using scanner and delimeter

I need to scan a series of lines from a .txt file that looks like this picture
to make an output like the following: "this output

Here is my code:

Scanner scan = new Scanner(new File("C:\a1.txt"));

String wordbuffer="";



while(scan.hasNext()) {

   scan.useDelimiter("\Z");

   wordbuffer+=scan.next();

   System.out.println(wordbuffer);



   if(scan.next==" "){

       wordbuffer="";

   }

}

scan.close();

edited Nov 20 '18 at 20:10

asked Nov 20 '18 at 19:36

Djordje Milošević

154

1) Don't change delimiter between hasNext() and next(). --- 2) Since input is one character per line, including a space on a blank line, use nextLine(), not next(), to read lines.

– Andreas
Nov 20 '18 at 19:38

1

You forgot to ask a question.

– achAmháin
Nov 20 '18 at 19:38

Why did you believe Z (The end of the input but for the final terminator, if any) would be a good delimiter here?

– Andreas
Nov 20 '18 at 19:41

please do not post a screenshot of text - hard to read and even harder to copy... (and blocked in some environments)

– Carlos Heuberger
Nov 20 '18 at 20:42

@CarlosHeuberger okay,thanks on advice :)

– Djordje Milošević
Nov 21 '18 at 17:36

add a comment |

I need to scan a series of lines from a .txt file that looks like this picture
to make an output like the following: "this output

Here is my code:

Scanner scan = new Scanner(new File("C:\a1.txt"));

String wordbuffer="";



while(scan.hasNext()) {

   scan.useDelimiter("\Z");

   wordbuffer+=scan.next();

   System.out.println(wordbuffer);



   if(scan.next==" "){

       wordbuffer="";

   }

}

scan.close();

edited Nov 20 '18 at 20:10

asked Nov 20 '18 at 19:36

Djordje Milošević

154

1) Don't change delimiter between hasNext() and next(). --- 2) Since input is one character per line, including a space on a blank line, use nextLine(), not next(), to read lines.

– Andreas
Nov 20 '18 at 19:38

1

You forgot to ask a question.

– achAmháin
Nov 20 '18 at 19:38

Why did you believe Z (The end of the input but for the final terminator, if any) would be a good delimiter here?

– Andreas
Nov 20 '18 at 19:41

please do not post a screenshot of text - hard to read and even harder to copy... (and blocked in some environments)

– Carlos Heuberger
Nov 20 '18 at 20:42

@CarlosHeuberger okay,thanks on advice :)

– Djordje Milošević
Nov 21 '18 at 17:36

add a comment |

I need to scan a series of lines from a .txt file that looks like this picture
to make an output like the following: "this output

Here is my code:

Scanner scan = new Scanner(new File("C:\a1.txt"));

String wordbuffer="";



while(scan.hasNext()) {

   scan.useDelimiter("\Z");

   wordbuffer+=scan.next();

   System.out.println(wordbuffer);



   if(scan.next==" "){

       wordbuffer="";

   }

}

scan.close();

edited Nov 20 '18 at 20:10

asked Nov 20 '18 at 19:36

Djordje Milošević

154

I need to scan a series of lines from a .txt file that looks like this picture
to make an output like the following: "this output

Here is my code:

Scanner scan = new Scanner(new File("C:\a1.txt"));

String wordbuffer="";



while(scan.hasNext()) {

   scan.useDelimiter("\Z");

   wordbuffer+=scan.next();

   System.out.println(wordbuffer);



   if(scan.next==" "){

       wordbuffer="";

   }

}

scan.close();

java java.util.scanner

edited Nov 20 '18 at 20:10

asked Nov 20 '18 at 19:36

Djordje Milošević

154

edited Nov 20 '18 at 20:10

asked Nov 20 '18 at 19:36

Djordje Milošević

154

edited Nov 20 '18 at 20:10

asked Nov 20 '18 at 19:36

Djordje Milošević

154

asked Nov 20 '18 at 19:36

Djordje Milošević

154

asked Nov 20 '18 at 19:36

Djordje Milošević

154

1) Don't change delimiter between hasNext() and next(). --- 2) Since input is one character per line, including a space on a blank line, use nextLine(), not next(), to read lines.

– Andreas
Nov 20 '18 at 19:38

1

You forgot to ask a question.

– achAmháin
Nov 20 '18 at 19:38

Why did you believe Z (The end of the input but for the final terminator, if any) would be a good delimiter here?

– Andreas
Nov 20 '18 at 19:41

please do not post a screenshot of text - hard to read and even harder to copy... (and blocked in some environments)

– Carlos Heuberger
Nov 20 '18 at 20:42

@CarlosHeuberger okay,thanks on advice :)

– Djordje Milošević
Nov 21 '18 at 17:36

add a comment |

1) Don't change delimiter between hasNext() and next(). --- 2) Since input is one character per line, including a space on a blank line, use nextLine(), not next(), to read lines.

– Andreas
Nov 20 '18 at 19:38

1

You forgot to ask a question.

– achAmháin
Nov 20 '18 at 19:38

Why did you believe Z (The end of the input but for the final terminator, if any) would be a good delimiter here?

– Andreas
Nov 20 '18 at 19:41

please do not post a screenshot of text - hard to read and even harder to copy... (and blocked in some environments)

– Carlos Heuberger
Nov 20 '18 at 20:42

@CarlosHeuberger okay,thanks on advice :)

– Djordje Milošević
Nov 21 '18 at 17:36

1) Don't change delimiter between hasNext() and next(). --- 2) Since input is one character per line, including a space on a blank line, use nextLine(), not next(), to read lines.

– Andreas
Nov 20 '18 at 19:38

You forgot to ask a question.

– achAmháin
Nov 20 '18 at 19:38

Why did you believe Z (The end of the input but for the final terminator, if any) would be a good delimiter here?

– Andreas
Nov 20 '18 at 19:41

please do not post a screenshot of text - hard to read and even harder to copy... (and blocked in some environments)

– Carlos Heuberger
Nov 20 '18 at 20:42

@CarlosHeuberger okay,thanks on advice :)

– Djordje Milošević
Nov 21 '18 at 17:36

add a comment |

1 Answer
1

active

oldest

votes

You can try the following:

Add:

import java.io.FileReader;

import java.io.IOException;

import java.util.*;

Code:

public static void main(String args) throws IOException {             

    Scanner in = new Scanner(new FileReader("C:\a.txt"));

    StringBuilder sb = new StringBuilder();

    while(in.hasNext()) {

        String s=in.nextLine();

        if (s.equals(""))               

           sb.append(System.lineSeparator());

        else

            sb.append(s);           

    }

    in.close();

    System.out.println( sb.toString());

    }

Output:

stack 

o2 

flow

edited Nov 20 '18 at 20:38

answered Nov 20 '18 at 19:51

Nehorai

1,014314

sorry dude, it was my mistake, SO format my string, i edited now

– Djordje Milošević
Nov 20 '18 at 20:13

@DjordjeMilošević See update

– Nehorai
Nov 20 '18 at 20:38

Yeahh it works, thanks a lot dude :)

– Djordje Milošević
Nov 20 '18 at 20:46

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You can try the following:

Add:

import java.io.FileReader;

import java.io.IOException;

import java.util.*;

Code:

public static void main(String args) throws IOException {             

    Scanner in = new Scanner(new FileReader("C:\a.txt"));

    StringBuilder sb = new StringBuilder();

    while(in.hasNext()) {

        String s=in.nextLine();

        if (s.equals(""))               

           sb.append(System.lineSeparator());

        else

            sb.append(s);           

    }

    in.close();

    System.out.println( sb.toString());

    }

Output:

stack 

o2 

flow

edited Nov 20 '18 at 20:38

answered Nov 20 '18 at 19:51

Nehorai

1,014314

sorry dude, it was my mistake, SO format my string, i edited now

– Djordje Milošević
Nov 20 '18 at 20:13

@DjordjeMilošević See update

– Nehorai
Nov 20 '18 at 20:38

Yeahh it works, thanks a lot dude :)

– Djordje Milošević
Nov 20 '18 at 20:46

add a comment |

You can try the following:

Add:

import java.io.FileReader;

import java.io.IOException;

import java.util.*;

Code:

public static void main(String args) throws IOException {             

    Scanner in = new Scanner(new FileReader("C:\a.txt"));

    StringBuilder sb = new StringBuilder();

    while(in.hasNext()) {

        String s=in.nextLine();

        if (s.equals(""))               

           sb.append(System.lineSeparator());

        else

            sb.append(s);           

    }

    in.close();

    System.out.println( sb.toString());

    }

Output:

stack 

o2 

flow

edited Nov 20 '18 at 20:38

answered Nov 20 '18 at 19:51

Nehorai

1,014314

sorry dude, it was my mistake, SO format my string, i edited now

– Djordje Milošević
Nov 20 '18 at 20:13

@DjordjeMilošević See update

– Nehorai
Nov 20 '18 at 20:38

Yeahh it works, thanks a lot dude :)

– Djordje Milošević
Nov 20 '18 at 20:46

add a comment |

You can try the following:

Add:

import java.io.FileReader;

import java.io.IOException;

import java.util.*;

Code:

public static void main(String args) throws IOException {             

    Scanner in = new Scanner(new FileReader("C:\a.txt"));

    StringBuilder sb = new StringBuilder();

    while(in.hasNext()) {

        String s=in.nextLine();

        if (s.equals(""))               

           sb.append(System.lineSeparator());

        else

            sb.append(s);           

    }

    in.close();

    System.out.println( sb.toString());

    }

Output:

stack 

o2 

flow

edited Nov 20 '18 at 20:38

answered Nov 20 '18 at 19:51

Nehorai

1,014314

You can try the following:

Add:

import java.io.FileReader;

import java.io.IOException;

import java.util.*;

Code:

public static void main(String args) throws IOException {             

    Scanner in = new Scanner(new FileReader("C:\a.txt"));

    StringBuilder sb = new StringBuilder();

    while(in.hasNext()) {

        String s=in.nextLine();

        if (s.equals(""))               

           sb.append(System.lineSeparator());

        else

            sb.append(s);           

    }

    in.close();

    System.out.println( sb.toString());

    }

Output:

stack 

o2 

flow

edited Nov 20 '18 at 20:38

answered Nov 20 '18 at 19:51

Nehorai

1,014314

edited Nov 20 '18 at 20:38

answered Nov 20 '18 at 19:51

Nehorai

1,014314

answered Nov 20 '18 at 19:51

Nehorai

1,014314

answered Nov 20 '18 at 19:51

Nehorai

1,014314

sorry dude, it was my mistake, SO format my string, i edited now

– Djordje Milošević
Nov 20 '18 at 20:13

@DjordjeMilošević See update

– Nehorai
Nov 20 '18 at 20:38

Yeahh it works, thanks a lot dude :)

– Djordje Milošević
Nov 20 '18 at 20:46

add a comment |

sorry dude, it was my mistake, SO format my string, i edited now

– Djordje Milošević
Nov 20 '18 at 20:13

@DjordjeMilošević See update

– Nehorai
Nov 20 '18 at 20:38

Yeahh it works, thanks a lot dude :)

– Djordje Milošević
Nov 20 '18 at 20:46

sorry dude, it was my mistake, SO format my string, i edited now

– Djordje Milošević
Nov 20 '18 at 20:13

@DjordjeMilošević See update

– Nehorai
Nov 20 '18 at 20:38

Yeahh it works, thanks a lot dude :)

– Djordje Milošević
Nov 20 '18 at 20:46

add a comment |

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