Calculate the operator norm of the difference of two operators












0














Let $x_1,...,x_n in [0,1]$, $lambda_1,...,lambda_n in mathbb{C}$ and let $S,T : C([0,1]) to C([0,1])$ be the operators defined by



$T(g)= int_0^1 g(s), ds$



and



$S(g) = sum_{i=1}^n lambda_i g(x_i)$.



$C([0,1])$ is equipped with the $|cdot|_{infty}$-norm.



I already proved that $|T| = 1$ and $|S| = sum_{i=1}^n |lambda_i|$, where I used for the $geq $-inequality the function $tilde{g}$, which satisfies $tilde{g}(x_i) = dfrac{bar{lambda_i}}{|lambda_i|}$ for all $i=1,...,n$ and is linearly interpolated between the $x_i$.



Now I want to find the norm of the operator $R:=T-S$.
We obviously have



$|R| leq |T|+|S| = 1+sum_{i=1}^n |lambda_i|$



and



$|R| geq ||T|-|S|| = |1-sum_{i=1}^n |lambda_i||$.



How can I proceed now?



Thanks in advance!










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  • 1




    The norm of $R$ is equal to the upper bound you calculated: define a continuous function which is $pm 1$ at $x_i$ and equal to $1$ at point with distance $epsilon$ to all $x_i$. Then let $epsilonsearrow0$.
    – daw
    Nov 20 '18 at 15:01


















0














Let $x_1,...,x_n in [0,1]$, $lambda_1,...,lambda_n in mathbb{C}$ and let $S,T : C([0,1]) to C([0,1])$ be the operators defined by



$T(g)= int_0^1 g(s), ds$



and



$S(g) = sum_{i=1}^n lambda_i g(x_i)$.



$C([0,1])$ is equipped with the $|cdot|_{infty}$-norm.



I already proved that $|T| = 1$ and $|S| = sum_{i=1}^n |lambda_i|$, where I used for the $geq $-inequality the function $tilde{g}$, which satisfies $tilde{g}(x_i) = dfrac{bar{lambda_i}}{|lambda_i|}$ for all $i=1,...,n$ and is linearly interpolated between the $x_i$.



Now I want to find the norm of the operator $R:=T-S$.
We obviously have



$|R| leq |T|+|S| = 1+sum_{i=1}^n |lambda_i|$



and



$|R| geq ||T|-|S|| = |1-sum_{i=1}^n |lambda_i||$.



How can I proceed now?



Thanks in advance!










share|cite|improve this question


















  • 1




    The norm of $R$ is equal to the upper bound you calculated: define a continuous function which is $pm 1$ at $x_i$ and equal to $1$ at point with distance $epsilon$ to all $x_i$. Then let $epsilonsearrow0$.
    – daw
    Nov 20 '18 at 15:01
















0












0








0







Let $x_1,...,x_n in [0,1]$, $lambda_1,...,lambda_n in mathbb{C}$ and let $S,T : C([0,1]) to C([0,1])$ be the operators defined by



$T(g)= int_0^1 g(s), ds$



and



$S(g) = sum_{i=1}^n lambda_i g(x_i)$.



$C([0,1])$ is equipped with the $|cdot|_{infty}$-norm.



I already proved that $|T| = 1$ and $|S| = sum_{i=1}^n |lambda_i|$, where I used for the $geq $-inequality the function $tilde{g}$, which satisfies $tilde{g}(x_i) = dfrac{bar{lambda_i}}{|lambda_i|}$ for all $i=1,...,n$ and is linearly interpolated between the $x_i$.



Now I want to find the norm of the operator $R:=T-S$.
We obviously have



$|R| leq |T|+|S| = 1+sum_{i=1}^n |lambda_i|$



and



$|R| geq ||T|-|S|| = |1-sum_{i=1}^n |lambda_i||$.



How can I proceed now?



Thanks in advance!










share|cite|improve this question













Let $x_1,...,x_n in [0,1]$, $lambda_1,...,lambda_n in mathbb{C}$ and let $S,T : C([0,1]) to C([0,1])$ be the operators defined by



$T(g)= int_0^1 g(s), ds$



and



$S(g) = sum_{i=1}^n lambda_i g(x_i)$.



$C([0,1])$ is equipped with the $|cdot|_{infty}$-norm.



I already proved that $|T| = 1$ and $|S| = sum_{i=1}^n |lambda_i|$, where I used for the $geq $-inequality the function $tilde{g}$, which satisfies $tilde{g}(x_i) = dfrac{bar{lambda_i}}{|lambda_i|}$ for all $i=1,...,n$ and is linearly interpolated between the $x_i$.



Now I want to find the norm of the operator $R:=T-S$.
We obviously have



$|R| leq |T|+|S| = 1+sum_{i=1}^n |lambda_i|$



and



$|R| geq ||T|-|S|| = |1-sum_{i=1}^n |lambda_i||$.



How can I proceed now?



Thanks in advance!







functional-analysis operator-theory norm






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asked Nov 20 '18 at 14:49









Max93

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30529








  • 1




    The norm of $R$ is equal to the upper bound you calculated: define a continuous function which is $pm 1$ at $x_i$ and equal to $1$ at point with distance $epsilon$ to all $x_i$. Then let $epsilonsearrow0$.
    – daw
    Nov 20 '18 at 15:01
















  • 1




    The norm of $R$ is equal to the upper bound you calculated: define a continuous function which is $pm 1$ at $x_i$ and equal to $1$ at point with distance $epsilon$ to all $x_i$. Then let $epsilonsearrow0$.
    – daw
    Nov 20 '18 at 15:01










1




1




The norm of $R$ is equal to the upper bound you calculated: define a continuous function which is $pm 1$ at $x_i$ and equal to $1$ at point with distance $epsilon$ to all $x_i$. Then let $epsilonsearrow0$.
– daw
Nov 20 '18 at 15:01






The norm of $R$ is equal to the upper bound you calculated: define a continuous function which is $pm 1$ at $x_i$ and equal to $1$ at point with distance $epsilon$ to all $x_i$. Then let $epsilonsearrow0$.
– daw
Nov 20 '18 at 15:01












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