How to get the total amount of contributors to a GitHub repository?

How can I get the total amount of contributors of a GitHub repository? The API makes it quite difficult because of the pagination.

This is what I tried so far using Python:

contributors = "https://api.github.com/repos/JetBrains/kotlin-web-site/contributors"

x = requests.get(contributors)

y = json.loads(x.text)

len(y) # maximum 30 because of pagination

edited Nov 22 '18 at 14:04

asked Nov 22 '18 at 12:52

Max

447

1

/repos/:owner/:repo/stats/contributors (documented here) has weekly statistics, but if you're interested in the overall total, that isn't a big help, either.

– das-g
Nov 22 '18 at 13:51

Maybe the GraphQL API allows such aggregation. Might be worth investigating.

– das-g
Nov 22 '18 at 14:43

add a comment |

How can I get the total amount of contributors of a GitHub repository? The API makes it quite difficult because of the pagination.

This is what I tried so far using Python:

contributors = "https://api.github.com/repos/JetBrains/kotlin-web-site/contributors"

x = requests.get(contributors)

y = json.loads(x.text)

len(y) # maximum 30 because of pagination

edited Nov 22 '18 at 14:04

asked Nov 22 '18 at 12:52

Max

447

1

/repos/:owner/:repo/stats/contributors (documented here) has weekly statistics, but if you're interested in the overall total, that isn't a big help, either.

– das-g
Nov 22 '18 at 13:51

Maybe the GraphQL API allows such aggregation. Might be worth investigating.

– das-g
Nov 22 '18 at 14:43

add a comment |

How can I get the total amount of contributors of a GitHub repository? The API makes it quite difficult because of the pagination.

This is what I tried so far using Python:

contributors = "https://api.github.com/repos/JetBrains/kotlin-web-site/contributors"

x = requests.get(contributors)

y = json.loads(x.text)

len(y) # maximum 30 because of pagination

edited Nov 22 '18 at 14:04

asked Nov 22 '18 at 12:52

Max

447

How can I get the total amount of contributors of a GitHub repository? The API makes it quite difficult because of the pagination.

This is what I tried so far using Python:

contributors = "https://api.github.com/repos/JetBrains/kotlin-web-site/contributors"

x = requests.get(contributors)

y = json.loads(x.text)

len(y) # maximum 30 because of pagination

python python-requests github-api

edited Nov 22 '18 at 14:04

asked Nov 22 '18 at 12:52

Max

447

edited Nov 22 '18 at 14:04

asked Nov 22 '18 at 12:52

Max

447

edited Nov 22 '18 at 14:04

asked Nov 22 '18 at 12:52

Max

447

asked Nov 22 '18 at 12:52

Max

447

asked Nov 22 '18 at 12:52

Max

447

1

/repos/:owner/:repo/stats/contributors (documented here) has weekly statistics, but if you're interested in the overall total, that isn't a big help, either.

– das-g
Nov 22 '18 at 13:51

Maybe the GraphQL API allows such aggregation. Might be worth investigating.

– das-g
Nov 22 '18 at 14:43

add a comment |

1

/repos/:owner/:repo/stats/contributors (documented here) has weekly statistics, but if you're interested in the overall total, that isn't a big help, either.

– das-g
Nov 22 '18 at 13:51

Maybe the GraphQL API allows such aggregation. Might be worth investigating.

– das-g
Nov 22 '18 at 14:43

/repos/:owner/:repo/stats/contributors (documented here) has weekly statistics, but if you're interested in the overall total, that isn't a big help, either.

– das-g
Nov 22 '18 at 13:51

Maybe the GraphQL API allows such aggregation. Might be worth investigating.

– das-g
Nov 22 '18 at 14:43

add a comment |

1 Answer
1

active

oldest

votes

As a last resort you can scrape required value from GitHub HTML page (lxml.html lib required):

import requests

from lxml import html



r = requests.get('https://github.com/JetBrains/kotlin-web-site')

xpath = '//span[contains(@class, "num") and following-sibling::text()[normalize-space()="contributors"]]/text()'

contributors_number = int(html.fromstring(r.text).xpath(xpath)[0].strip())

print(contributors_number)

# 338

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

Gives me just what I wanted, thank you.

– Max
Nov 22 '18 at 15:37

Well know I'm wondering how to get the amount of commits. I'm experimenting around but I don't get it.

– Max
Nov 22 '18 at 16:10

@Max , try to replace "contributors" with "commits" in xpath and use commits_number = int(html.fromstring(r.text).xpath(xpath)[0].strip().replace(',', ''))

– Andersson
Nov 22 '18 at 16:13

Nice! Thanks once again.

– Max
Nov 22 '18 at 16:18

I just ran into it so I share it: Sometimes it happens that a repository has more than 1000 contributors and the number will include a comma again, so the replace() method has to be used again to get rid of it.

– Max
Nov 23 '18 at 10:52

|
show 1 more comment

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1 Answer
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oldest

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1 Answer
1

active

oldest

votes

As a last resort you can scrape required value from GitHub HTML page (lxml.html lib required):

import requests

from lxml import html



r = requests.get('https://github.com/JetBrains/kotlin-web-site')

xpath = '//span[contains(@class, "num") and following-sibling::text()[normalize-space()="contributors"]]/text()'

contributors_number = int(html.fromstring(r.text).xpath(xpath)[0].strip())

print(contributors_number)

# 338

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

Gives me just what I wanted, thank you.

– Max
Nov 22 '18 at 15:37

Well know I'm wondering how to get the amount of commits. I'm experimenting around but I don't get it.

– Max
Nov 22 '18 at 16:10

@Max , try to replace "contributors" with "commits" in xpath and use commits_number = int(html.fromstring(r.text).xpath(xpath)[0].strip().replace(',', ''))

– Andersson
Nov 22 '18 at 16:13

Nice! Thanks once again.

– Max
Nov 22 '18 at 16:18

I just ran into it so I share it: Sometimes it happens that a repository has more than 1000 contributors and the number will include a comma again, so the replace() method has to be used again to get rid of it.

– Max
Nov 23 '18 at 10:52

|
show 1 more comment

As a last resort you can scrape required value from GitHub HTML page (lxml.html lib required):

import requests

from lxml import html



r = requests.get('https://github.com/JetBrains/kotlin-web-site')

xpath = '//span[contains(@class, "num") and following-sibling::text()[normalize-space()="contributors"]]/text()'

contributors_number = int(html.fromstring(r.text).xpath(xpath)[0].strip())

print(contributors_number)

# 338

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

Gives me just what I wanted, thank you.

– Max
Nov 22 '18 at 15:37

Well know I'm wondering how to get the amount of commits. I'm experimenting around but I don't get it.

– Max
Nov 22 '18 at 16:10

@Max , try to replace "contributors" with "commits" in xpath and use commits_number = int(html.fromstring(r.text).xpath(xpath)[0].strip().replace(',', ''))

– Andersson
Nov 22 '18 at 16:13

Nice! Thanks once again.

– Max
Nov 22 '18 at 16:18

I just ran into it so I share it: Sometimes it happens that a repository has more than 1000 contributors and the number will include a comma again, so the replace() method has to be used again to get rid of it.

– Max
Nov 23 '18 at 10:52

|
show 1 more comment

As a last resort you can scrape required value from GitHub HTML page (lxml.html lib required):

import requests

from lxml import html



r = requests.get('https://github.com/JetBrains/kotlin-web-site')

xpath = '//span[contains(@class, "num") and following-sibling::text()[normalize-space()="contributors"]]/text()'

contributors_number = int(html.fromstring(r.text).xpath(xpath)[0].strip())

print(contributors_number)

# 338

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

As a last resort you can scrape required value from GitHub HTML page (lxml.html lib required):

import requests

from lxml import html



r = requests.get('https://github.com/JetBrains/kotlin-web-site')

xpath = '//span[contains(@class, "num") and following-sibling::text()[normalize-space()="contributors"]]/text()'

contributors_number = int(html.fromstring(r.text).xpath(xpath)[0].strip())

print(contributors_number)

# 338

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

answered Nov 22 '18 at 14:57

Andersson

38.9k103468

Gives me just what I wanted, thank you.

– Max
Nov 22 '18 at 15:37

Well know I'm wondering how to get the amount of commits. I'm experimenting around but I don't get it.

– Max
Nov 22 '18 at 16:10

@Max , try to replace "contributors" with "commits" in xpath and use commits_number = int(html.fromstring(r.text).xpath(xpath)[0].strip().replace(',', ''))

– Andersson
Nov 22 '18 at 16:13

Nice! Thanks once again.

– Max
Nov 22 '18 at 16:18

I just ran into it so I share it: Sometimes it happens that a repository has more than 1000 contributors and the number will include a comma again, so the replace() method has to be used again to get rid of it.

– Max
Nov 23 '18 at 10:52

|
show 1 more comment

Gives me just what I wanted, thank you.

– Max
Nov 22 '18 at 15:37

Well know I'm wondering how to get the amount of commits. I'm experimenting around but I don't get it.

– Max
Nov 22 '18 at 16:10

@Max , try to replace "contributors" with "commits" in xpath and use commits_number = int(html.fromstring(r.text).xpath(xpath)[0].strip().replace(',', ''))

– Andersson
Nov 22 '18 at 16:13

Nice! Thanks once again.

– Max
Nov 22 '18 at 16:18

I just ran into it so I share it: Sometimes it happens that a repository has more than 1000 contributors and the number will include a comma again, so the replace() method has to be used again to get rid of it.

– Max
Nov 23 '18 at 10:52

Gives me just what I wanted, thank you.

– Max
Nov 22 '18 at 15:37

Well know I'm wondering how to get the amount of commits. I'm experimenting around but I don't get it.

– Max
Nov 22 '18 at 16:10

@Max , try to replace "contributors" with "commits" in xpath and use commits_number = int(html.fromstring(r.text).xpath(xpath)[0].strip().replace(',', ''))

– Andersson
Nov 22 '18 at 16:13

Nice! Thanks once again.

– Max
Nov 22 '18 at 16:18

I just ran into it so I share it: Sometimes it happens that a repository has more than 1000 contributors and the number will include a comma again, so the replace() method has to be used again to get rid of it.

– Max
Nov 23 '18 at 10:52

|
show 1 more comment

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