I'm writing a C program on visual studio. But my program doesn't run nor it returns any errors. Can someone...

I hopelessly tried to copy paste this into another file but it still doesn't return anything.

#include "stdio.h"

#include "stdlib.h"

#include "string.h"

#include "conio.h"

#pragma warning (disable: 4996)



typedef struct item

{

    char *pName;

    int Quantity, Price, Total;

} ITEM;



ITEM *Exam(char *pInput);



int main()

{

    ITEM *pItem;

    char input[81];

    printf("Type items: ");

    gets_s(input);

    char *pInput = input;

    pItem = Exam(pInput);

    printf("Name: %snQuantity: %dnPrice: %dnTotal: %dn", pItem->pName, pItem->Quantity, pItem->Price, pItem->Total);

    free(pItem);

    return 0;

}



ITEM *Exam(char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    char *pNam, *pQuantity, *pPrice;

    int total, l, q, p;

    int qu, pr;



    for (l = 0; *(pInput + l) != ','; l++);

    pNam = (char *)malloc(l + 1);

    *(pInput + l) = '';

    strcpy(pNam, pInput);

    pItem->pName = pNam;

    *(pInput + l) = ',';



    for (q = 0; *(pInput + l + 2 + q) != ','; q++);

    pQuantity = (char *)malloc(q + 1);

    *(pInput + l + q + 2) = 0;

    strcpy(pQuantity, pInput + l + 2);

    qu = atoi(pQuantity);

    pItem->Quantity = qu;



    for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

    pPrice = (char *)malloc(p + 1);

    *(pInput + l + q + 4) = 0;

    strcpy(pPrice, pInput + l + q + 4);

    pr = atoi(pPrice);

    pItem->Price = pr;

    pItem->Total = pr * qu;

    return pItem;

}

input is 'shirt, 100, 5'. I want the output to be a structure of name, quantity, price and total. It let me type the input but when i press enter it doesn't return anything. The program just hangs...

asked Jan 1 at 16:49

catify

156

1

First of all, why don't you use the standard strtok function? Secondly, I suggest you learn how to debug your programs. Especially how to run inside the debugger and how to catch crashes (which might be what you have).

– Some programmer dude
Jan 1 at 16:52

Where does it hang? (Attach a debugger.)

– Davis Herring
Jan 1 at 16:53

@Davis Herring after i type the input and hit enter. it doesn't do anything. It just stays there

– catify
Jan 1 at 16:54

2

You should edit the question rather than clarify in comments. The question says that it does not run, when it clearly does if it prompts for input. VS has about the best debugger available - consider using it; it will be far faster that posting questions on SO.

– Clifford
Jan 1 at 17:38

1

@catify to use all these offsets complicate a lot your program, it is more simple to have a pointer going through the string, just my 2 cents

– bruno
Jan 1 at 17:45

|
show 10 more comments

I hopelessly tried to copy paste this into another file but it still doesn't return anything.

#include "stdio.h"

#include "stdlib.h"

#include "string.h"

#include "conio.h"

#pragma warning (disable: 4996)



typedef struct item

{

    char *pName;

    int Quantity, Price, Total;

} ITEM;



ITEM *Exam(char *pInput);



int main()

{

    ITEM *pItem;

    char input[81];

    printf("Type items: ");

    gets_s(input);

    char *pInput = input;

    pItem = Exam(pInput);

    printf("Name: %snQuantity: %dnPrice: %dnTotal: %dn", pItem->pName, pItem->Quantity, pItem->Price, pItem->Total);

    free(pItem);

    return 0;

}



ITEM *Exam(char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    char *pNam, *pQuantity, *pPrice;

    int total, l, q, p;

    int qu, pr;



    for (l = 0; *(pInput + l) != ','; l++);

    pNam = (char *)malloc(l + 1);

    *(pInput + l) = '';

    strcpy(pNam, pInput);

    pItem->pName = pNam;

    *(pInput + l) = ',';



    for (q = 0; *(pInput + l + 2 + q) != ','; q++);

    pQuantity = (char *)malloc(q + 1);

    *(pInput + l + q + 2) = 0;

    strcpy(pQuantity, pInput + l + 2);

    qu = atoi(pQuantity);

    pItem->Quantity = qu;



    for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

    pPrice = (char *)malloc(p + 1);

    *(pInput + l + q + 4) = 0;

    strcpy(pPrice, pInput + l + q + 4);

    pr = atoi(pPrice);

    pItem->Price = pr;

    pItem->Total = pr * qu;

    return pItem;

}

input is 'shirt, 100, 5'. I want the output to be a structure of name, quantity, price and total. It let me type the input but when i press enter it doesn't return anything. The program just hangs...

asked Jan 1 at 16:49

catify

156

1

First of all, why don't you use the standard strtok function? Secondly, I suggest you learn how to debug your programs. Especially how to run inside the debugger and how to catch crashes (which might be what you have).

– Some programmer dude
Jan 1 at 16:52

Where does it hang? (Attach a debugger.)

– Davis Herring
Jan 1 at 16:53

@Davis Herring after i type the input and hit enter. it doesn't do anything. It just stays there

– catify
Jan 1 at 16:54

2

You should edit the question rather than clarify in comments. The question says that it does not run, when it clearly does if it prompts for input. VS has about the best debugger available - consider using it; it will be far faster that posting questions on SO.

– Clifford
Jan 1 at 17:38

1

@catify to use all these offsets complicate a lot your program, it is more simple to have a pointer going through the string, just my 2 cents

– bruno
Jan 1 at 17:45

|
show 10 more comments

I hopelessly tried to copy paste this into another file but it still doesn't return anything.

#include "stdio.h"

#include "stdlib.h"

#include "string.h"

#include "conio.h"

#pragma warning (disable: 4996)



typedef struct item

{

    char *pName;

    int Quantity, Price, Total;

} ITEM;



ITEM *Exam(char *pInput);



int main()

{

    ITEM *pItem;

    char input[81];

    printf("Type items: ");

    gets_s(input);

    char *pInput = input;

    pItem = Exam(pInput);

    printf("Name: %snQuantity: %dnPrice: %dnTotal: %dn", pItem->pName, pItem->Quantity, pItem->Price, pItem->Total);

    free(pItem);

    return 0;

}



ITEM *Exam(char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    char *pNam, *pQuantity, *pPrice;

    int total, l, q, p;

    int qu, pr;



    for (l = 0; *(pInput + l) != ','; l++);

    pNam = (char *)malloc(l + 1);

    *(pInput + l) = '';

    strcpy(pNam, pInput);

    pItem->pName = pNam;

    *(pInput + l) = ',';



    for (q = 0; *(pInput + l + 2 + q) != ','; q++);

    pQuantity = (char *)malloc(q + 1);

    *(pInput + l + q + 2) = 0;

    strcpy(pQuantity, pInput + l + 2);

    qu = atoi(pQuantity);

    pItem->Quantity = qu;



    for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

    pPrice = (char *)malloc(p + 1);

    *(pInput + l + q + 4) = 0;

    strcpy(pPrice, pInput + l + q + 4);

    pr = atoi(pPrice);

    pItem->Price = pr;

    pItem->Total = pr * qu;

    return pItem;

}

input is 'shirt, 100, 5'. I want the output to be a structure of name, quantity, price and total. It let me type the input but when i press enter it doesn't return anything. The program just hangs...

asked Jan 1 at 16:49

catify

156

I hopelessly tried to copy paste this into another file but it still doesn't return anything.

#include "stdio.h"

#include "stdlib.h"

#include "string.h"

#include "conio.h"

#pragma warning (disable: 4996)



typedef struct item

{

    char *pName;

    int Quantity, Price, Total;

} ITEM;



ITEM *Exam(char *pInput);



int main()

{

    ITEM *pItem;

    char input[81];

    printf("Type items: ");

    gets_s(input);

    char *pInput = input;

    pItem = Exam(pInput);

    printf("Name: %snQuantity: %dnPrice: %dnTotal: %dn", pItem->pName, pItem->Quantity, pItem->Price, pItem->Total);

    free(pItem);

    return 0;

}



ITEM *Exam(char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    char *pNam, *pQuantity, *pPrice;

    int total, l, q, p;

    int qu, pr;



    for (l = 0; *(pInput + l) != ','; l++);

    pNam = (char *)malloc(l + 1);

    *(pInput + l) = '';

    strcpy(pNam, pInput);

    pItem->pName = pNam;

    *(pInput + l) = ',';



    for (q = 0; *(pInput + l + 2 + q) != ','; q++);

    pQuantity = (char *)malloc(q + 1);

    *(pInput + l + q + 2) = 0;

    strcpy(pQuantity, pInput + l + 2);

    qu = atoi(pQuantity);

    pItem->Quantity = qu;



    for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

    pPrice = (char *)malloc(p + 1);

    *(pInput + l + q + 4) = 0;

    strcpy(pPrice, pInput + l + q + 4);

    pr = atoi(pPrice);

    pItem->Price = pr;

    pItem->Total = pr * qu;

    return pItem;

}

input is 'shirt, 100, 5'. I want the output to be a structure of name, quantity, price and total. It let me type the input but when i press enter it doesn't return anything. The program just hangs...

c visual-studio

asked Jan 1 at 16:49

catify

156

asked Jan 1 at 16:49

catify

156

asked Jan 1 at 16:49

catify

156

asked Jan 1 at 16:49

catify

156

asked Jan 1 at 16:49

catify

156

1

First of all, why don't you use the standard strtok function? Secondly, I suggest you learn how to debug your programs. Especially how to run inside the debugger and how to catch crashes (which might be what you have).

– Some programmer dude
Jan 1 at 16:52

Where does it hang? (Attach a debugger.)

– Davis Herring
Jan 1 at 16:53

@Davis Herring after i type the input and hit enter. it doesn't do anything. It just stays there

– catify
Jan 1 at 16:54

2

You should edit the question rather than clarify in comments. The question says that it does not run, when it clearly does if it prompts for input. VS has about the best debugger available - consider using it; it will be far faster that posting questions on SO.

– Clifford
Jan 1 at 17:38

1

@catify to use all these offsets complicate a lot your program, it is more simple to have a pointer going through the string, just my 2 cents

– bruno
Jan 1 at 17:45

|
show 10 more comments

1

First of all, why don't you use the standard strtok function? Secondly, I suggest you learn how to debug your programs. Especially how to run inside the debugger and how to catch crashes (which might be what you have).

– Some programmer dude
Jan 1 at 16:52

Where does it hang? (Attach a debugger.)

– Davis Herring
Jan 1 at 16:53

@Davis Herring after i type the input and hit enter. it doesn't do anything. It just stays there

– catify
Jan 1 at 16:54

2

You should edit the question rather than clarify in comments. The question says that it does not run, when it clearly does if it prompts for input. VS has about the best debugger available - consider using it; it will be far faster that posting questions on SO.

– Clifford
Jan 1 at 17:38

1

@catify to use all these offsets complicate a lot your program, it is more simple to have a pointer going through the string, just my 2 cents

– bruno
Jan 1 at 17:45

First of all, why don't you use the standard strtok function? Secondly, I suggest you learn how to debug your programs. Especially how to run inside the debugger and how to catch crashes (which might be what you have).

– Some programmer dude
Jan 1 at 16:52

Where does it hang? (Attach a debugger.)

– Davis Herring
Jan 1 at 16:53

@Davis Herring after i type the input and hit enter. it doesn't do anything. It just stays there

– catify
Jan 1 at 16:54

You should edit the question rather than clarify in comments. The question says that it does not run, when it clearly does if it prompts for input. VS has about the best debugger available - consider using it; it will be far faster that posting questions on SO.

– Clifford
Jan 1 at 17:38

@catify to use all these offsets complicate a lot your program, it is more simple to have a pointer going through the string, just my 2 cents

– bruno
Jan 1 at 17:45

|
show 10 more comments

1 Answer
1

active

oldest

votes

The last for in Exam is :

for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

that for never end because its condition is always true

if *(pInput + l + q + 4) values ';' the test is false || true then true

if *(pInput + l + q + 4) values 0 the test is true || false then true

for all the other characters the test is true || true so again true

+ 4 must be + 3 else goes 1 character too far

and p++ has no effect at all on the test

The test can be changed to !(*(pInput + l + q + 3 + p) == ';' || *(pInput + l + q + 3 + p) == 0) to stop when ';' or the null character is reached

Of course after *(pInput + l + q + 4) = 0; must be *(pInput + l + q + 3 + p) = 0;

Note that pQuantity and pPrice are allocated but never freed.

Exam can be simplified, for instance :

ITEM *Exam(const char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    const char *p;



    p = strchr(pInput, ',');

    pItem->pName = strndup(pInput, p - pInput);

    p += 1;



    pItem->Quantity = atoi(p);

    p = strchr(p, ',') + 1;



    pItem->Price = atoi(p);

    pItem->Total = pItem->Price * pItem->Quantity;



    return pItem;

}

Note that the input string is not modified (I moved it const) and there is no dynamic allocation except for the result and the name

if you do not have strndup :

char * strndup(const char * s, int n)

{

    char * r = (char *) malloc(n + 1);



    memcpy(r, s, n);

    r[n] = 0;

    return r;

}

edited Jan 2 at 14:32

answered Jan 1 at 17:10

bruno

10.1k21126

Thank you so much for your time and knowledge sir!

– catify
Jan 2 at 14:21

@catify I added strndup if you don't have it on visual-studio, and I added a missing const in the declaration of p

– bruno
Jan 2 at 14:36

add a comment |

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1 Answer
1

active

oldest

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1 Answer
1

active

oldest

votes

The last for in Exam is :

for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

that for never end because its condition is always true

if *(pInput + l + q + 4) values ';' the test is false || true then true

if *(pInput + l + q + 4) values 0 the test is true || false then true

for all the other characters the test is true || true so again true

+ 4 must be + 3 else goes 1 character too far

and p++ has no effect at all on the test

The test can be changed to !(*(pInput + l + q + 3 + p) == ';' || *(pInput + l + q + 3 + p) == 0) to stop when ';' or the null character is reached

Of course after *(pInput + l + q + 4) = 0; must be *(pInput + l + q + 3 + p) = 0;

Note that pQuantity and pPrice are allocated but never freed.

Exam can be simplified, for instance :

ITEM *Exam(const char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    const char *p;



    p = strchr(pInput, ',');

    pItem->pName = strndup(pInput, p - pInput);

    p += 1;



    pItem->Quantity = atoi(p);

    p = strchr(p, ',') + 1;



    pItem->Price = atoi(p);

    pItem->Total = pItem->Price * pItem->Quantity;



    return pItem;

}

Note that the input string is not modified (I moved it const) and there is no dynamic allocation except for the result and the name

if you do not have strndup :

char * strndup(const char * s, int n)

{

    char * r = (char *) malloc(n + 1);



    memcpy(r, s, n);

    r[n] = 0;

    return r;

}

edited Jan 2 at 14:32

answered Jan 1 at 17:10

bruno

10.1k21126

Thank you so much for your time and knowledge sir!

– catify
Jan 2 at 14:21

@catify I added strndup if you don't have it on visual-studio, and I added a missing const in the declaration of p

– bruno
Jan 2 at 14:36

add a comment |

The last for in Exam is :

for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

that for never end because its condition is always true

if *(pInput + l + q + 4) values ';' the test is false || true then true

if *(pInput + l + q + 4) values 0 the test is true || false then true

for all the other characters the test is true || true so again true

+ 4 must be + 3 else goes 1 character too far

and p++ has no effect at all on the test

The test can be changed to !(*(pInput + l + q + 3 + p) == ';' || *(pInput + l + q + 3 + p) == 0) to stop when ';' or the null character is reached

Of course after *(pInput + l + q + 4) = 0; must be *(pInput + l + q + 3 + p) = 0;

Note that pQuantity and pPrice are allocated but never freed.

Exam can be simplified, for instance :

ITEM *Exam(const char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    const char *p;



    p = strchr(pInput, ',');

    pItem->pName = strndup(pInput, p - pInput);

    p += 1;



    pItem->Quantity = atoi(p);

    p = strchr(p, ',') + 1;



    pItem->Price = atoi(p);

    pItem->Total = pItem->Price * pItem->Quantity;



    return pItem;

}

Note that the input string is not modified (I moved it const) and there is no dynamic allocation except for the result and the name

if you do not have strndup :

char * strndup(const char * s, int n)

{

    char * r = (char *) malloc(n + 1);



    memcpy(r, s, n);

    r[n] = 0;

    return r;

}

edited Jan 2 at 14:32

answered Jan 1 at 17:10

bruno

10.1k21126

Thank you so much for your time and knowledge sir!

– catify
Jan 2 at 14:21

@catify I added strndup if you don't have it on visual-studio, and I added a missing const in the declaration of p

– bruno
Jan 2 at 14:36

add a comment |

The last for in Exam is :

for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

that for never end because its condition is always true

if *(pInput + l + q + 4) values ';' the test is false || true then true

if *(pInput + l + q + 4) values 0 the test is true || false then true

for all the other characters the test is true || true so again true

+ 4 must be + 3 else goes 1 character too far

and p++ has no effect at all on the test

The test can be changed to !(*(pInput + l + q + 3 + p) == ';' || *(pInput + l + q + 3 + p) == 0) to stop when ';' or the null character is reached

Of course after *(pInput + l + q + 4) = 0; must be *(pInput + l + q + 3 + p) = 0;

Note that pQuantity and pPrice are allocated but never freed.

Exam can be simplified, for instance :

ITEM *Exam(const char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    const char *p;



    p = strchr(pInput, ',');

    pItem->pName = strndup(pInput, p - pInput);

    p += 1;



    pItem->Quantity = atoi(p);

    p = strchr(p, ',') + 1;



    pItem->Price = atoi(p);

    pItem->Total = pItem->Price * pItem->Quantity;



    return pItem;

}

Note that the input string is not modified (I moved it const) and there is no dynamic allocation except for the result and the name

if you do not have strndup :

char * strndup(const char * s, int n)

{

    char * r = (char *) malloc(n + 1);



    memcpy(r, s, n);

    r[n] = 0;

    return r;

}

edited Jan 2 at 14:32

answered Jan 1 at 17:10

bruno

10.1k21126

The last for in Exam is :

for (p = 0; *(pInput + l + q + 4) != ';' || *(pInput + l + q + 4) != 0; p++);

that for never end because its condition is always true

if *(pInput + l + q + 4) values ';' the test is false || true then true

if *(pInput + l + q + 4) values 0 the test is true || false then true

for all the other characters the test is true || true so again true

+ 4 must be + 3 else goes 1 character too far

and p++ has no effect at all on the test

The test can be changed to !(*(pInput + l + q + 3 + p) == ';' || *(pInput + l + q + 3 + p) == 0) to stop when ';' or the null character is reached

Of course after *(pInput + l + q + 4) = 0; must be *(pInput + l + q + 3 + p) = 0;

Note that pQuantity and pPrice are allocated but never freed.

Exam can be simplified, for instance :

ITEM *Exam(const char *pInput)

{

    ITEM *pItem = (ITEM *)malloc(sizeof(ITEM));

    const char *p;



    p = strchr(pInput, ',');

    pItem->pName = strndup(pInput, p - pInput);

    p += 1;



    pItem->Quantity = atoi(p);

    p = strchr(p, ',') + 1;



    pItem->Price = atoi(p);

    pItem->Total = pItem->Price * pItem->Quantity;



    return pItem;

}

Note that the input string is not modified (I moved it const) and there is no dynamic allocation except for the result and the name

if you do not have strndup :

char * strndup(const char * s, int n)

{

    char * r = (char *) malloc(n + 1);



    memcpy(r, s, n);

    r[n] = 0;

    return r;

}

edited Jan 2 at 14:32

answered Jan 1 at 17:10

bruno

10.1k21126

edited Jan 2 at 14:32

answered Jan 1 at 17:10

bruno

10.1k21126

answered Jan 1 at 17:10

bruno

10.1k21126

answered Jan 1 at 17:10

bruno

10.1k21126

Thank you so much for your time and knowledge sir!

– catify
Jan 2 at 14:21

@catify I added strndup if you don't have it on visual-studio, and I added a missing const in the declaration of p

– bruno
Jan 2 at 14:36

add a comment |

Thank you so much for your time and knowledge sir!

– catify
Jan 2 at 14:21

@catify I added strndup if you don't have it on visual-studio, and I added a missing const in the declaration of p

– bruno
Jan 2 at 14:36

Thank you so much for your time and knowledge sir!

– catify
Jan 2 at 14:21

@catify I added strndup if you don't have it on visual-studio, and I added a missing const in the declaration of p

– bruno
Jan 2 at 14:36

add a comment |

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