Mixing
Principal Disjunctive form of the following
I have to calculate the PDNF and PCNF of the following expression
$$(P longleftrightarrow Q) longleftrightarrow (P longleftrightarrow Q)$$
As it is a tautology so it will only have PDNF. I'm currently stuck at expanding this given equation as it has a huge expansion with many terms. Any simpler way possible ?
Thank you
discrete-mathematics boolean-algebra conjunctive-normal-form disjunctive-normal-form
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
add a comment |
I have to calculate the PDNF and PCNF of the following expression
$$(P longleftrightarrow Q) longleftrightarrow (P longleftrightarrow Q)$$
As it is a tautology so it will only have PDNF. I'm currently stuck at expanding this given equation as it has a huge expansion with many terms. Any simpler way possible ?
Thank you
discrete-mathematics boolean-algebra conjunctive-normal-form disjunctive-normal-form
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
It is not necessary to expand. As you said, the formula is a tautology, is true for any choice of P, Q. So PDNF is PQ+P'Q+PQ'+P'Q' (or in any notation you use).
– user376343
Jan 3 at 19:53
add a comment |
I have to calculate the PDNF and PCNF of the following expression
$$(P longleftrightarrow Q) longleftrightarrow (P longleftrightarrow Q)$$
As it is a tautology so it will only have PDNF. I'm currently stuck at expanding this given equation as it has a huge expansion with many terms. Any simpler way possible ?
Thank you
discrete-mathematics boolean-algebra conjunctive-normal-form disjunctive-normal-form
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
I have to calculate the PDNF and PCNF of the following expression
$$(P longleftrightarrow Q) longleftrightarrow (P longleftrightarrow Q)$$
As it is a tautology so it will only have PDNF. I'm currently stuck at expanding this given equation as it has a huge expansion with many terms. Any simpler way possible ?
Thank you
discrete-mathematics boolean-algebra conjunctive-normal-form disjunctive-normal-form
discrete-mathematics boolean-algebra conjunctive-normal-form disjunctive-normal-form
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
edited Jan 1 at 16:32
Arturo Magidin
261k32585906
261k32585906
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
asked Jan 1 at 7:22
Naman SoodNaman Sood
1
1
It is not necessary to expand. As you said, the formula is a tautology, is true for any choice of P, Q. So PDNF is PQ+P'Q+PQ'+P'Q' (or in any notation you use).
– user376343
Jan 3 at 19:53
add a comment |
It is not necessary to expand. As you said, the formula is a tautology, is true for any choice of P, Q. So PDNF is PQ+P'Q+PQ'+P'Q' (or in any notation you use).
– user376343
Jan 3 at 19:53
It is not necessary to expand. As you said, the formula is a tautology, is true for any choice of P, Q. So PDNF is PQ+P'Q+PQ'+P'Q' (or in any notation you use).
– user376343
Jan 3 at 19:53
It is not necessary to expand. As you said, the formula is a tautology, is true for any choice of P, Q. So PDNF is PQ+P'Q+PQ'+P'Q' (or in any notation you use).
– user376343
Jan 3 at 19:53
add a comment |
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It is not necessary to expand. As you said, the formula is a tautology, is true for any choice of P, Q. So PDNF is PQ+P'Q+PQ'+P'Q' (or in any notation you use).
– user376343
Jan 3 at 19:53