH"
.. and I'm using the following regular expression:
"_New=[A-Z]{2}_(w{7})_(JAVA.+)";
Problem: it always returns false. But why?
java regex spring-mvc
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
asked Nov 19 '18 at 20:02
JeenaJeena
72
add a comment |
I've the following java string:
"Java (simple) _New=AB_U748490_JAVA47BYH"
.. and I'm using the following regular expression:
"_New=[A-Z]{2}_(w{7})_(JAVA.+)";
Problem: it always returns false. But why?
java regex spring-mvc
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
asked Nov 19 '18 at 20:02
JeenaJeena
72
I've the following java string:
"Java (simple) _New=AB_U748490_JAVA47BYH"
.. and I'm using the following regular expression:
"_New=[A-Z]{2}_(w{7})_(JAVA.+)";
Problem: it always returns false. But why?
java regex spring-mvc
java regex spring-mvc
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
asked Nov 19 '18 at 20:02
JeenaJeena
72
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
asked Nov 19 '18 at 20:02
JeenaJeena
72
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
edited Nov 19 '18 at 20:06
Rene Knop
1,3403622
1,3403622
asked Nov 19 '18 at 20:02
JeenaJeena
72
asked Nov 19 '18 at 20:02
JeenaJeena
72
asked Nov 19 '18 at 20:02
JeenaJeena
72
72
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The way you have written your regex will work with Matcher.find() because find searches the regex in whole input string anywhere.
If you want to make your regex to match fully, you need to modify your regex little and prepend .* in the beginning of regex something like this,
.*_New=[A-Z]{2}_(\w{7})_(JAVA.+)
Notice how in java you need to escape character to \
Try with this code and it will print Matches
public static void main(String args) {
String s = "Java (simple) _New=AB_U748490_JAVA47BYH";
Pattern p = Pattern.compile(".*_New=[A-Z]{2}_(\w{7})_(JAVA.+)");
Matcher m = p.matcher(s);
if (m.matches()) {
System.out.println("Matches");
} else {
System.out.println("Didn't match");
}
}
Or alternatively, you can use find() method on Matcher object if you don't want to change your regex.
Hope that helps.
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The way you have written your regex will work with Matcher.find() because find searches the regex in whole input string anywhere.
If you want to make your regex to match fully, you need to modify your regex little and prepend .* in the beginning of regex something like this,
.*_New=[A-Z]{2}_(\w{7})_(JAVA.+)
Notice how in java you need to escape character to \
Try with this code and it will print Matches
public static void main(String args) {
String s = "Java (simple) _New=AB_U748490_JAVA47BYH";
Pattern p = Pattern.compile(".*_New=[A-Z]{2}_(\w{7})_(JAVA.+)");
Matcher m = p.matcher(s);
if (m.matches()) {
System.out.println("Matches");
} else {
System.out.println("Didn't match");
}
}
Or alternatively, you can use find() method on Matcher object if you don't want to change your regex.
Hope that helps.
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
add a comment |
The way you have written your regex will work with Matcher.find() because find searches the regex in whole input string anywhere.
If you want to make your regex to match fully, you need to modify your regex little and prepend .* in the beginning of regex something like this,
.*_New=[A-Z]{2}_(\w{7})_(JAVA.+)
Notice how in java you need to escape character to \
Try with this code and it will print Matches
public static void main(String args) {
String s = "Java (simple) _New=AB_U748490_JAVA47BYH";
Pattern p = Pattern.compile(".*_New=[A-Z]{2}_(\w{7})_(JAVA.+)");
Matcher m = p.matcher(s);
if (m.matches()) {
System.out.println("Matches");
} else {
System.out.println("Didn't match");
}
}
Or alternatively, you can use find() method on Matcher object if you don't want to change your regex.
Hope that helps.
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
add a comment |
The way you have written your regex will work with Matcher.find() because find searches the regex in whole input string anywhere.
If you want to make your regex to match fully, you need to modify your regex little and prepend .* in the beginning of regex something like this,
.*_New=[A-Z]{2}_(\w{7})_(JAVA.+)
Notice how in java you need to escape character to \
Try with this code and it will print Matches
public static void main(String args) {
String s = "Java (simple) _New=AB_U748490_JAVA47BYH";
Pattern p = Pattern.compile(".*_New=[A-Z]{2}_(\w{7})_(JAVA.+)");
Matcher m = p.matcher(s);
if (m.matches()) {
System.out.println("Matches");
} else {
System.out.println("Didn't match");
}
}
Or alternatively, you can use find() method on Matcher object if you don't want to change your regex.
Hope that helps.
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
The way you have written your regex will work with Matcher.find() because find searches the regex in whole input string anywhere.
If you want to make your regex to match fully, you need to modify your regex little and prepend .* in the beginning of regex something like this,
.*_New=[A-Z]{2}_(\w{7})_(JAVA.+)
Notice how in java you need to escape character to \
Try with this code and it will print Matches
public static void main(String args) {
String s = "Java (simple) _New=AB_U748490_JAVA47BYH";
Pattern p = Pattern.compile(".*_New=[A-Z]{2}_(\w{7})_(JAVA.+)");
Matcher m = p.matcher(s);
if (m.matches()) {
System.out.println("Matches");
} else {
System.out.println("Didn't match");
}
}
Or alternatively, you can use find() method on Matcher object if you don't want to change your regex.
Hope that helps.
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
edited Nov 19 '18 at 21:32
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
answered Nov 19 '18 at 20:09
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,6522827
5,6522827
add a comment |
add a comment |
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