Mixing
Do different Web Hosts give different responses under same conditions?
I am working on a Android app. Therefore I'm creating an Login/Register Aktivity.I'm using JsonRequest(Volley) to get the Information stored in a SQL Data-base.Furthermore I wrote some php files(for Testing Purpose) to create a JSONObject as the Server Response.
Everything seems to work but only for some webhosts. What i mean by that is that the same Android Studio Code and the same php Code once work fine and in the other case Output Errors.
My Test php Code uploaded via FileManagers
<?php
$myObj=new stdClass();
$myObj->name = "Test";
$myJSON = json_encode($myObj);
echo $myJSON;
?>
my Java Code
RequestQueue requestQueue= Volley.newRequestQueue(this);
JsonObjectRequest jsonObjectRequest=new JsonObjectRequest(Request.Method.GET,url,null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
String success=response.getString("name");
Toast.makeText(getApplicationContext(),success, Toast.LENGTH_SHORT).show();
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "ErrorCatch"+e.toString(), Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), "ErrorResponse"+error.toString(), Toast.LENGTH_LONG).show();
}
});
requestQueue.add(jsonObjectRequest);
Using one Webhost I get the Correct Toast including the stored Information from the Server. Using another Webhost I get an Error :"Java.lang.String cannot be converted to JSONObject" which I find Odd since I'm doing the same Stuff.
Thank you in advance for your help.
java php
android-studio web-hosting asked Nov 19 '18 at 22:08
R.K.R.K.
1
add a comment |
I am working on a Android app. Therefore I'm creating an Login/Register Aktivity.I'm using JsonRequest(Volley) to get the Information stored in a SQL Data-base.Furthermore I wrote some php files(for Testing Purpose) to create a JSONObject as the Server Response.
Everything seems to work but only for some webhosts. What i mean by that is that the same Android Studio Code and the same php Code once work fine and in the other case Output Errors.
My Test php Code uploaded via FileManagers
<?php
$myObj=new stdClass();
$myObj->name = "Test";
$myJSON = json_encode($myObj);
echo $myJSON;
?>
my Java Code
RequestQueue requestQueue= Volley.newRequestQueue(this);
JsonObjectRequest jsonObjectRequest=new JsonObjectRequest(Request.Method.GET,url,null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
String success=response.getString("name");
Toast.makeText(getApplicationContext(),success, Toast.LENGTH_SHORT).show();
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "ErrorCatch"+e.toString(), Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), "ErrorResponse"+error.toString(), Toast.LENGTH_LONG).show();
}
});
requestQueue.add(jsonObjectRequest);
Using one Webhost I get the Correct Toast including the stored Information from the Server. Using another Webhost I get an Error :"Java.lang.String cannot be converted to JSONObject" which I find Odd since I'm doing the same Stuff.
Thank you in advance for your help.
java php
android-studio web-hosting asked Nov 19 '18 at 22:08
R.K.R.K.
1
Possibly some other server configuration or php version. Maybe the faulty server has a very old php version, where json_encode is not yet implemented and throws an error. Try to access the php via browser or any api-client tester software to see what the return is.
– Jeff
Nov 19 '18 at 22:14
also remove the trailing?>in your php script. In some cases sending additional space/tab/linefeed produces errors in receiving environments.
– Jeff
Nov 19 '18 at 22:18
Thanks for your answer.One webhost is using php Version 7.0.19 and the other one php Version 7.1 which, as far as i know, both should include Jason_encode. Furthermore if i go to the url both Output "{"name":"Test"}" which seems like the correct and expected echo.
– R.K.
Nov 20 '18 at 8:35
add a comment |
I am working on a Android app. Therefore I'm creating an Login/Register Aktivity.I'm using JsonRequest(Volley) to get the Information stored in a SQL Data-base.Furthermore I wrote some php files(for Testing Purpose) to create a JSONObject as the Server Response.
Everything seems to work but only for some webhosts. What i mean by that is that the same Android Studio Code and the same php Code once work fine and in the other case Output Errors.
My Test php Code uploaded via FileManagers
<?php
$myObj=new stdClass();
$myObj->name = "Test";
$myJSON = json_encode($myObj);
echo $myJSON;
?>
my Java Code
RequestQueue requestQueue= Volley.newRequestQueue(this);
JsonObjectRequest jsonObjectRequest=new JsonObjectRequest(Request.Method.GET,url,null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
String success=response.getString("name");
Toast.makeText(getApplicationContext(),success, Toast.LENGTH_SHORT).show();
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "ErrorCatch"+e.toString(), Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), "ErrorResponse"+error.toString(), Toast.LENGTH_LONG).show();
}
});
requestQueue.add(jsonObjectRequest);
Using one Webhost I get the Correct Toast including the stored Information from the Server. Using another Webhost I get an Error :"Java.lang.String cannot be converted to JSONObject" which I find Odd since I'm doing the same Stuff.
Thank you in advance for your help.
java php
android-studio web-hosting asked Nov 19 '18 at 22:08
R.K.R.K.
1
I am working on a Android app. Therefore I'm creating an Login/Register Aktivity.I'm using JsonRequest(Volley) to get the Information stored in a SQL Data-base.Furthermore I wrote some php files(for Testing Purpose) to create a JSONObject as the Server Response.
Everything seems to work but only for some webhosts. What i mean by that is that the same Android Studio Code and the same php Code once work fine and in the other case Output Errors.
My Test php Code uploaded via FileManagers
<?php
$myObj=new stdClass();
$myObj->name = "Test";
$myJSON = json_encode($myObj);
echo $myJSON;
?>
my Java Code
RequestQueue requestQueue= Volley.newRequestQueue(this);
JsonObjectRequest jsonObjectRequest=new JsonObjectRequest(Request.Method.GET,url,null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
String success=response.getString("name");
Toast.makeText(getApplicationContext(),success, Toast.LENGTH_SHORT).show();
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "ErrorCatch"+e.toString(), Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), "ErrorResponse"+error.toString(), Toast.LENGTH_LONG).show();
}
});
requestQueue.add(jsonObjectRequest);
Using one Webhost I get the Correct Toast including the stored Information from the Server. Using another Webhost I get an Error :"Java.lang.String cannot be converted to JSONObject" which I find Odd since I'm doing the same Stuff.
Thank you in advance for your help.
java php
android-studio web-hosting java php
android-studio web-hosting asked Nov 19 '18 at 22:08
R.K.R.K.
1
asked Nov 19 '18 at 22:08
R.K.R.K.
1
asked Nov 19 '18 at 22:08
R.K.R.K.
1
asked Nov 19 '18 at 22:08
R.K.R.K.
1
asked Nov 19 '18 at 22:08
R.K.R.K.
1
1
Possibly some other server configuration or php version. Maybe the faulty server has a very old php version, where json_encode is not yet implemented and throws an error. Try to access the php via browser or any api-client tester software to see what the return is.
– Jeff
Nov 19 '18 at 22:14
also remove the trailing?>in your php script. In some cases sending additional space/tab/linefeed produces errors in receiving environments.
– Jeff
Nov 19 '18 at 22:18
Thanks for your answer.One webhost is using php Version 7.0.19 and the other one php Version 7.1 which, as far as i know, both should include Jason_encode. Furthermore if i go to the url both Output "{"name":"Test"}" which seems like the correct and expected echo.
– R.K.
Nov 20 '18 at 8:35
add a comment |
Possibly some other server configuration or php version. Maybe the faulty server has a very old php version, where json_encode is not yet implemented and throws an error. Try to access the php via browser or any api-client tester software to see what the return is.
– Jeff
Nov 19 '18 at 22:14
also remove the trailing?>in your php script. In some cases sending additional space/tab/linefeed produces errors in receiving environments.
– Jeff
Nov 19 '18 at 22:18
Thanks for your answer.One webhost is using php Version 7.0.19 and the other one php Version 7.1 which, as far as i know, both should include Jason_encode. Furthermore if i go to the url both Output "{"name":"Test"}" which seems like the correct and expected echo.
– R.K.
Nov 20 '18 at 8:35
Possibly some other server configuration or php version. Maybe the faulty server has a very old php version, where json_encode is not yet implemented and throws an error. Try to access the php via browser or any api-client tester software to see what the return is.
– Jeff
Nov 19 '18 at 22:14
Possibly some other server configuration or php version. Maybe the faulty server has a very old php version, where json_encode is not yet implemented and throws an error. Try to access the php via browser or any api-client tester software to see what the return is.
– Jeff
Nov 19 '18 at 22:14
also remove the trailing
?> in your php script. In some cases sending additional space/tab/linefeed produces errors in receiving environments.– Jeff
Nov 19 '18 at 22:18
also remove the trailing
?> in your php script. In some cases sending additional space/tab/linefeed produces errors in receiving environments.– Jeff
Nov 19 '18 at 22:18
Thanks for your answer.One webhost is using php Version 7.0.19 and the other one php Version 7.1 which, as far as i know, both should include Jason_encode. Furthermore if i go to the url both Output "{"name":"Test"}" which seems like the correct and expected echo.
– R.K.
Nov 20 '18 at 8:35
Thanks for your answer.One webhost is using php Version 7.0.19 and the other one php Version 7.1 which, as far as i know, both should include Jason_encode. Furthermore if i go to the url both Output "{"name":"Test"}" which seems like the correct and expected echo.
– R.K.
Nov 20 '18 at 8:35
add a comment |
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Possibly some other server configuration or php version. Maybe the faulty server has a very old php version, where json_encode is not yet implemented and throws an error. Try to access the php via browser or any api-client tester software to see what the return is.
– Jeff
Nov 19 '18 at 22:14
also remove the trailing
?>in your php script. In some cases sending additional space/tab/linefeed produces errors in receiving environments.– Jeff
Nov 19 '18 at 22:18
Thanks for your answer.One webhost is using php Version 7.0.19 and the other one php Version 7.1 which, as far as i know, both should include Jason_encode. Furthermore if i go to the url both Output "{"name":"Test"}" which seems like the correct and expected echo.
– R.K.
Nov 20 '18 at 8:35