Mixing
JacksonMapper Date deserialization with UTC time zone fails with given format
I know there are many duplicate questions about the same issue, however, I wasn't able to deserialize given date format into java.util.Date object. The client api I am using returns date fields with 6 digit combined with milliseconds and nanoseconds.
- 2016-12-08T20:09:05.508883Z
- 2016-12-08T20:09:05.527Z
Sometimes it includes nano seconds sometimes not. I tried to follow deserialization examples from jackson-databind library itself however couldn't found a workaround. Say this is the example json blob
{
"id": "68e6a28f-ae28-4788-8d4f-5ab4e5e5ae08",
"created_at": "2016-12-08T20:09:05.508883Z",
"done_at": "2016-12-08T20:09:05.527Z"
}
Entity.java
@Data
@JsonIgnoreProperties(ignoreUnknown = true)
public class OrderResponse {
private String id;
@JsonProperty("created_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date createdAt;
@JsonProperty("done_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date doneAt;
}
If I only use format yyyy-MM-dd'T'HH:mm:ss jackson mapper deserializes with timezone coming from jvm itself. But I need to use UTC format and I tried also implementing custom deserializer and serializer which doesn't work as well. My question is java.util.Date correct object type? Additionally, I also tried to create my own object mapper with registering new JavaTimeModule() but it didn't work.
Thanks for help.
java jackson fasterxml java-date
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
add a comment |
I know there are many duplicate questions about the same issue, however, I wasn't able to deserialize given date format into java.util.Date object. The client api I am using returns date fields with 6 digit combined with milliseconds and nanoseconds.
- 2016-12-08T20:09:05.508883Z
- 2016-12-08T20:09:05.527Z
Sometimes it includes nano seconds sometimes not. I tried to follow deserialization examples from jackson-databind library itself however couldn't found a workaround. Say this is the example json blob
{
"id": "68e6a28f-ae28-4788-8d4f-5ab4e5e5ae08",
"created_at": "2016-12-08T20:09:05.508883Z",
"done_at": "2016-12-08T20:09:05.527Z"
}
Entity.java
@Data
@JsonIgnoreProperties(ignoreUnknown = true)
public class OrderResponse {
private String id;
@JsonProperty("created_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date createdAt;
@JsonProperty("done_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date doneAt;
}
If I only use format yyyy-MM-dd'T'HH:mm:ss jackson mapper deserializes with timezone coming from jvm itself. But I need to use UTC format and I tried also implementing custom deserializer and serializer which doesn't work as well. My question is java.util.Date correct object type? Additionally, I also tried to create my own object mapper with registering new JavaTimeModule() but it didn't work.
Thanks for help.
java jackson fasterxml java-date
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
...Your problem mostly stems from the fact that you're usingjava.util.Date, which should be put out of its misery. Are you able to switch to a more appropriate type, likejava.time.Instant(although this will require loading an additional jackson module for best support)?
– Clockwork-Muse
Nov 19 '18 at 22:29
@Clockwork-Muse yeah I can move from Date to Instant however I wasn't able to parse given format to Instant as well.
– quartaela
Nov 19 '18 at 22:31
add a comment |
I know there are many duplicate questions about the same issue, however, I wasn't able to deserialize given date format into java.util.Date object. The client api I am using returns date fields with 6 digit combined with milliseconds and nanoseconds.
- 2016-12-08T20:09:05.508883Z
- 2016-12-08T20:09:05.527Z
Sometimes it includes nano seconds sometimes not. I tried to follow deserialization examples from jackson-databind library itself however couldn't found a workaround. Say this is the example json blob
{
"id": "68e6a28f-ae28-4788-8d4f-5ab4e5e5ae08",
"created_at": "2016-12-08T20:09:05.508883Z",
"done_at": "2016-12-08T20:09:05.527Z"
}
Entity.java
@Data
@JsonIgnoreProperties(ignoreUnknown = true)
public class OrderResponse {
private String id;
@JsonProperty("created_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date createdAt;
@JsonProperty("done_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date doneAt;
}
If I only use format yyyy-MM-dd'T'HH:mm:ss jackson mapper deserializes with timezone coming from jvm itself. But I need to use UTC format and I tried also implementing custom deserializer and serializer which doesn't work as well. My question is java.util.Date correct object type? Additionally, I also tried to create my own object mapper with registering new JavaTimeModule() but it didn't work.
Thanks for help.
java jackson fasterxml java-date
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
I know there are many duplicate questions about the same issue, however, I wasn't able to deserialize given date format into java.util.Date object. The client api I am using returns date fields with 6 digit combined with milliseconds and nanoseconds.
- 2016-12-08T20:09:05.508883Z
- 2016-12-08T20:09:05.527Z
Sometimes it includes nano seconds sometimes not. I tried to follow deserialization examples from jackson-databind library itself however couldn't found a workaround. Say this is the example json blob
{
"id": "68e6a28f-ae28-4788-8d4f-5ab4e5e5ae08",
"created_at": "2016-12-08T20:09:05.508883Z",
"done_at": "2016-12-08T20:09:05.527Z"
}
Entity.java
@Data
@JsonIgnoreProperties(ignoreUnknown = true)
public class OrderResponse {
private String id;
@JsonProperty("created_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date createdAt;
@JsonProperty("done_at")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss'*'", timezone = "UTC")
private Date doneAt;
}
If I only use format yyyy-MM-dd'T'HH:mm:ss jackson mapper deserializes with timezone coming from jvm itself. But I need to use UTC format and I tried also implementing custom deserializer and serializer which doesn't work as well. My question is java.util.Date correct object type? Additionally, I also tried to create my own object mapper with registering new JavaTimeModule() but it didn't work.
Thanks for help.
java jackson fasterxml java-date
java jackson fasterxml java-date
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
asked Nov 19 '18 at 22:14
quartaelaquartaela
1,02283265
1,02283265
...Your problem mostly stems from the fact that you're usingjava.util.Date, which should be put out of its misery. Are you able to switch to a more appropriate type, likejava.time.Instant(although this will require loading an additional jackson module for best support)?
– Clockwork-Muse
Nov 19 '18 at 22:29
@Clockwork-Muse yeah I can move from Date to Instant however I wasn't able to parse given format to Instant as well.
– quartaela
Nov 19 '18 at 22:31
add a comment |
...Your problem mostly stems from the fact that you're usingjava.util.Date, which should be put out of its misery. Are you able to switch to a more appropriate type, likejava.time.Instant(although this will require loading an additional jackson module for best support)?
– Clockwork-Muse
Nov 19 '18 at 22:29
@Clockwork-Muse yeah I can move from Date to Instant however I wasn't able to parse given format to Instant as well.
– quartaela
Nov 19 '18 at 22:31
...Your problem mostly stems from the fact that you're using
java.util.Date, which should be put out of its misery. Are you able to switch to a more appropriate type, like java.time.Instant (although this will require loading an additional jackson module for best support)?– Clockwork-Muse
Nov 19 '18 at 22:29
...Your problem mostly stems from the fact that you're using
java.util.Date, which should be put out of its misery. Are you able to switch to a more appropriate type, like java.time.Instant (although this will require loading an additional jackson module for best support)?– Clockwork-Muse
Nov 19 '18 at 22:29
@Clockwork-Muse yeah I can move from Date to Instant however I wasn't able to parse given format to Instant as well.
– quartaela
Nov 19 '18 at 22:31
@Clockwork-Muse yeah I can move from Date to Instant however I wasn't able to parse given format to Instant as well.
– quartaela
Nov 19 '18 at 22:31
add a comment |
2 Answers
2
active
oldest
votes
I found that java.time.format.DateTimeFormatter has ISO_INSTANT format type which supports the format I was looking for.
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html#ISO_INSTANT
Basically, I wrote my custom deserializer
public class CustomInstantDeserializer extends JsonDeserializer<Instant> {
private DateTimeFormatter fmt = DateTimeFormatter.ISO_INSTANT.withZone(ZoneOffset.UTC);
@Override
public Instant deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return Instant.from(fmt.parse(p.getText()));
}
}
with @JsonDeserialize annotation on related field.
@JsonProperty("created_at")
@JsonDeserialize(using = CustomInstantDeserializer.class)
private Instant createdAt;
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
add a comment |
try to use @JsonSetter:
@JsonSetter("createdAt")
public Date setCreatedAt(String date){
SimpleDateFormat sdfDate = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sdfDate.setTimeZone(TimeZone.getTimeZone("UTC"));
return sdfDate.parse(date);
}
doneAt should be similar
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
hey @slimane thanks for the response, however, I am gettingjava.text.ParseException: Unparseable date:exception.
– quartaela
Nov 19 '18 at 22:48
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I found that java.time.format.DateTimeFormatter has ISO_INSTANT format type which supports the format I was looking for.
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html#ISO_INSTANT
Basically, I wrote my custom deserializer
public class CustomInstantDeserializer extends JsonDeserializer<Instant> {
private DateTimeFormatter fmt = DateTimeFormatter.ISO_INSTANT.withZone(ZoneOffset.UTC);
@Override
public Instant deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return Instant.from(fmt.parse(p.getText()));
}
}
with @JsonDeserialize annotation on related field.
@JsonProperty("created_at")
@JsonDeserialize(using = CustomInstantDeserializer.class)
private Instant createdAt;
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
add a comment |
I found that java.time.format.DateTimeFormatter has ISO_INSTANT format type which supports the format I was looking for.
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html#ISO_INSTANT
Basically, I wrote my custom deserializer
public class CustomInstantDeserializer extends JsonDeserializer<Instant> {
private DateTimeFormatter fmt = DateTimeFormatter.ISO_INSTANT.withZone(ZoneOffset.UTC);
@Override
public Instant deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return Instant.from(fmt.parse(p.getText()));
}
}
with @JsonDeserialize annotation on related field.
@JsonProperty("created_at")
@JsonDeserialize(using = CustomInstantDeserializer.class)
private Instant createdAt;
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
add a comment |
I found that java.time.format.DateTimeFormatter has ISO_INSTANT format type which supports the format I was looking for.
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html#ISO_INSTANT
Basically, I wrote my custom deserializer
public class CustomInstantDeserializer extends JsonDeserializer<Instant> {
private DateTimeFormatter fmt = DateTimeFormatter.ISO_INSTANT.withZone(ZoneOffset.UTC);
@Override
public Instant deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return Instant.from(fmt.parse(p.getText()));
}
}
with @JsonDeserialize annotation on related field.
@JsonProperty("created_at")
@JsonDeserialize(using = CustomInstantDeserializer.class)
private Instant createdAt;
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
I found that java.time.format.DateTimeFormatter has ISO_INSTANT format type which supports the format I was looking for.
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html#ISO_INSTANT
Basically, I wrote my custom deserializer
public class CustomInstantDeserializer extends JsonDeserializer<Instant> {
private DateTimeFormatter fmt = DateTimeFormatter.ISO_INSTANT.withZone(ZoneOffset.UTC);
@Override
public Instant deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return Instant.from(fmt.parse(p.getText()));
}
}
with @JsonDeserialize annotation on related field.
@JsonProperty("created_at")
@JsonDeserialize(using = CustomInstantDeserializer.class)
private Instant createdAt;
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
answered Nov 19 '18 at 23:10
quartaelaquartaela
1,02283265
1,02283265
add a comment |
add a comment |
try to use @JsonSetter:
@JsonSetter("createdAt")
public Date setCreatedAt(String date){
SimpleDateFormat sdfDate = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sdfDate.setTimeZone(TimeZone.getTimeZone("UTC"));
return sdfDate.parse(date);
}
doneAt should be similar
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
hey @slimane thanks for the response, however, I am gettingjava.text.ParseException: Unparseable date:exception.
– quartaela
Nov 19 '18 at 22:48
add a comment |
try to use @JsonSetter:
@JsonSetter("createdAt")
public Date setCreatedAt(String date){
SimpleDateFormat sdfDate = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sdfDate.setTimeZone(TimeZone.getTimeZone("UTC"));
return sdfDate.parse(date);
}
doneAt should be similar
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
hey @slimane thanks for the response, however, I am gettingjava.text.ParseException: Unparseable date:exception.
– quartaela
Nov 19 '18 at 22:48
add a comment |
try to use @JsonSetter:
@JsonSetter("createdAt")
public Date setCreatedAt(String date){
SimpleDateFormat sdfDate = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sdfDate.setTimeZone(TimeZone.getTimeZone("UTC"));
return sdfDate.parse(date);
}
doneAt should be similar
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
try to use @JsonSetter:
@JsonSetter("createdAt")
public Date setCreatedAt(String date){
SimpleDateFormat sdfDate = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sdfDate.setTimeZone(TimeZone.getTimeZone("UTC"));
return sdfDate.parse(date);
}
doneAt should be similar
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
edited Nov 20 '18 at 9:14
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
answered Nov 19 '18 at 22:28
stackerstacker
1,10925
1,10925
hey @slimane thanks for the response, however, I am gettingjava.text.ParseException: Unparseable date:exception.
– quartaela
Nov 19 '18 at 22:48
add a comment |
hey @slimane thanks for the response, however, I am gettingjava.text.ParseException: Unparseable date:exception.
– quartaela
Nov 19 '18 at 22:48
hey @slimane thanks for the response, however, I am getting
java.text.ParseException: Unparseable date: exception.– quartaela
Nov 19 '18 at 22:48
hey @slimane thanks for the response, however, I am getting
java.text.ParseException: Unparseable date: exception.– quartaela
Nov 19 '18 at 22:48
add a comment |
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...Your problem mostly stems from the fact that you're using
java.util.Date, which should be put out of its misery. Are you able to switch to a more appropriate type, likejava.time.Instant(although this will require loading an additional jackson module for best support)?– Clockwork-Muse
Nov 19 '18 at 22:29
@Clockwork-Muse yeah I can move from Date to Instant however I wasn't able to parse given format to Instant as well.
– quartaela
Nov 19 '18 at 22:31