Mixing
Javascript percentage of winning algorithm
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
add a comment |
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 '18 at 22:04
2
Hint: 1/3 =0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)
– Bergi
Nov 19 '18 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 '18 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.
– Richardissimo
Nov 19 '18 at 22:39
add a comment |
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
javascript algorithm
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
edited Nov 19 '18 at 22:07
PixelArtie
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
asked Nov 19 '18 at 21:59
PixelArtiePixelArtie
43
43
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 '18 at 22:04
2
Hint: 1/3 =0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)
– Bergi
Nov 19 '18 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 '18 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.
– Richardissimo
Nov 19 '18 at 22:39
add a comment |
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 '18 at 22:04
2
Hint: 1/3 =0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)
– Bergi
Nov 19 '18 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 '18 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.
– Richardissimo
Nov 19 '18 at 22:39
1
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 '18 at 22:04
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 '18 at 22:04
2
2
Hint: 1/3 =
0.3333…, 1/200 = 0.005 (compared to 50% = 0.5, 20% = 0.2 in the existing code)– Bergi
Nov 19 '18 at 22:05
Hint: 1/3 =
0.3333…, 1/200 = 0.005 (compared to 50% = 0.5, 20% = 0.2 in the existing code)– Bergi
Nov 19 '18 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 '18 at 22:21
@Bergi thanks. I figured out
– PixelArtie
Nov 19 '18 at 22:21
1
1
< means less than. So if (this.d < 0.005) means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in the else clause of the <0.3333, so nobody will ever win the big prize.– Richardissimo
Nov 19 '18 at 22:39
< means less than. So if (this.d < 0.005) means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in the else clause of the <0.3333, so nobody will ever win the big prize.– Richardissimo
Nov 19 '18 at 22:39
add a comment |
1 Answer
1
active
oldest
votes
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
add a comment |
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1 Answer
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1 Answer
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oldest
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votes
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
add a comment |
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
add a comment |
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
answered Nov 19 '18 at 23:25
KonowyKonowy
339420
339420
add a comment |
add a comment |
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1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 '18 at 22:04
2
Hint: 1/3 =
0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)– Bergi
Nov 19 '18 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 '18 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.– Richardissimo
Nov 19 '18 at 22:39