Sequelize Postgres - Handling concurrent request












0















When concurrent request is made for below code, two transaction executed concurrently.




  1. First update (soft delete columns)

  2. Then inserts rows


For two transactions due to concurrent request, first two updates executes and then rows get inserted from both the transactions. How to resolve this.



execute(aid, id, d) {
const _self = this;
this.db.transaction({autocommit: false, isolationLevel: this.db.Transaction.ISOLATION_LEVELS.SERIALIZABLE},
function (t)
{
_self.modal.destroy({
where: {
aid : aid
}
})
.then((result) => {
let promises = ;

for(let i=0; i<data.length; i++) {
promises.push(new Promise(function(resolve, reject) {
_self.modal.create({
val: d[i].val,
id: id,
}).then((s) => {
let hold =
for(let j=0; j<data[i].hold.length; j++) {
hold.push(_self.addDist(id, aid, s.id, d[i].hold[j]))
}
Promise.all(hold).then(() => {
resolve();
})
}).error(error => {
// error
});
}));

}
return Promise.all(promises);
}).then(() => {
_self.modal.findOne({
where: {
id: id,
},
include: [{}]
}).then(e => {
//success
}).catch(error => {
console.log(error);
});
})

}).catch(function (error)
{
console.log('rolling back as got error ', error);

});









share|improve this question





























    0















    When concurrent request is made for below code, two transaction executed concurrently.




    1. First update (soft delete columns)

    2. Then inserts rows


    For two transactions due to concurrent request, first two updates executes and then rows get inserted from both the transactions. How to resolve this.



    execute(aid, id, d) {
    const _self = this;
    this.db.transaction({autocommit: false, isolationLevel: this.db.Transaction.ISOLATION_LEVELS.SERIALIZABLE},
    function (t)
    {
    _self.modal.destroy({
    where: {
    aid : aid
    }
    })
    .then((result) => {
    let promises = ;

    for(let i=0; i<data.length; i++) {
    promises.push(new Promise(function(resolve, reject) {
    _self.modal.create({
    val: d[i].val,
    id: id,
    }).then((s) => {
    let hold =
    for(let j=0; j<data[i].hold.length; j++) {
    hold.push(_self.addDist(id, aid, s.id, d[i].hold[j]))
    }
    Promise.all(hold).then(() => {
    resolve();
    })
    }).error(error => {
    // error
    });
    }));

    }
    return Promise.all(promises);
    }).then(() => {
    _self.modal.findOne({
    where: {
    id: id,
    },
    include: [{}]
    }).then(e => {
    //success
    }).catch(error => {
    console.log(error);
    });
    })

    }).catch(function (error)
    {
    console.log('rolling back as got error ', error);

    });









    share|improve this question



























      0












      0








      0








      When concurrent request is made for below code, two transaction executed concurrently.




      1. First update (soft delete columns)

      2. Then inserts rows


      For two transactions due to concurrent request, first two updates executes and then rows get inserted from both the transactions. How to resolve this.



      execute(aid, id, d) {
      const _self = this;
      this.db.transaction({autocommit: false, isolationLevel: this.db.Transaction.ISOLATION_LEVELS.SERIALIZABLE},
      function (t)
      {
      _self.modal.destroy({
      where: {
      aid : aid
      }
      })
      .then((result) => {
      let promises = ;

      for(let i=0; i<data.length; i++) {
      promises.push(new Promise(function(resolve, reject) {
      _self.modal.create({
      val: d[i].val,
      id: id,
      }).then((s) => {
      let hold =
      for(let j=0; j<data[i].hold.length; j++) {
      hold.push(_self.addDist(id, aid, s.id, d[i].hold[j]))
      }
      Promise.all(hold).then(() => {
      resolve();
      })
      }).error(error => {
      // error
      });
      }));

      }
      return Promise.all(promises);
      }).then(() => {
      _self.modal.findOne({
      where: {
      id: id,
      },
      include: [{}]
      }).then(e => {
      //success
      }).catch(error => {
      console.log(error);
      });
      })

      }).catch(function (error)
      {
      console.log('rolling back as got error ', error);

      });









      share|improve this question
















      When concurrent request is made for below code, two transaction executed concurrently.




      1. First update (soft delete columns)

      2. Then inserts rows


      For two transactions due to concurrent request, first two updates executes and then rows get inserted from both the transactions. How to resolve this.



      execute(aid, id, d) {
      const _self = this;
      this.db.transaction({autocommit: false, isolationLevel: this.db.Transaction.ISOLATION_LEVELS.SERIALIZABLE},
      function (t)
      {
      _self.modal.destroy({
      where: {
      aid : aid
      }
      })
      .then((result) => {
      let promises = ;

      for(let i=0; i<data.length; i++) {
      promises.push(new Promise(function(resolve, reject) {
      _self.modal.create({
      val: d[i].val,
      id: id,
      }).then((s) => {
      let hold =
      for(let j=0; j<data[i].hold.length; j++) {
      hold.push(_self.addDist(id, aid, s.id, d[i].hold[j]))
      }
      Promise.all(hold).then(() => {
      resolve();
      })
      }).error(error => {
      // error
      });
      }));

      }
      return Promise.all(promises);
      }).then(() => {
      _self.modal.findOne({
      where: {
      id: id,
      },
      include: [{}]
      }).then(e => {
      //success
      }).catch(error => {
      console.log(error);
      });
      })

      }).catch(function (error)
      {
      console.log('rolling back as got error ', error);

      });






      postgresql sequelize.js






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      edited Nov 20 '18 at 13:54







      Rehan

















      asked Nov 20 '18 at 13:36









      RehanRehan

      1216




      1216
























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          we need to define transaction type as mentioned below and it works well.
          type: this.db.Transaction.TYPES.EXCLUSIVE






          share|improve this answer























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            1 Answer
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            0














            we need to define transaction type as mentioned below and it works well.
            type: this.db.Transaction.TYPES.EXCLUSIVE






            share|improve this answer




























              0














              we need to define transaction type as mentioned below and it works well.
              type: this.db.Transaction.TYPES.EXCLUSIVE






              share|improve this answer


























                0












                0








                0







                we need to define transaction type as mentioned below and it works well.
                type: this.db.Transaction.TYPES.EXCLUSIVE






                share|improve this answer













                we need to define transaction type as mentioned below and it works well.
                type: this.db.Transaction.TYPES.EXCLUSIVE







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 28 '18 at 12:58









                RehanRehan

                1216




                1216






























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