Mixing
npm - Pass arguments from CLI through multiple scripts
Let's say I have the following in a file called print-last-arg.js:
console.log(process.argv[process.argv.length-1])
And the following scripts in my package.json:
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
When I run npm run print_a -- --foo=bar, I get --foo=bar as expected.
However, npm run print_b -- --foo=bar gives me no output.
How do I pass the CLI arguments from print_b to print_a?
npm npm-scripts
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
add a comment |
Let's say I have the following in a file called print-last-arg.js:
console.log(process.argv[process.argv.length-1])
And the following scripts in my package.json:
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
When I run npm run print_a -- --foo=bar, I get --foo=bar as expected.
However, npm run print_b -- --foo=bar gives me no output.
How do I pass the CLI arguments from print_b to print_a?
npm npm-scripts
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
1
Possible duplicate of How to pass a command line argument to a nested script?
– RobC
Nov 22 '18 at 9:03
Agreed, @RobC - didn’t find that one. Thanks.
– ethan.roday
Nov 22 '18 at 21:09
add a comment |
Let's say I have the following in a file called print-last-arg.js:
console.log(process.argv[process.argv.length-1])
And the following scripts in my package.json:
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
When I run npm run print_a -- --foo=bar, I get --foo=bar as expected.
However, npm run print_b -- --foo=bar gives me no output.
How do I pass the CLI arguments from print_b to print_a?
npm npm-scripts
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
Let's say I have the following in a file called print-last-arg.js:
console.log(process.argv[process.argv.length-1])
And the following scripts in my package.json:
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
When I run npm run print_a -- --foo=bar, I get --foo=bar as expected.
However, npm run print_b -- --foo=bar gives me no output.
How do I pass the CLI arguments from print_b to print_a?
npm npm-scripts
npm npm-scripts
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
asked Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
1,110720
1
Possible duplicate of How to pass a command line argument to a nested script?
– RobC
Nov 22 '18 at 9:03
Agreed, @RobC - didn’t find that one. Thanks.
– ethan.roday
Nov 22 '18 at 21:09
add a comment |
1
Possible duplicate of How to pass a command line argument to a nested script?
– RobC
Nov 22 '18 at 9:03
Agreed, @RobC - didn’t find that one. Thanks.
– ethan.roday
Nov 22 '18 at 21:09
1
1
Possible duplicate of How to pass a command line argument to a nested script?
– RobC
Nov 22 '18 at 9:03
Possible duplicate of How to pass a command line argument to a nested script?
– RobC
Nov 22 '18 at 9:03
Agreed, @RobC - didn’t find that one. Thanks.
– ethan.roday
Nov 22 '18 at 21:09
Agreed, @RobC - didn’t find that one. Thanks.
– ethan.roday
Nov 22 '18 at 21:09
add a comment |
1 Answer
1
active
oldest
votes
It turns out that you just have to add an extra -- on the end of print_b, which will tell npm to pass whatever arguments print_b got to print_a. So,
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
becomes
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a -- "
}
Voilà! Now npm run print_b -- --foo=bar prints --foo=bar as expected.
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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oldest
votes
It turns out that you just have to add an extra -- on the end of print_b, which will tell npm to pass whatever arguments print_b got to print_a. So,
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
becomes
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a -- "
}
Voilà! Now npm run print_b -- --foo=bar prints --foo=bar as expected.
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
add a comment |
It turns out that you just have to add an extra -- on the end of print_b, which will tell npm to pass whatever arguments print_b got to print_a. So,
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
becomes
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a -- "
}
Voilà! Now npm run print_b -- --foo=bar prints --foo=bar as expected.
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
add a comment |
It turns out that you just have to add an extra -- on the end of print_b, which will tell npm to pass whatever arguments print_b got to print_a. So,
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
becomes
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a -- "
}
Voilà! Now npm run print_b -- --foo=bar prints --foo=bar as expected.
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
It turns out that you just have to add an extra -- on the end of print_b, which will tell npm to pass whatever arguments print_b got to print_a. So,
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a"
}
becomes
"scripts": {
"print_a": "node print-last-arg.js",
"print_b": "npm run print_a -- "
}
Voilà! Now npm run print_b -- --foo=bar prints --foo=bar as expected.
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
answered Nov 22 '18 at 0:15
ethan.rodayethan.roday
1,110720
1,110720
add a comment |
add a comment |
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1
Possible duplicate of How to pass a command line argument to a nested script?
– RobC
Nov 22 '18 at 9:03
Agreed, @RobC - didn’t find that one. Thanks.
– ethan.roday
Nov 22 '18 at 21:09