Can I adjust a weighted average of uniforms to be uniform?












0














I have uniformly-distributed random variables $x_i$ satisfying



$$0le x_ile 1$$



I take a weighted mean of these using weights $w_i$ satisfying



$$0le w_ile 1$$
$$sum w_i=1$$



The naive weighted mean is



$$hat{x}=sum w_ix_i$$



but $hat{x}$ no longer has a uniform distribution.



What smooth adjustment $X=f(hat{x})$ can I make such that $X$ has uniform distribution?










share|cite|improve this question






















  • If $F$ is the cumulative distribution function of $hat x$, then $F(hat x)$ is uniform on $[0,1]$. See probability integral transform.
    – Rahul
    Nov 20 '18 at 15:01












  • So what is the CDF of $hat{x}$?
    – spraff
    Nov 20 '18 at 22:27
















0














I have uniformly-distributed random variables $x_i$ satisfying



$$0le x_ile 1$$



I take a weighted mean of these using weights $w_i$ satisfying



$$0le w_ile 1$$
$$sum w_i=1$$



The naive weighted mean is



$$hat{x}=sum w_ix_i$$



but $hat{x}$ no longer has a uniform distribution.



What smooth adjustment $X=f(hat{x})$ can I make such that $X$ has uniform distribution?










share|cite|improve this question






















  • If $F$ is the cumulative distribution function of $hat x$, then $F(hat x)$ is uniform on $[0,1]$. See probability integral transform.
    – Rahul
    Nov 20 '18 at 15:01












  • So what is the CDF of $hat{x}$?
    – spraff
    Nov 20 '18 at 22:27














0












0








0







I have uniformly-distributed random variables $x_i$ satisfying



$$0le x_ile 1$$



I take a weighted mean of these using weights $w_i$ satisfying



$$0le w_ile 1$$
$$sum w_i=1$$



The naive weighted mean is



$$hat{x}=sum w_ix_i$$



but $hat{x}$ no longer has a uniform distribution.



What smooth adjustment $X=f(hat{x})$ can I make such that $X$ has uniform distribution?










share|cite|improve this question













I have uniformly-distributed random variables $x_i$ satisfying



$$0le x_ile 1$$



I take a weighted mean of these using weights $w_i$ satisfying



$$0le w_ile 1$$
$$sum w_i=1$$



The naive weighted mean is



$$hat{x}=sum w_ix_i$$



but $hat{x}$ no longer has a uniform distribution.



What smooth adjustment $X=f(hat{x})$ can I make such that $X$ has uniform distribution?







probability-theory probability-distributions






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 20 '18 at 14:37









spraff

465213




465213












  • If $F$ is the cumulative distribution function of $hat x$, then $F(hat x)$ is uniform on $[0,1]$. See probability integral transform.
    – Rahul
    Nov 20 '18 at 15:01












  • So what is the CDF of $hat{x}$?
    – spraff
    Nov 20 '18 at 22:27


















  • If $F$ is the cumulative distribution function of $hat x$, then $F(hat x)$ is uniform on $[0,1]$. See probability integral transform.
    – Rahul
    Nov 20 '18 at 15:01












  • So what is the CDF of $hat{x}$?
    – spraff
    Nov 20 '18 at 22:27
















If $F$ is the cumulative distribution function of $hat x$, then $F(hat x)$ is uniform on $[0,1]$. See probability integral transform.
– Rahul
Nov 20 '18 at 15:01






If $F$ is the cumulative distribution function of $hat x$, then $F(hat x)$ is uniform on $[0,1]$. See probability integral transform.
– Rahul
Nov 20 '18 at 15:01














So what is the CDF of $hat{x}$?
– spraff
Nov 20 '18 at 22:27




So what is the CDF of $hat{x}$?
– spraff
Nov 20 '18 at 22:27










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