OffsetDateTime toString() return different format date string

I have date in this format yyyy-MM-dd'T'HH:mm:ss'Z', but while i'm parsing this using OffsetDateTime.parse(date); it returns the string by elimination seconds

Logic : Get the day from date, if it is Saturday or Sunday change day to monday and return the date String

String date = "2018-12-30T06:00:00Z";



System.out.println(date);



try {

    OffsetDateTime dateTime = OffsetDateTime.parse(date);



    System.out.println(dateTime);           //2018-12-30T06:00Z



    DayOfWeek day = dateTime.getDayOfWeek();

    // check if price change  date is Sunday or Saturday and change it to Monday

    if (day.equals(DayOfWeek.SATURDAY) || day.equals(DayOfWeek.SUNDAY)) {



        String finalDateTime = dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)).toString();

         System.out.println(finalDateTime);      //2018-12-31T06:00Z

    }else {

        System.out.println(date);

    }

    }catch(Exception ex) {

        System.out.println(ex);

        System.out.println(date);

    }

I need to return string as same input format yyyy-MM-dd'T'HH:mm:ss'Z'

edited Jan 2 at 17:28

asked Jan 2 at 16:55

Deadpool

7,4572829

Why don't you use LocalDateTime?

– Nicholas K
Jan 2 at 16:57

honestly i'm not good at java date time, but i have an offset in String right Z?

– Deadpool
Jan 2 at 16:58

1

Don't use toString(), use DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'").format(dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)))

– ernest_k
Jan 2 at 17:02

That works thank you @ernest_k

– Deadpool
Jan 2 at 17:05

add a comment |

I have date in this format yyyy-MM-dd'T'HH:mm:ss'Z', but while i'm parsing this using OffsetDateTime.parse(date); it returns the string by elimination seconds

Logic : Get the day from date, if it is Saturday or Sunday change day to monday and return the date String

String date = "2018-12-30T06:00:00Z";



System.out.println(date);



try {

    OffsetDateTime dateTime = OffsetDateTime.parse(date);



    System.out.println(dateTime);           //2018-12-30T06:00Z



    DayOfWeek day = dateTime.getDayOfWeek();

    // check if price change  date is Sunday or Saturday and change it to Monday

    if (day.equals(DayOfWeek.SATURDAY) || day.equals(DayOfWeek.SUNDAY)) {



        String finalDateTime = dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)).toString();

         System.out.println(finalDateTime);      //2018-12-31T06:00Z

    }else {

        System.out.println(date);

    }

    }catch(Exception ex) {

        System.out.println(ex);

        System.out.println(date);

    }

I need to return string as same input format yyyy-MM-dd'T'HH:mm:ss'Z'

edited Jan 2 at 17:28

asked Jan 2 at 16:55

Deadpool

7,4572829

Why don't you use LocalDateTime?

– Nicholas K
Jan 2 at 16:57

honestly i'm not good at java date time, but i have an offset in String right Z?

– Deadpool
Jan 2 at 16:58

1

Don't use toString(), use DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'").format(dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)))

– ernest_k
Jan 2 at 17:02

That works thank you @ernest_k

– Deadpool
Jan 2 at 17:05

add a comment |

I have date in this format yyyy-MM-dd'T'HH:mm:ss'Z', but while i'm parsing this using OffsetDateTime.parse(date); it returns the string by elimination seconds

Logic : Get the day from date, if it is Saturday or Sunday change day to monday and return the date String

String date = "2018-12-30T06:00:00Z";



System.out.println(date);



try {

    OffsetDateTime dateTime = OffsetDateTime.parse(date);



    System.out.println(dateTime);           //2018-12-30T06:00Z



    DayOfWeek day = dateTime.getDayOfWeek();

    // check if price change  date is Sunday or Saturday and change it to Monday

    if (day.equals(DayOfWeek.SATURDAY) || day.equals(DayOfWeek.SUNDAY)) {



        String finalDateTime = dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)).toString();

         System.out.println(finalDateTime);      //2018-12-31T06:00Z

    }else {

        System.out.println(date);

    }

    }catch(Exception ex) {

        System.out.println(ex);

        System.out.println(date);

    }

I need to return string as same input format yyyy-MM-dd'T'HH:mm:ss'Z'

edited Jan 2 at 17:28

asked Jan 2 at 16:55

Deadpool

7,4572829

I have date in this format yyyy-MM-dd'T'HH:mm:ss'Z', but while i'm parsing this using OffsetDateTime.parse(date); it returns the string by elimination seconds

Logic : Get the day from date, if it is Saturday or Sunday change day to monday and return the date String

String date = "2018-12-30T06:00:00Z";



System.out.println(date);



try {

    OffsetDateTime dateTime = OffsetDateTime.parse(date);



    System.out.println(dateTime);           //2018-12-30T06:00Z



    DayOfWeek day = dateTime.getDayOfWeek();

    // check if price change  date is Sunday or Saturday and change it to Monday

    if (day.equals(DayOfWeek.SATURDAY) || day.equals(DayOfWeek.SUNDAY)) {



        String finalDateTime = dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)).toString();

         System.out.println(finalDateTime);      //2018-12-31T06:00Z

    }else {

        System.out.println(date);

    }

    }catch(Exception ex) {

        System.out.println(ex);

        System.out.println(date);

    }

I need to return string as same input format yyyy-MM-dd'T'HH:mm:ss'Z'

java java-date

edited Jan 2 at 17:28

asked Jan 2 at 16:55

Deadpool

7,4572829

edited Jan 2 at 17:28

asked Jan 2 at 16:55

Deadpool

7,4572829

edited Jan 2 at 17:28

asked Jan 2 at 16:55

Deadpool

7,4572829

asked Jan 2 at 16:55

Deadpool

7,4572829

asked Jan 2 at 16:55

Deadpool

7,4572829

Why don't you use LocalDateTime?

– Nicholas K
Jan 2 at 16:57

honestly i'm not good at java date time, but i have an offset in String right Z?

– Deadpool
Jan 2 at 16:58

1

Don't use toString(), use DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'").format(dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)))

– ernest_k
Jan 2 at 17:02

That works thank you @ernest_k

– Deadpool
Jan 2 at 17:05

add a comment |

Why don't you use LocalDateTime?

– Nicholas K
Jan 2 at 16:57

honestly i'm not good at java date time, but i have an offset in String right Z?

– Deadpool
Jan 2 at 16:58

1

Don't use toString(), use DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'").format(dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)))

– ernest_k
Jan 2 at 17:02

That works thank you @ernest_k

– Deadpool
Jan 2 at 17:05

Why don't you use LocalDateTime?

– Nicholas K
Jan 2 at 16:57

honestly i'm not good at java date time, but i have an offset in String right Z?

– Deadpool
Jan 2 at 16:58

Don't use toString(), use DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'").format(dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)))

– ernest_k
Jan 2 at 17:02

That works thank you @ernest_k

– Deadpool
Jan 2 at 17:05

add a comment |

1 Answer
1

active

oldest

votes

As per OffsetDateTime.toString() method javadoc the shortest possible format for the value is used while omitted parts are implied to be zero. The shortest possible format for 2018-12-30T06:00:00Z is uuuu-MM-dd'T'HH:mmXXXXX so the seconds and nanos are skipped:

The output will be one of the following ISO-8601 formats:

uuuu-MM-dd'T'HH:mmXXXXX

uuuu-MM-dd'T'HH:mm:ssXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The format used will be the shortest that outputs the full value of the time where the omitted parts are implied to be zero.

If you need a precise format use a DateTimeFormatter instance with specific pattern to output the date:

String date = "2018-12-30T06:00:00Z";

OffsetDateTime dt = OffsetDateTime.parse(date);

DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");

System.out.println(fmt.format(dt));

edited Jan 2 at 17:08

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

add a comment |

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The output will be one of the following ISO-8601 formats:

uuuu-MM-dd'T'HH:mmXXXXX

uuuu-MM-dd'T'HH:mm:ssXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The format used will be the shortest that outputs the full value of the time where the omitted parts are implied to be zero.

If you need a precise format use a DateTimeFormatter instance with specific pattern to output the date:

String date = "2018-12-30T06:00:00Z";

OffsetDateTime dt = OffsetDateTime.parse(date);

DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");

System.out.println(fmt.format(dt));

edited Jan 2 at 17:08

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

add a comment |

The output will be one of the following ISO-8601 formats:

uuuu-MM-dd'T'HH:mmXXXXX

uuuu-MM-dd'T'HH:mm:ssXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The format used will be the shortest that outputs the full value of the time where the omitted parts are implied to be zero.

If you need a precise format use a DateTimeFormatter instance with specific pattern to output the date:

String date = "2018-12-30T06:00:00Z";

OffsetDateTime dt = OffsetDateTime.parse(date);

DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");

System.out.println(fmt.format(dt));

edited Jan 2 at 17:08

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

add a comment |

The output will be one of the following ISO-8601 formats:

uuuu-MM-dd'T'HH:mmXXXXX

uuuu-MM-dd'T'HH:mm:ssXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The format used will be the shortest that outputs the full value of the time where the omitted parts are implied to be zero.

If you need a precise format use a DateTimeFormatter instance with specific pattern to output the date:

String date = "2018-12-30T06:00:00Z";

OffsetDateTime dt = OffsetDateTime.parse(date);

DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");

System.out.println(fmt.format(dt));

edited Jan 2 at 17:08

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

The output will be one of the following ISO-8601 formats:

uuuu-MM-dd'T'HH:mmXXXXX

uuuu-MM-dd'T'HH:mm:ssXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX

uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The format used will be the shortest that outputs the full value of the time where the omitted parts are implied to be zero.

If you need a precise format use a DateTimeFormatter instance with specific pattern to output the date:

String date = "2018-12-30T06:00:00Z";

OffsetDateTime dt = OffsetDateTime.parse(date);

DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");

System.out.println(fmt.format(dt));

edited Jan 2 at 17:08

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

edited Jan 2 at 17:08

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

answered Jan 2 at 17:02

Karol Dowbecki

25.4k93759

add a comment |

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