Nonhomogeneous Second oder ODE












0












$begingroup$


I've recently started to learn ode, consider this equation $t''+at'-t=f$, where $a$ is not a constant and $f$ is a desired function.



$$y^{2} + ay-1= 0 quadLeftrightarrowquad y_{pm} = - frac{a}{2} pm sqrt{left(frac{a}{2}right)^{!2} +1}, $$



so for simplicity let's call it $y_{+}=A$ and $y_{-}=B $ as fundamental solution.



if I'm not mistaken this is the general solution:



$$t= frac{fA}{-BA'+AB'}-frac{fB}{-BA'+AB'}+C_{1}A+C_{2}B.$$



Now I want to know if this can be an explicit solution or not? And how can I show existence and uniqueness of this solution?










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$endgroup$












  • $begingroup$
    The characteristic polynomial method only works for constant coefficients. (And the rest of the development is also wrong).
    $endgroup$
    – Yves Daoust
    Jan 22 at 16:50










  • $begingroup$
    @YvesDaoust So, what is the right solution for this equation? How can I solve it?
    $endgroup$
    – Angela
    Jan 22 at 17:04










  • $begingroup$
    In the general case, solving such a second order ODE equation is painful. As it is linear, you first solve the homogeneous part. Then you can try variation of constants to obtain a particular solution.
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:21












  • $begingroup$
    @YvesDaoust and what is fundamental solution for homogeneous equation? It's $e^{y_{/pm}}t$
    $endgroup$
    – Angela
    Jan 22 at 17:25












  • $begingroup$
    No. Lookup "second order linear ODE with variable coefficients".
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:53
















0












$begingroup$


I've recently started to learn ode, consider this equation $t''+at'-t=f$, where $a$ is not a constant and $f$ is a desired function.



$$y^{2} + ay-1= 0 quadLeftrightarrowquad y_{pm} = - frac{a}{2} pm sqrt{left(frac{a}{2}right)^{!2} +1}, $$



so for simplicity let's call it $y_{+}=A$ and $y_{-}=B $ as fundamental solution.



if I'm not mistaken this is the general solution:



$$t= frac{fA}{-BA'+AB'}-frac{fB}{-BA'+AB'}+C_{1}A+C_{2}B.$$



Now I want to know if this can be an explicit solution or not? And how can I show existence and uniqueness of this solution?










share|cite|improve this question











$endgroup$












  • $begingroup$
    The characteristic polynomial method only works for constant coefficients. (And the rest of the development is also wrong).
    $endgroup$
    – Yves Daoust
    Jan 22 at 16:50










  • $begingroup$
    @YvesDaoust So, what is the right solution for this equation? How can I solve it?
    $endgroup$
    – Angela
    Jan 22 at 17:04










  • $begingroup$
    In the general case, solving such a second order ODE equation is painful. As it is linear, you first solve the homogeneous part. Then you can try variation of constants to obtain a particular solution.
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:21












  • $begingroup$
    @YvesDaoust and what is fundamental solution for homogeneous equation? It's $e^{y_{/pm}}t$
    $endgroup$
    – Angela
    Jan 22 at 17:25












  • $begingroup$
    No. Lookup "second order linear ODE with variable coefficients".
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:53














0












0








0





$begingroup$


I've recently started to learn ode, consider this equation $t''+at'-t=f$, where $a$ is not a constant and $f$ is a desired function.



$$y^{2} + ay-1= 0 quadLeftrightarrowquad y_{pm} = - frac{a}{2} pm sqrt{left(frac{a}{2}right)^{!2} +1}, $$



so for simplicity let's call it $y_{+}=A$ and $y_{-}=B $ as fundamental solution.



if I'm not mistaken this is the general solution:



$$t= frac{fA}{-BA'+AB'}-frac{fB}{-BA'+AB'}+C_{1}A+C_{2}B.$$



Now I want to know if this can be an explicit solution or not? And how can I show existence and uniqueness of this solution?










share|cite|improve this question











$endgroup$




I've recently started to learn ode, consider this equation $t''+at'-t=f$, where $a$ is not a constant and $f$ is a desired function.



$$y^{2} + ay-1= 0 quadLeftrightarrowquad y_{pm} = - frac{a}{2} pm sqrt{left(frac{a}{2}right)^{!2} +1}, $$



so for simplicity let's call it $y_{+}=A$ and $y_{-}=B $ as fundamental solution.



if I'm not mistaken this is the general solution:



$$t= frac{fA}{-BA'+AB'}-frac{fB}{-BA'+AB'}+C_{1}A+C_{2}B.$$



Now I want to know if this can be an explicit solution or not? And how can I show existence and uniqueness of this solution?







ordinary-differential-equations






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 22 at 15:56









Adrian Keister

5,27371933




5,27371933










asked Jan 22 at 15:49









AngelaAngela

61




61












  • $begingroup$
    The characteristic polynomial method only works for constant coefficients. (And the rest of the development is also wrong).
    $endgroup$
    – Yves Daoust
    Jan 22 at 16:50










  • $begingroup$
    @YvesDaoust So, what is the right solution for this equation? How can I solve it?
    $endgroup$
    – Angela
    Jan 22 at 17:04










  • $begingroup$
    In the general case, solving such a second order ODE equation is painful. As it is linear, you first solve the homogeneous part. Then you can try variation of constants to obtain a particular solution.
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:21












  • $begingroup$
    @YvesDaoust and what is fundamental solution for homogeneous equation? It's $e^{y_{/pm}}t$
    $endgroup$
    – Angela
    Jan 22 at 17:25












  • $begingroup$
    No. Lookup "second order linear ODE with variable coefficients".
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:53


















  • $begingroup$
    The characteristic polynomial method only works for constant coefficients. (And the rest of the development is also wrong).
    $endgroup$
    – Yves Daoust
    Jan 22 at 16:50










  • $begingroup$
    @YvesDaoust So, what is the right solution for this equation? How can I solve it?
    $endgroup$
    – Angela
    Jan 22 at 17:04










  • $begingroup$
    In the general case, solving such a second order ODE equation is painful. As it is linear, you first solve the homogeneous part. Then you can try variation of constants to obtain a particular solution.
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:21












  • $begingroup$
    @YvesDaoust and what is fundamental solution for homogeneous equation? It's $e^{y_{/pm}}t$
    $endgroup$
    – Angela
    Jan 22 at 17:25












  • $begingroup$
    No. Lookup "second order linear ODE with variable coefficients".
    $endgroup$
    – Yves Daoust
    Jan 22 at 17:53
















$begingroup$
The characteristic polynomial method only works for constant coefficients. (And the rest of the development is also wrong).
$endgroup$
– Yves Daoust
Jan 22 at 16:50




$begingroup$
The characteristic polynomial method only works for constant coefficients. (And the rest of the development is also wrong).
$endgroup$
– Yves Daoust
Jan 22 at 16:50












$begingroup$
@YvesDaoust So, what is the right solution for this equation? How can I solve it?
$endgroup$
– Angela
Jan 22 at 17:04




$begingroup$
@YvesDaoust So, what is the right solution for this equation? How can I solve it?
$endgroup$
– Angela
Jan 22 at 17:04












$begingroup$
In the general case, solving such a second order ODE equation is painful. As it is linear, you first solve the homogeneous part. Then you can try variation of constants to obtain a particular solution.
$endgroup$
– Yves Daoust
Jan 22 at 17:21






$begingroup$
In the general case, solving such a second order ODE equation is painful. As it is linear, you first solve the homogeneous part. Then you can try variation of constants to obtain a particular solution.
$endgroup$
– Yves Daoust
Jan 22 at 17:21














$begingroup$
@YvesDaoust and what is fundamental solution for homogeneous equation? It's $e^{y_{/pm}}t$
$endgroup$
– Angela
Jan 22 at 17:25






$begingroup$
@YvesDaoust and what is fundamental solution for homogeneous equation? It's $e^{y_{/pm}}t$
$endgroup$
– Angela
Jan 22 at 17:25














$begingroup$
No. Lookup "second order linear ODE with variable coefficients".
$endgroup$
– Yves Daoust
Jan 22 at 17:53




$begingroup$
No. Lookup "second order linear ODE with variable coefficients".
$endgroup$
– Yves Daoust
Jan 22 at 17:53










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I would try a series solution - there isn't enough information on a, besides it being an arbitrary function.






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    $begingroup$

    I would try a series solution - there isn't enough information on a, besides it being an arbitrary function.






    share|cite|improve this answer









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      $begingroup$

      I would try a series solution - there isn't enough information on a, besides it being an arbitrary function.






      share|cite|improve this answer









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        $begingroup$

        I would try a series solution - there isn't enough information on a, besides it being an arbitrary function.






        share|cite|improve this answer









        $endgroup$



        I would try a series solution - there isn't enough information on a, besides it being an arbitrary function.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 23 at 2:53









        FizzerFizzer

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