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1
I have an avatar command that allows you to look up a member to get their avatar in Discord. The problem is that anytime I run the command with any arguments (implying you wanna find someone else's avatar, it sends a blank embed. It works fine sending the message author avatar, but not anyone else's.
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
Any help would be greatly appreciated, thank you.
javascript node.js discord discord.js
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
add a comment |
1
I have an avatar command that allows you to look up a member to get their avatar in Discord. The problem is that anytime I run the command with any arguments (implying you wanna find someone else's avatar, it sends a blank embed. It works fine sending the message author avatar, but not anyone else's.
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
Any help would be greatly appreciated, thank you.
javascript node.js discord discord.js
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
add a comment |
1
1
1
2
I have an avatar command that allows you to look up a member to get their avatar in Discord. The problem is that anytime I run the command with any arguments (implying you wanna find someone else's avatar, it sends a blank embed. It works fine sending the message author avatar, but not anyone else's.
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
Any help would be greatly appreciated, thank you.
javascript node.js discord discord.js
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
I have an avatar command that allows you to look up a member to get their avatar in Discord. The problem is that anytime I run the command with any arguments (implying you wanna find someone else's avatar, it sends a blank embed. It works fine sending the message author avatar, but not anyone else's.
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
Any help would be greatly appreciated, thank you.
javascript node.js discord discord.js
javascript node.js discord discord.js
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
edited Nov 20 '18 at 17:35
Federico Grandi
2,81321127
2,81321127
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
asked Nov 20 '18 at 4:01
Adam KerikAdam Kerik
5318
5318
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
2
It's not working because you're trying to use GuildMember.displayAvatarURL, but that is a User property: try using memb.user.displayAvatarURL:
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.user.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
add a comment |
0
Instead of making it so you type in the users' name, just make the command take a tagged user like so;
exports.run = (client, message, args) => {
if(!message.mentions.users.first()) return no.mention.function();
let member = message.mentions.users.first();
let memberAvatar = member.avatarURL;
let embed = new Discord.RichEmbed()
.setColor(client.config.embedColor)
.setImage(memberAvatar);
message.channel.send(embed);
}
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
It's not working because you're trying to use GuildMember.displayAvatarURL, but that is a User property: try using memb.user.displayAvatarURL:
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.user.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
add a comment |
2
It's not working because you're trying to use GuildMember.displayAvatarURL, but that is a User property: try using memb.user.displayAvatarURL:
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.user.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
add a comment |
2
2
2
It's not working because you're trying to use GuildMember.displayAvatarURL, but that is a User property: try using memb.user.displayAvatarURL:
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.user.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
It's not working because you're trying to use GuildMember.displayAvatarURL, but that is a User property: try using memb.user.displayAvatarURL:
exports.run = (client, message, args) => {
let mem = args.join(' ');
let memb = message.guild.members.find(m => [m.displayName.toLowerCase(), m.user.username.toLowerCase()].includes(mem.toLowerCase()));
let embed = new Discord.RichEmbed()
.setImage(memb ? memb.user.displayAvatarURL : message.author.displayAvatarURL)
.setColor(client.config.embedColor);
message.channel.send(embed);
}
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
answered Nov 20 '18 at 17:33
Federico GrandiFederico Grandi
2,81321127
2,81321127
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
add a comment |
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Thank you so much! I really appreciate the answer as I was stumped. You, my friend, are a miracle worker.
– Adam Kerik
Nov 20 '18 at 17:48
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
Happy to hear that it worked :D
– Federico Grandi
Nov 20 '18 at 18:46
add a comment |
0
Instead of making it so you type in the users' name, just make the command take a tagged user like so;
exports.run = (client, message, args) => {
if(!message.mentions.users.first()) return no.mention.function();
let member = message.mentions.users.first();
let memberAvatar = member.avatarURL;
let embed = new Discord.RichEmbed()
.setColor(client.config.embedColor)
.setImage(memberAvatar);
message.channel.send(embed);
}
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
add a comment |
0
Instead of making it so you type in the users' name, just make the command take a tagged user like so;
exports.run = (client, message, args) => {
if(!message.mentions.users.first()) return no.mention.function();
let member = message.mentions.users.first();
let memberAvatar = member.avatarURL;
let embed = new Discord.RichEmbed()
.setColor(client.config.embedColor)
.setImage(memberAvatar);
message.channel.send(embed);
}
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
add a comment |
0
0
0
Instead of making it so you type in the users' name, just make the command take a tagged user like so;
exports.run = (client, message, args) => {
if(!message.mentions.users.first()) return no.mention.function();
let member = message.mentions.users.first();
let memberAvatar = member.avatarURL;
let embed = new Discord.RichEmbed()
.setColor(client.config.embedColor)
.setImage(memberAvatar);
message.channel.send(embed);
}
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
Instead of making it so you type in the users' name, just make the command take a tagged user like so;
exports.run = (client, message, args) => {
if(!message.mentions.users.first()) return no.mention.function();
let member = message.mentions.users.first();
let memberAvatar = member.avatarURL;
let embed = new Discord.RichEmbed()
.setColor(client.config.embedColor)
.setImage(memberAvatar);
message.channel.send(embed);
}
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
answered Nov 20 '18 at 13:52
ethamitcethamitc
193111
193111
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
add a comment |
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
Thank you for your answer, but I specfically am avoiding that so I do not have to ping people.
– Adam Kerik
Nov 20 '18 at 17:47
add a comment |
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