Mixing
Fuctional Equation with some inequality
$begingroup$
QUESTION )
{2f(x₁)+4f(x₂)+....+2nf(xₙ)-nf(xₘ)} is divided by {f(xᵥ)} the quotient obtained was a square of (n) giving a remaider {0}.
given that, {m=(n-1)} and { v=(n-2) } also the above is true only if { n>2 }
The following inequality is a modified form of a famous inequality given with respect to above fuctional equation,
{f(xᵢ)²+f(xⱼ)²+2f(xₖ)²} > {4f(xᵣ)f(xₜ)}
again given that,
{k = (i+j)}
{r = (i-1)}
{t = (j-2)} and {(i+j)< (n)}
so find the value of function of (x₃) .
I just cannot understand what the inequality means for. I have reached till proving f(m)= f(v) , but unable to solve any furthur.
Please instruct if I am going wrong or give me a simple hint if i am going right proving f(m)= f(v) ??
functions
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
$endgroup$
add a comment |
$begingroup$
QUESTION )
{2f(x₁)+4f(x₂)+....+2nf(xₙ)-nf(xₘ)} is divided by {f(xᵥ)} the quotient obtained was a square of (n) giving a remaider {0}.
given that, {m=(n-1)} and { v=(n-2) } also the above is true only if { n>2 }
The following inequality is a modified form of a famous inequality given with respect to above fuctional equation,
{f(xᵢ)²+f(xⱼ)²+2f(xₖ)²} > {4f(xᵣ)f(xₜ)}
again given that,
{k = (i+j)}
{r = (i-1)}
{t = (j-2)} and {(i+j)< (n)}
so find the value of function of (x₃) .
I just cannot understand what the inequality means for. I have reached till proving f(m)= f(v) , but unable to solve any furthur.
Please instruct if I am going wrong or give me a simple hint if i am going right proving f(m)= f(v) ??
functions
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
$endgroup$
add a comment |
$begingroup$
QUESTION )
{2f(x₁)+4f(x₂)+....+2nf(xₙ)-nf(xₘ)} is divided by {f(xᵥ)} the quotient obtained was a square of (n) giving a remaider {0}.
given that, {m=(n-1)} and { v=(n-2) } also the above is true only if { n>2 }
The following inequality is a modified form of a famous inequality given with respect to above fuctional equation,
{f(xᵢ)²+f(xⱼ)²+2f(xₖ)²} > {4f(xᵣ)f(xₜ)}
again given that,
{k = (i+j)}
{r = (i-1)}
{t = (j-2)} and {(i+j)< (n)}
so find the value of function of (x₃) .
I just cannot understand what the inequality means for. I have reached till proving f(m)= f(v) , but unable to solve any furthur.
Please instruct if I am going wrong or give me a simple hint if i am going right proving f(m)= f(v) ??
functions
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
$endgroup$
QUESTION )
{2f(x₁)+4f(x₂)+....+2nf(xₙ)-nf(xₘ)} is divided by {f(xᵥ)} the quotient obtained was a square of (n) giving a remaider {0}.
given that, {m=(n-1)} and { v=(n-2) } also the above is true only if { n>2 }
The following inequality is a modified form of a famous inequality given with respect to above fuctional equation,
{f(xᵢ)²+f(xⱼ)²+2f(xₖ)²} > {4f(xᵣ)f(xₜ)}
again given that,
{k = (i+j)}
{r = (i-1)}
{t = (j-2)} and {(i+j)< (n)}
so find the value of function of (x₃) .
I just cannot understand what the inequality means for. I have reached till proving f(m)= f(v) , but unable to solve any furthur.
Please instruct if I am going wrong or give me a simple hint if i am going right proving f(m)= f(v) ??
functions
functions
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
asked Jan 17 at 14:24
D.Ne.JBP.2D.Ne.JBP.2
11
11
add a comment |
add a comment |
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