How to prove that {$sin(x) , sin(2x) , sin(3x) ,…,sin(nx)$} is independent in $mathbb{R}$? [duplicate]












0












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This question already has an answer here:




  • How to prove that the set ${sin(x),sin(2x),…,sin(mx)}$ is linearly independent? [closed]

    5 answers





Prove that {$sin(x) , sin(2x) , sin(3x) ,...,sin(nx)$} is independent in $mathbb{R}$




my trial :



we know that the Wronsekian shouldn't be $0$ to get the trivial solution and thus they are independent. its not trivial to show that $ W not = 0$



W =



begin{vmatrix}
(1)sin(x) & (1)sin(2x) & (1)sin(3x) & ... & (1)sin(nx) \
(1)cos(x) & (2)cos(2x) & (3)cos(3x) & ... & (n)cos(nx) \
-(1)^2sin(x) & -(2)^2sin(2x) & -(3)^2sin(3x) & ... & -(n)^2sin(nx) \
-(1)^3cos(x) & -(2)^3cos(2x) & -(3)^3cos(3x) & ... & -(n)^3cos(nx) \
end{vmatrix}



and so on. it looks like Vandermonde matrix but i cant prove that and so we conclude that its $Wnot =0$










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marked as duplicate by Martin R, TheSimpliFire, 5xum, Shubham Johri, Ahmad Bazzi Jan 3 at 9:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • $begingroup$
    Note that $LaTeX$ commands $sin$ sin and $cos$ cos for future reference.
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:09










  • $begingroup$
    thanks i updated it
    $endgroup$
    – Mather
    Jan 3 at 9:10










  • $begingroup$
    this is ODE class i don't know whats the topic there but it doesn't like ODE class
    $endgroup$
    – Mather
    Jan 3 at 9:13










  • $begingroup$
    @MartinR And of course that one deserves closure as well
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:13






  • 1




    $begingroup$
    @Mather The answer I have given does not use any theorem. It is extremely elementary.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 9:18
















0












$begingroup$



This question already has an answer here:




  • How to prove that the set ${sin(x),sin(2x),…,sin(mx)}$ is linearly independent? [closed]

    5 answers





Prove that {$sin(x) , sin(2x) , sin(3x) ,...,sin(nx)$} is independent in $mathbb{R}$




my trial :



we know that the Wronsekian shouldn't be $0$ to get the trivial solution and thus they are independent. its not trivial to show that $ W not = 0$



W =



begin{vmatrix}
(1)sin(x) & (1)sin(2x) & (1)sin(3x) & ... & (1)sin(nx) \
(1)cos(x) & (2)cos(2x) & (3)cos(3x) & ... & (n)cos(nx) \
-(1)^2sin(x) & -(2)^2sin(2x) & -(3)^2sin(3x) & ... & -(n)^2sin(nx) \
-(1)^3cos(x) & -(2)^3cos(2x) & -(3)^3cos(3x) & ... & -(n)^3cos(nx) \
end{vmatrix}



and so on. it looks like Vandermonde matrix but i cant prove that and so we conclude that its $Wnot =0$










share|cite|improve this question











$endgroup$



marked as duplicate by Martin R, TheSimpliFire, 5xum, Shubham Johri, Ahmad Bazzi Jan 3 at 9:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • $begingroup$
    Note that $LaTeX$ commands $sin$ sin and $cos$ cos for future reference.
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:09










  • $begingroup$
    thanks i updated it
    $endgroup$
    – Mather
    Jan 3 at 9:10










  • $begingroup$
    this is ODE class i don't know whats the topic there but it doesn't like ODE class
    $endgroup$
    – Mather
    Jan 3 at 9:13










  • $begingroup$
    @MartinR And of course that one deserves closure as well
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:13






  • 1




    $begingroup$
    @Mather The answer I have given does not use any theorem. It is extremely elementary.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 9:18














0












0








0





$begingroup$



This question already has an answer here:




  • How to prove that the set ${sin(x),sin(2x),…,sin(mx)}$ is linearly independent? [closed]

    5 answers





Prove that {$sin(x) , sin(2x) , sin(3x) ,...,sin(nx)$} is independent in $mathbb{R}$




my trial :



we know that the Wronsekian shouldn't be $0$ to get the trivial solution and thus they are independent. its not trivial to show that $ W not = 0$



W =



begin{vmatrix}
(1)sin(x) & (1)sin(2x) & (1)sin(3x) & ... & (1)sin(nx) \
(1)cos(x) & (2)cos(2x) & (3)cos(3x) & ... & (n)cos(nx) \
-(1)^2sin(x) & -(2)^2sin(2x) & -(3)^2sin(3x) & ... & -(n)^2sin(nx) \
-(1)^3cos(x) & -(2)^3cos(2x) & -(3)^3cos(3x) & ... & -(n)^3cos(nx) \
end{vmatrix}



and so on. it looks like Vandermonde matrix but i cant prove that and so we conclude that its $Wnot =0$










share|cite|improve this question











$endgroup$





This question already has an answer here:




  • How to prove that the set ${sin(x),sin(2x),…,sin(mx)}$ is linearly independent? [closed]

    5 answers





Prove that {$sin(x) , sin(2x) , sin(3x) ,...,sin(nx)$} is independent in $mathbb{R}$




my trial :



we know that the Wronsekian shouldn't be $0$ to get the trivial solution and thus they are independent. its not trivial to show that $ W not = 0$



W =



begin{vmatrix}
(1)sin(x) & (1)sin(2x) & (1)sin(3x) & ... & (1)sin(nx) \
(1)cos(x) & (2)cos(2x) & (3)cos(3x) & ... & (n)cos(nx) \
-(1)^2sin(x) & -(2)^2sin(2x) & -(3)^2sin(3x) & ... & -(n)^2sin(nx) \
-(1)^3cos(x) & -(2)^3cos(2x) & -(3)^3cos(3x) & ... & -(n)^3cos(nx) \
end{vmatrix}



and so on. it looks like Vandermonde matrix but i cant prove that and so we conclude that its $Wnot =0$





This question already has an answer here:




  • How to prove that the set ${sin(x),sin(2x),…,sin(mx)}$ is linearly independent? [closed]

    5 answers








ordinary-differential-equations






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share|cite|improve this question













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share|cite|improve this question








edited Jan 3 at 11:00









wilsonw

467315




467315










asked Jan 3 at 9:07









Mather Mather

1947




1947




marked as duplicate by Martin R, TheSimpliFire, 5xum, Shubham Johri, Ahmad Bazzi Jan 3 at 9:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Martin R, TheSimpliFire, 5xum, Shubham Johri, Ahmad Bazzi Jan 3 at 9:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • $begingroup$
    Note that $LaTeX$ commands $sin$ sin and $cos$ cos for future reference.
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:09










  • $begingroup$
    thanks i updated it
    $endgroup$
    – Mather
    Jan 3 at 9:10










  • $begingroup$
    this is ODE class i don't know whats the topic there but it doesn't like ODE class
    $endgroup$
    – Mather
    Jan 3 at 9:13










  • $begingroup$
    @MartinR And of course that one deserves closure as well
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:13






  • 1




    $begingroup$
    @Mather The answer I have given does not use any theorem. It is extremely elementary.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 9:18


















  • $begingroup$
    Note that $LaTeX$ commands $sin$ sin and $cos$ cos for future reference.
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:09










  • $begingroup$
    thanks i updated it
    $endgroup$
    – Mather
    Jan 3 at 9:10










  • $begingroup$
    this is ODE class i don't know whats the topic there but it doesn't like ODE class
    $endgroup$
    – Mather
    Jan 3 at 9:13










  • $begingroup$
    @MartinR And of course that one deserves closure as well
    $endgroup$
    – TheSimpliFire
    Jan 3 at 9:13






  • 1




    $begingroup$
    @Mather The answer I have given does not use any theorem. It is extremely elementary.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 9:18
















$begingroup$
Note that $LaTeX$ commands $sin$ sin and $cos$ cos for future reference.
$endgroup$
– TheSimpliFire
Jan 3 at 9:09




$begingroup$
Note that $LaTeX$ commands $sin$ sin and $cos$ cos for future reference.
$endgroup$
– TheSimpliFire
Jan 3 at 9:09












$begingroup$
thanks i updated it
$endgroup$
– Mather
Jan 3 at 9:10




$begingroup$
thanks i updated it
$endgroup$
– Mather
Jan 3 at 9:10












$begingroup$
this is ODE class i don't know whats the topic there but it doesn't like ODE class
$endgroup$
– Mather
Jan 3 at 9:13




$begingroup$
this is ODE class i don't know whats the topic there but it doesn't like ODE class
$endgroup$
– Mather
Jan 3 at 9:13












$begingroup$
@MartinR And of course that one deserves closure as well
$endgroup$
– TheSimpliFire
Jan 3 at 9:13




$begingroup$
@MartinR And of course that one deserves closure as well
$endgroup$
– TheSimpliFire
Jan 3 at 9:13




1




1




$begingroup$
@Mather The answer I have given does not use any theorem. It is extremely elementary.
$endgroup$
– Kavi Rama Murthy
Jan 3 at 9:18




$begingroup$
@Mather The answer I have given does not use any theorem. It is extremely elementary.
$endgroup$
– Kavi Rama Murthy
Jan 3 at 9:18










1 Answer
1






active

oldest

votes


















2












$begingroup$

If $sum_{j=1}^{n} c_j sin (jx)$=0 for all $x$ you can prove that each $c_k=0$ by multiplying both sides by $sin(kx)$ and and integrating from $-pi$ to $pi$. Use the fact that $int_{-pi}^{pi} sin(jx)sin (kx), dx =0$ if $j neq k$. This proves the stronger result that the sequence is independent on $[-pi,pi]$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    This question has been asked and answered before ...
    $endgroup$
    – Martin R
    Jan 3 at 9:13










  • $begingroup$
    thank you but is there an answer related to ODE and wronsekian
    $endgroup$
    – Mather
    Jan 3 at 9:16










  • $begingroup$
    @Mather please emphasize in your question that you would like a Wronsekian oriented answer.
    $endgroup$
    – Ahmad Bazzi
    Jan 3 at 9:18










  • $begingroup$
    the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
    $endgroup$
    – Mather
    Jan 3 at 9:58








  • 1




    $begingroup$
    @Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 10:00


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

If $sum_{j=1}^{n} c_j sin (jx)$=0 for all $x$ you can prove that each $c_k=0$ by multiplying both sides by $sin(kx)$ and and integrating from $-pi$ to $pi$. Use the fact that $int_{-pi}^{pi} sin(jx)sin (kx), dx =0$ if $j neq k$. This proves the stronger result that the sequence is independent on $[-pi,pi]$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    This question has been asked and answered before ...
    $endgroup$
    – Martin R
    Jan 3 at 9:13










  • $begingroup$
    thank you but is there an answer related to ODE and wronsekian
    $endgroup$
    – Mather
    Jan 3 at 9:16










  • $begingroup$
    @Mather please emphasize in your question that you would like a Wronsekian oriented answer.
    $endgroup$
    – Ahmad Bazzi
    Jan 3 at 9:18










  • $begingroup$
    the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
    $endgroup$
    – Mather
    Jan 3 at 9:58








  • 1




    $begingroup$
    @Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 10:00
















2












$begingroup$

If $sum_{j=1}^{n} c_j sin (jx)$=0 for all $x$ you can prove that each $c_k=0$ by multiplying both sides by $sin(kx)$ and and integrating from $-pi$ to $pi$. Use the fact that $int_{-pi}^{pi} sin(jx)sin (kx), dx =0$ if $j neq k$. This proves the stronger result that the sequence is independent on $[-pi,pi]$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    This question has been asked and answered before ...
    $endgroup$
    – Martin R
    Jan 3 at 9:13










  • $begingroup$
    thank you but is there an answer related to ODE and wronsekian
    $endgroup$
    – Mather
    Jan 3 at 9:16










  • $begingroup$
    @Mather please emphasize in your question that you would like a Wronsekian oriented answer.
    $endgroup$
    – Ahmad Bazzi
    Jan 3 at 9:18










  • $begingroup$
    the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
    $endgroup$
    – Mather
    Jan 3 at 9:58








  • 1




    $begingroup$
    @Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 10:00














2












2








2





$begingroup$

If $sum_{j=1}^{n} c_j sin (jx)$=0 for all $x$ you can prove that each $c_k=0$ by multiplying both sides by $sin(kx)$ and and integrating from $-pi$ to $pi$. Use the fact that $int_{-pi}^{pi} sin(jx)sin (kx), dx =0$ if $j neq k$. This proves the stronger result that the sequence is independent on $[-pi,pi]$.






share|cite|improve this answer











$endgroup$



If $sum_{j=1}^{n} c_j sin (jx)$=0 for all $x$ you can prove that each $c_k=0$ by multiplying both sides by $sin(kx)$ and and integrating from $-pi$ to $pi$. Use the fact that $int_{-pi}^{pi} sin(jx)sin (kx), dx =0$ if $j neq k$. This proves the stronger result that the sequence is independent on $[-pi,pi]$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Jan 3 at 10:02

























answered Jan 3 at 9:12









Kavi Rama MurthyKavi Rama Murthy

53.8k32055




53.8k32055












  • $begingroup$
    This question has been asked and answered before ...
    $endgroup$
    – Martin R
    Jan 3 at 9:13










  • $begingroup$
    thank you but is there an answer related to ODE and wronsekian
    $endgroup$
    – Mather
    Jan 3 at 9:16










  • $begingroup$
    @Mather please emphasize in your question that you would like a Wronsekian oriented answer.
    $endgroup$
    – Ahmad Bazzi
    Jan 3 at 9:18










  • $begingroup$
    the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
    $endgroup$
    – Mather
    Jan 3 at 9:58








  • 1




    $begingroup$
    @Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 10:00


















  • $begingroup$
    This question has been asked and answered before ...
    $endgroup$
    – Martin R
    Jan 3 at 9:13










  • $begingroup$
    thank you but is there an answer related to ODE and wronsekian
    $endgroup$
    – Mather
    Jan 3 at 9:16










  • $begingroup$
    @Mather please emphasize in your question that you would like a Wronsekian oriented answer.
    $endgroup$
    – Ahmad Bazzi
    Jan 3 at 9:18










  • $begingroup$
    the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
    $endgroup$
    – Mather
    Jan 3 at 9:58








  • 1




    $begingroup$
    @Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
    $endgroup$
    – Kavi Rama Murthy
    Jan 3 at 10:00
















$begingroup$
This question has been asked and answered before ...
$endgroup$
– Martin R
Jan 3 at 9:13




$begingroup$
This question has been asked and answered before ...
$endgroup$
– Martin R
Jan 3 at 9:13












$begingroup$
thank you but is there an answer related to ODE and wronsekian
$endgroup$
– Mather
Jan 3 at 9:16




$begingroup$
thank you but is there an answer related to ODE and wronsekian
$endgroup$
– Mather
Jan 3 at 9:16












$begingroup$
@Mather please emphasize in your question that you would like a Wronsekian oriented answer.
$endgroup$
– Ahmad Bazzi
Jan 3 at 9:18




$begingroup$
@Mather please emphasize in your question that you would like a Wronsekian oriented answer.
$endgroup$
– Ahmad Bazzi
Jan 3 at 9:18












$begingroup$
the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
$endgroup$
– Mather
Jan 3 at 9:58






$begingroup$
the solution is simple as they mentioned above , yet the integral above proves that they are independent only in $ [-pi,pi] $ right ? can we do that for $Re$ in a similar way ?
$endgroup$
– Mather
Jan 3 at 9:58






1




1




$begingroup$
@Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
$endgroup$
– Kavi Rama Murthy
Jan 3 at 10:00




$begingroup$
@Mather Independent on a subset of $mathbb R$ implies indepedence on all of $mathbb R$.
$endgroup$
– Kavi Rama Murthy
Jan 3 at 10:00



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