What is the length of the diagonal of a square with perimeter $48$ inches? [closed]












0














The perimeter of a square is 48 inches.
What would be the length, in inches, of its diagonal?










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closed as off-topic by Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik Jan 1 at 15:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Any clues as to what maths you might know which might help you to answer this? Have you tried drawing a diagram?
    – Mark Bennet
    Mar 30 '12 at 20:55










  • Can you find the length of a side of this square? Assuming you can do this, the diagonal will be the hypotenuse of a right triangle . . .
    – Dave L. Renfro
    Mar 30 '12 at 20:56










  • 48:4=12, 12 inch. is each side of the square. Now use Pythagorean theorem to compute the diagonal.
    – Salech Alhasov
    Mar 30 '12 at 20:57










  • I picked this question from my GRE Book which has answer on it. But answer which i received is differing from Book Answer
    – Medex
    Mar 30 '12 at 20:59






  • 2




    In a case such as you described (Medex, comment #4), what you want to do is tell how you solved the problem (and give the specific answer you got), then give the different answer from the Book Answer (and say that it's the Book Answer), and then ask if the Book Answer is wrong or if you're wrong (could be both, of course), and if you're wrong, what your mistake(s) is (are).
    – Dave L. Renfro
    Mar 30 '12 at 21:21


















0














The perimeter of a square is 48 inches.
What would be the length, in inches, of its diagonal?










share|cite|improve this question















closed as off-topic by Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik Jan 1 at 15:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Any clues as to what maths you might know which might help you to answer this? Have you tried drawing a diagram?
    – Mark Bennet
    Mar 30 '12 at 20:55










  • Can you find the length of a side of this square? Assuming you can do this, the diagonal will be the hypotenuse of a right triangle . . .
    – Dave L. Renfro
    Mar 30 '12 at 20:56










  • 48:4=12, 12 inch. is each side of the square. Now use Pythagorean theorem to compute the diagonal.
    – Salech Alhasov
    Mar 30 '12 at 20:57










  • I picked this question from my GRE Book which has answer on it. But answer which i received is differing from Book Answer
    – Medex
    Mar 30 '12 at 20:59






  • 2




    In a case such as you described (Medex, comment #4), what you want to do is tell how you solved the problem (and give the specific answer you got), then give the different answer from the Book Answer (and say that it's the Book Answer), and then ask if the Book Answer is wrong or if you're wrong (could be both, of course), and if you're wrong, what your mistake(s) is (are).
    – Dave L. Renfro
    Mar 30 '12 at 21:21
















0












0








0







The perimeter of a square is 48 inches.
What would be the length, in inches, of its diagonal?










share|cite|improve this question















The perimeter of a square is 48 inches.
What would be the length, in inches, of its diagonal?







trigonometry triangle






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share|cite|improve this question













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share|cite|improve this question








edited Oct 28 '18 at 10:08









Blue

47.7k870151




47.7k870151










asked Mar 30 '12 at 20:52









MedexMedex

1671310




1671310




closed as off-topic by Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik Jan 1 at 15:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik Jan 1 at 15:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, José Carlos Santos, amWhy, Xander Henderson, Henrik

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Any clues as to what maths you might know which might help you to answer this? Have you tried drawing a diagram?
    – Mark Bennet
    Mar 30 '12 at 20:55










  • Can you find the length of a side of this square? Assuming you can do this, the diagonal will be the hypotenuse of a right triangle . . .
    – Dave L. Renfro
    Mar 30 '12 at 20:56










  • 48:4=12, 12 inch. is each side of the square. Now use Pythagorean theorem to compute the diagonal.
    – Salech Alhasov
    Mar 30 '12 at 20:57










  • I picked this question from my GRE Book which has answer on it. But answer which i received is differing from Book Answer
    – Medex
    Mar 30 '12 at 20:59






  • 2




    In a case such as you described (Medex, comment #4), what you want to do is tell how you solved the problem (and give the specific answer you got), then give the different answer from the Book Answer (and say that it's the Book Answer), and then ask if the Book Answer is wrong or if you're wrong (could be both, of course), and if you're wrong, what your mistake(s) is (are).
    – Dave L. Renfro
    Mar 30 '12 at 21:21




















  • Any clues as to what maths you might know which might help you to answer this? Have you tried drawing a diagram?
    – Mark Bennet
    Mar 30 '12 at 20:55










  • Can you find the length of a side of this square? Assuming you can do this, the diagonal will be the hypotenuse of a right triangle . . .
    – Dave L. Renfro
    Mar 30 '12 at 20:56










  • 48:4=12, 12 inch. is each side of the square. Now use Pythagorean theorem to compute the diagonal.
    – Salech Alhasov
    Mar 30 '12 at 20:57










  • I picked this question from my GRE Book which has answer on it. But answer which i received is differing from Book Answer
    – Medex
    Mar 30 '12 at 20:59






  • 2




    In a case such as you described (Medex, comment #4), what you want to do is tell how you solved the problem (and give the specific answer you got), then give the different answer from the Book Answer (and say that it's the Book Answer), and then ask if the Book Answer is wrong or if you're wrong (could be both, of course), and if you're wrong, what your mistake(s) is (are).
    – Dave L. Renfro
    Mar 30 '12 at 21:21


















Any clues as to what maths you might know which might help you to answer this? Have you tried drawing a diagram?
– Mark Bennet
Mar 30 '12 at 20:55




Any clues as to what maths you might know which might help you to answer this? Have you tried drawing a diagram?
– Mark Bennet
Mar 30 '12 at 20:55












Can you find the length of a side of this square? Assuming you can do this, the diagonal will be the hypotenuse of a right triangle . . .
– Dave L. Renfro
Mar 30 '12 at 20:56




Can you find the length of a side of this square? Assuming you can do this, the diagonal will be the hypotenuse of a right triangle . . .
– Dave L. Renfro
Mar 30 '12 at 20:56












48:4=12, 12 inch. is each side of the square. Now use Pythagorean theorem to compute the diagonal.
– Salech Alhasov
Mar 30 '12 at 20:57




48:4=12, 12 inch. is each side of the square. Now use Pythagorean theorem to compute the diagonal.
– Salech Alhasov
Mar 30 '12 at 20:57












I picked this question from my GRE Book which has answer on it. But answer which i received is differing from Book Answer
– Medex
Mar 30 '12 at 20:59




I picked this question from my GRE Book which has answer on it. But answer which i received is differing from Book Answer
– Medex
Mar 30 '12 at 20:59




2




2




In a case such as you described (Medex, comment #4), what you want to do is tell how you solved the problem (and give the specific answer you got), then give the different answer from the Book Answer (and say that it's the Book Answer), and then ask if the Book Answer is wrong or if you're wrong (could be both, of course), and if you're wrong, what your mistake(s) is (are).
– Dave L. Renfro
Mar 30 '12 at 21:21






In a case such as you described (Medex, comment #4), what you want to do is tell how you solved the problem (and give the specific answer you got), then give the different answer from the Book Answer (and say that it's the Book Answer), and then ask if the Book Answer is wrong or if you're wrong (could be both, of course), and if you're wrong, what your mistake(s) is (are).
– Dave L. Renfro
Mar 30 '12 at 21:21












2 Answers
2






active

oldest

votes


















1














Since the perimeter of the square is 48 inches, each side is 12 inches. Using the Pythagorean theorem ($a^{2}$ + $b^{2}$ = $c^{2}$), we have $$12^{2}+12^{2} = diagonal^{2}$$
$$288 = diagonal ^{2}$$



Thus, the diagonal is about $16.97$ inches.






share|cite|improve this answer





























    0














    $4a=48$



    $a=12$



    Length of diagonal $l$, of Every square with lenght of side=$a$, is



    $l=asqrt{2}$



    $l=12sqrt{2}approx16.97 $






    share|cite|improve this answer























    • Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
      – JP McCarthy
      Dec 11 '14 at 14:20










    • @JpMcCarthy You are right, it should be $approx$
      – Dheeraj Kumar
      Dec 11 '14 at 14:23












    • You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
      – JP McCarthy
      Dec 11 '14 at 14:26




















    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Since the perimeter of the square is 48 inches, each side is 12 inches. Using the Pythagorean theorem ($a^{2}$ + $b^{2}$ = $c^{2}$), we have $$12^{2}+12^{2} = diagonal^{2}$$
    $$288 = diagonal ^{2}$$



    Thus, the diagonal is about $16.97$ inches.






    share|cite|improve this answer


























      1














      Since the perimeter of the square is 48 inches, each side is 12 inches. Using the Pythagorean theorem ($a^{2}$ + $b^{2}$ = $c^{2}$), we have $$12^{2}+12^{2} = diagonal^{2}$$
      $$288 = diagonal ^{2}$$



      Thus, the diagonal is about $16.97$ inches.






      share|cite|improve this answer
























        1












        1








        1






        Since the perimeter of the square is 48 inches, each side is 12 inches. Using the Pythagorean theorem ($a^{2}$ + $b^{2}$ = $c^{2}$), we have $$12^{2}+12^{2} = diagonal^{2}$$
        $$288 = diagonal ^{2}$$



        Thus, the diagonal is about $16.97$ inches.






        share|cite|improve this answer












        Since the perimeter of the square is 48 inches, each side is 12 inches. Using the Pythagorean theorem ($a^{2}$ + $b^{2}$ = $c^{2}$), we have $$12^{2}+12^{2} = diagonal^{2}$$
        $$288 = diagonal ^{2}$$



        Thus, the diagonal is about $16.97$ inches.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Mar 30 '12 at 21:36









        JoeJoe

        3,82942451




        3,82942451























            0














            $4a=48$



            $a=12$



            Length of diagonal $l$, of Every square with lenght of side=$a$, is



            $l=asqrt{2}$



            $l=12sqrt{2}approx16.97 $






            share|cite|improve this answer























            • Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
              – JP McCarthy
              Dec 11 '14 at 14:20










            • @JpMcCarthy You are right, it should be $approx$
              – Dheeraj Kumar
              Dec 11 '14 at 14:23












            • You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
              – JP McCarthy
              Dec 11 '14 at 14:26


















            0














            $4a=48$



            $a=12$



            Length of diagonal $l$, of Every square with lenght of side=$a$, is



            $l=asqrt{2}$



            $l=12sqrt{2}approx16.97 $






            share|cite|improve this answer























            • Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
              – JP McCarthy
              Dec 11 '14 at 14:20










            • @JpMcCarthy You are right, it should be $approx$
              – Dheeraj Kumar
              Dec 11 '14 at 14:23












            • You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
              – JP McCarthy
              Dec 11 '14 at 14:26
















            0












            0








            0






            $4a=48$



            $a=12$



            Length of diagonal $l$, of Every square with lenght of side=$a$, is



            $l=asqrt{2}$



            $l=12sqrt{2}approx16.97 $






            share|cite|improve this answer














            $4a=48$



            $a=12$



            Length of diagonal $l$, of Every square with lenght of side=$a$, is



            $l=asqrt{2}$



            $l=12sqrt{2}approx16.97 $







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited Dec 11 '14 at 14:27

























            answered Dec 11 '14 at 14:12









            Dheeraj KumarDheeraj Kumar

            1,732822




            1,732822












            • Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
              – JP McCarthy
              Dec 11 '14 at 14:20










            • @JpMcCarthy You are right, it should be $approx$
              – Dheeraj Kumar
              Dec 11 '14 at 14:23












            • You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
              – JP McCarthy
              Dec 11 '14 at 14:26




















            • Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
              – JP McCarthy
              Dec 11 '14 at 14:20










            • @JpMcCarthy You are right, it should be $approx$
              – Dheeraj Kumar
              Dec 11 '14 at 14:23












            • You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
              – JP McCarthy
              Dec 11 '14 at 14:26


















            Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
            – JP McCarthy
            Dec 11 '14 at 14:20




            Do you want to change the very last equals sign? It should be an $approx$ sign because $12sqrt{2}$ is not equal to 16.97...
            – JP McCarthy
            Dec 11 '14 at 14:20












            @JpMcCarthy You are right, it should be $approx$
            – Dheeraj Kumar
            Dec 11 '14 at 14:23






            @JpMcCarthy You are right, it should be $approx$
            – Dheeraj Kumar
            Dec 11 '14 at 14:23














            You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
            – JP McCarthy
            Dec 11 '14 at 14:26






            You can write $12sqrt{2}approx 16.97$ or $12sqrt{2}approx 16.9705627485approx 16.97$ or maybe $12sqrt{2}=16.9705...approx 16.97$. It is incorrect to write $12sqrt{2}=16.9705627485$.
            – JP McCarthy
            Dec 11 '14 at 14:26





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