Mixing
Determine the values of a, b for which the systems have (1) exactly one solution, (2) no solutions, (3)...
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I'll leave two pictures, can someone check if I'm right? (exercise b)
linear-algebra matrices systems-of-equations determinant
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
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add a comment |
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I'll leave two pictures, can someone check if I'm right? (exercise b)
linear-algebra matrices systems-of-equations determinant
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
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add a comment |
$begingroup$
I'll leave two pictures, can someone check if I'm right? (exercise b)
linear-algebra matrices systems-of-equations determinant
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
$endgroup$
I'll leave two pictures, can someone check if I'm right? (exercise b)
linear-algebra matrices systems-of-equations determinant
linear-algebra matrices systems-of-equations determinant
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
asked Jan 16 at 19:29
Aliaksei KlimovichAliaksei Klimovich
516
516
add a comment |
add a comment |
1 Answer
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Your answer for no solution is incorrect. Note that you already found out that the system will have a unique solution iff $ane4$, regardless of the value of $b$. So the case $b=6,ane4$ gives a unique solution and has already been taken care of. You get no solution iff $a=4,bne6$.
The others are correct.
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
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Ahh, yes, I did not mention this. Thanks
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– Aliaksei Klimovich
Jan 16 at 20:01
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
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active
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votes
$begingroup$
Your answer for no solution is incorrect. Note that you already found out that the system will have a unique solution iff $ane4$, regardless of the value of $b$. So the case $b=6,ane4$ gives a unique solution and has already been taken care of. You get no solution iff $a=4,bne6$.
The others are correct.
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
$endgroup$
$begingroup$
Ahh, yes, I did not mention this. Thanks
$endgroup$
– Aliaksei Klimovich
Jan 16 at 20:01
add a comment |
$begingroup$
Your answer for no solution is incorrect. Note that you already found out that the system will have a unique solution iff $ane4$, regardless of the value of $b$. So the case $b=6,ane4$ gives a unique solution and has already been taken care of. You get no solution iff $a=4,bne6$.
The others are correct.
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
$endgroup$
$begingroup$
Ahh, yes, I did not mention this. Thanks
$endgroup$
– Aliaksei Klimovich
Jan 16 at 20:01
add a comment |
$begingroup$
Your answer for no solution is incorrect. Note that you already found out that the system will have a unique solution iff $ane4$, regardless of the value of $b$. So the case $b=6,ane4$ gives a unique solution and has already been taken care of. You get no solution iff $a=4,bne6$.
The others are correct.
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
$endgroup$
Your answer for no solution is incorrect. Note that you already found out that the system will have a unique solution iff $ane4$, regardless of the value of $b$. So the case $b=6,ane4$ gives a unique solution and has already been taken care of. You get no solution iff $a=4,bne6$.
The others are correct.
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
answered Jan 16 at 19:44
Shubham JohriShubham Johri
5,186717
5,186717
$begingroup$
Ahh, yes, I did not mention this. Thanks
$endgroup$
– Aliaksei Klimovich
Jan 16 at 20:01
add a comment |
$begingroup$
Ahh, yes, I did not mention this. Thanks
$endgroup$
– Aliaksei Klimovich
Jan 16 at 20:01
$begingroup$
Ahh, yes, I did not mention this. Thanks
$endgroup$
– Aliaksei Klimovich
Jan 16 at 20:01
$begingroup$
Ahh, yes, I did not mention this. Thanks
$endgroup$
– Aliaksei Klimovich
Jan 16 at 20:01
add a comment |
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