Mixing
Elementary schools summation in denominator?
$begingroup$
after being lazy for a long time and being away from any fraction and equations, I am confused with a seriously ridiculous math problem, and I want to confirm my answer:
the equation is pretty simple as I followed some formula and having something like this:
enter image description here
is this the right answer?
enter image description here
Or did I just failed in my exam?
By the way, I know its probably the simplest and the dumbest question ever, so if that's what you think forgive me.
fractions elementary-functions
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
$endgroup$
add a comment |
$begingroup$
after being lazy for a long time and being away from any fraction and equations, I am confused with a seriously ridiculous math problem, and I want to confirm my answer:
the equation is pretty simple as I followed some formula and having something like this:
enter image description here
is this the right answer?
enter image description here
Or did I just failed in my exam?
By the way, I know its probably the simplest and the dumbest question ever, so if that's what you think forgive me.
fractions elementary-functions
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
$endgroup$
$begingroup$
Think about this logically: If you consider the number $100/102$, it has to be pretty close to one, right? I mean, 100 is pretty close to 102. But 1/3 is not close to 1. Therefore, intuitively, this cannot be correct.
$endgroup$
– Matti P.
Jan 17 at 9:11
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Jan 17 at 9:12
$begingroup$
The thing to learn from this: You cannot cancel terms that are summed together in fractions.
$endgroup$
– Matti P.
Jan 17 at 9:12
add a comment |
$begingroup$
after being lazy for a long time and being away from any fraction and equations, I am confused with a seriously ridiculous math problem, and I want to confirm my answer:
the equation is pretty simple as I followed some formula and having something like this:
enter image description here
is this the right answer?
enter image description here
Or did I just failed in my exam?
By the way, I know its probably the simplest and the dumbest question ever, so if that's what you think forgive me.
fractions elementary-functions
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
$endgroup$
after being lazy for a long time and being away from any fraction and equations, I am confused with a seriously ridiculous math problem, and I want to confirm my answer:
the equation is pretty simple as I followed some formula and having something like this:
enter image description here
is this the right answer?
enter image description here
Or did I just failed in my exam?
By the way, I know its probably the simplest and the dumbest question ever, so if that's what you think forgive me.
fractions elementary-functions
fractions elementary-functions
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
asked Jan 17 at 9:08
mohammad fallah.rasoulnejadmohammad fallah.rasoulnejad
31
31
$begingroup$
Think about this logically: If you consider the number $100/102$, it has to be pretty close to one, right? I mean, 100 is pretty close to 102. But 1/3 is not close to 1. Therefore, intuitively, this cannot be correct.
$endgroup$
– Matti P.
Jan 17 at 9:11
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Jan 17 at 9:12
$begingroup$
The thing to learn from this: You cannot cancel terms that are summed together in fractions.
$endgroup$
– Matti P.
Jan 17 at 9:12
add a comment |
$begingroup$
Think about this logically: If you consider the number $100/102$, it has to be pretty close to one, right? I mean, 100 is pretty close to 102. But 1/3 is not close to 1. Therefore, intuitively, this cannot be correct.
$endgroup$
– Matti P.
Jan 17 at 9:11
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Jan 17 at 9:12
$begingroup$
The thing to learn from this: You cannot cancel terms that are summed together in fractions.
$endgroup$
– Matti P.
Jan 17 at 9:12
$begingroup$
Think about this logically: If you consider the number $100/102$, it has to be pretty close to one, right? I mean, 100 is pretty close to 102. But 1/3 is not close to 1. Therefore, intuitively, this cannot be correct.
$endgroup$
– Matti P.
Jan 17 at 9:11
$begingroup$
Think about this logically: If you consider the number $100/102$, it has to be pretty close to one, right? I mean, 100 is pretty close to 102. But 1/3 is not close to 1. Therefore, intuitively, this cannot be correct.
$endgroup$
– Matti P.
Jan 17 at 9:11
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Jan 17 at 9:12
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Jan 17 at 9:12
$begingroup$
The thing to learn from this: You cannot cancel terms that are summed together in fractions.
$endgroup$
– Matti P.
Jan 17 at 9:12
$begingroup$
The thing to learn from this: You cannot cancel terms that are summed together in fractions.
$endgroup$
– Matti P.
Jan 17 at 9:12
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Simplifying fractions involves only multiplication, not summation. For example, if you have a fraction
$$
frac{100}{102}
$$
and you need to simplify it, you multiply both the enumerator and denominator with the same number (Why the same number? because their ratio is exactly 1, and multiplying by 1 doesn't change the value of a number). In this case, we can multiply both by $1/2$:
$$
frac{100}{102} times frac{1/2}{1/2} = frac{(100/2)}{(102/2)} = frac{50}{51}
$$
This is as far as we can simplify this fraction (Why? Because $50= 2times 5^2$ and $51= 3times 17$, and we see that they don't have any common factors).
This is all that you can do to a fraction. Don't cancel summed terms in a fraction.
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
$endgroup$
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Simplifying fractions involves only multiplication, not summation. For example, if you have a fraction
$$
frac{100}{102}
$$
and you need to simplify it, you multiply both the enumerator and denominator with the same number (Why the same number? because their ratio is exactly 1, and multiplying by 1 doesn't change the value of a number). In this case, we can multiply both by $1/2$:
$$
frac{100}{102} times frac{1/2}{1/2} = frac{(100/2)}{(102/2)} = frac{50}{51}
$$
This is as far as we can simplify this fraction (Why? Because $50= 2times 5^2$ and $51= 3times 17$, and we see that they don't have any common factors).
This is all that you can do to a fraction. Don't cancel summed terms in a fraction.
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
$endgroup$
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
add a comment |
$begingroup$
Simplifying fractions involves only multiplication, not summation. For example, if you have a fraction
$$
frac{100}{102}
$$
and you need to simplify it, you multiply both the enumerator and denominator with the same number (Why the same number? because their ratio is exactly 1, and multiplying by 1 doesn't change the value of a number). In this case, we can multiply both by $1/2$:
$$
frac{100}{102} times frac{1/2}{1/2} = frac{(100/2)}{(102/2)} = frac{50}{51}
$$
This is as far as we can simplify this fraction (Why? Because $50= 2times 5^2$ and $51= 3times 17$, and we see that they don't have any common factors).
This is all that you can do to a fraction. Don't cancel summed terms in a fraction.
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
$endgroup$
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
add a comment |
$begingroup$
Simplifying fractions involves only multiplication, not summation. For example, if you have a fraction
$$
frac{100}{102}
$$
and you need to simplify it, you multiply both the enumerator and denominator with the same number (Why the same number? because their ratio is exactly 1, and multiplying by 1 doesn't change the value of a number). In this case, we can multiply both by $1/2$:
$$
frac{100}{102} times frac{1/2}{1/2} = frac{(100/2)}{(102/2)} = frac{50}{51}
$$
This is as far as we can simplify this fraction (Why? Because $50= 2times 5^2$ and $51= 3times 17$, and we see that they don't have any common factors).
This is all that you can do to a fraction. Don't cancel summed terms in a fraction.
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
$endgroup$
Simplifying fractions involves only multiplication, not summation. For example, if you have a fraction
$$
frac{100}{102}
$$
and you need to simplify it, you multiply both the enumerator and denominator with the same number (Why the same number? because their ratio is exactly 1, and multiplying by 1 doesn't change the value of a number). In this case, we can multiply both by $1/2$:
$$
frac{100}{102} times frac{1/2}{1/2} = frac{(100/2)}{(102/2)} = frac{50}{51}
$$
This is as far as we can simplify this fraction (Why? Because $50= 2times 5^2$ and $51= 3times 17$, and we see that they don't have any common factors).
This is all that you can do to a fraction. Don't cancel summed terms in a fraction.
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
answered Jan 17 at 9:23
Matti P.Matti P.
2,1431414
2,1431414
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
add a comment |
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
$begingroup$
OK, guess that exam as a fail then :((, damn (thanks by the way)
$endgroup$
– mohammad fallah.rasoulnejad
Jan 18 at 13:44
add a comment |
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$begingroup$
Think about this logically: If you consider the number $100/102$, it has to be pretty close to one, right? I mean, 100 is pretty close to 102. But 1/3 is not close to 1. Therefore, intuitively, this cannot be correct.
$endgroup$
– Matti P.
Jan 17 at 9:11
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Jan 17 at 9:12
$begingroup$
The thing to learn from this: You cannot cancel terms that are summed together in fractions.
$endgroup$
– Matti P.
Jan 17 at 9:12